2285. Maximum Total Importance of Roads || LeetCode POTD || Explained in HINDI

Approach:-
Degree Calculation:
Initialize an array degree to count the number of connections (roads) for each city.
Traverse through the given roads and increment the degree for each connected city.
Sorting:
Sort the degree array to easily assign the highest values to the cities with the most connections.
Importance Calculation:
Initialize a variable val starting from 1 and another variable ans to accumulate the total importance.
Traverse through the sorted degree array and for each city, multiply its degree by val and add it to ans. Increment val after each iteration.
Return Result:
The total accumulated importance ans is returned as the result.
Time and Space Complexity
Time Complexity: O(n log n)
Calculating the degree of each city takes O(m), where m is the number of roads.
Sorting the degree array takes O(n log n), where n is the number of cities.
The final loop to calculate the total importance runs in O(n).
Therefore, the overall time complexity is dominated by the sorting step, which is O(n log n).
Space Complexity: O(n)
The space complexity is primarily due to the degree array, which requires O(n) space to store the degree of each city.
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2285. Maximum Total Importance of Roads
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Code link:- leetcode.com/problems/maximum-total-importance-of-roads/solutions/5381519/java-solution-explained-in-hindi/