FE Exam Mechanics Of Materials - Location of Load P

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  • Опубліковано 20 гру 2024

КОМЕНТАРІ • 10

  • @2011jdp
    @2011jdp 4 роки тому

    That problem was more difficult than I expected. For example, if you took your moment in a different location, you have to deal with P, another variable. Another equation you could use is: (sum of Y forces) P=T(al)+T(st)

  • @edwardzheng8162
    @edwardzheng8162 3 роки тому

    PL/AE is for longitudinal deformation, but this is a beam deflection problem and I think you need to utilize the area moment of inertia in this case.

  • @kathleenmil402
    @kathleenmil402 2 місяці тому

    why is Ps plus when it is going the same direction as Pa?

  • @medoghany6882
    @medoghany6882 5 років тому +1

    Thanks for your effort .
    Do you have explained all subjects or there is another subjects?

  • @ShivamPatel-ms9lu
    @ShivamPatel-ms9lu 5 років тому +3

    Could you add the videos to it's respective playlist? It becomes a huge mess searching for a specific topic.

    • @Genieprep
      @Genieprep  5 років тому +1

      Hello Shivam, I actually have a playlist for each subject and I also just updated it yesterday. Thank you for your feedback and thank you for watching!

  • @nanabekoetv1548
    @nanabekoetv1548 5 років тому +1

    Good job

  • @brianwin5183
    @brianwin5183 Рік тому

    Thank you

  • @farhadhaidar4147
    @farhadhaidar4147 2 роки тому

    If we do below easy equation We get the same answer: 10”x29000/(29000+10,000) = 7.43m

  • @doradito33
    @doradito33 4 роки тому

    From (Pa/Ea = Ps/Es) wouldn't you go to Pa = (Ps*Ea)/Es. It just seems like Ps should also be divided by Es. Let me know what you think :)