Let current in upper source be I1 & current in lower source be I2 I1 + I2 =0 Va - 6 - I1 = Vb Va-Vb = 6 + I1 Also Va-Vb = 3 + 2(I2) Equating Above Equations Va - Vb = 5V
Because, protons are flowing in the name of current. Since protons have positive charge and positive charges are attracted towards negative. The current(protons) flow from positive to negative
sir why did you leave those current sources and 1 ohm resistor .yes u have told it in the previous lectures ,but is it possible to remove those ?????????? pls any one clear my doubt
Your explanation is the best in your UA-cam channel @ Neso academy....
Thank u sir.....
This is one of the best videos I have watched in my entire life, thank you so much.
By Millman’s Theorem,
VA-VB = (6/1 + 3/2)/(1/1 + 1/2) = 7.5/1.5
= 5V
Awosem bro 🎉
Thank you for this video. Now my KVL and KCL concepts are clear!! :)
Sir your voice+your explanation
Awesome combination
total current follwing in he circuit I= -1 amp
Va - 6 -1(-1) = Vb
Vab = +5 volts
@15TUEE038 DINESH KUMAR R. Apply KVL so you will get 6 + 1I + 2I - 3 = 0, solve this I =-1.
@Gowri Varun Devabattula it's your choice to choose the path, anyway you will get the same answer.
@Gowri Varun Devabattula Va - 3 + 2 ( i ) = Vb here i = (-1) amp i.e Va -3 -2 = Vb , Vab= +5 volt (same as mentioned above)
@Gowri Varun Devabattula because of the direction of flow of current, i have assumed while, applying KVL in Inner Loop.
@@anandini5740 current across 1 ohm and current across 2 ohm is not same.. As they are in parallel connection
thank you sir, your pronunciation snd also your explanation is very good
Neso Academy thank you sir.. But please resume signals & systems also
Let current in upper source be I1 & current in lower source be I2
I1 + I2 =0
Va - 6 - I1 = Vb
Va-Vb = 6 + I1
Also
Va-Vb = 3 + 2(I2)
Equating Above Equations
Va - Vb = 5V
How can we equate
Thnk u so much
Otherwise no one else interested to gíven full solution 🙏
@@monikakumarikoli1133 can you please tell how i1+i2=0?
@@puneetchhabra411 kcl law
How I1+ I2 is equals to zero ?
Your voice is confusing me to take the next step but your videos are so helpful
Thanks you so much for your efforts and productive lecture 💕🥰
Once it is mentioned that power is delivered that implies we should take magnitude of power not considering sign.
When will you again continue signals & systems? just curious to know, no offence
when power is delever the formula should be P= -IV. but in these example you took P=IV
Stop mugging formula
Ya that's right but when u said the power is delivered then we don't need to include negative sing.... Hope it will be useful
Thank you sir 😊😊😊
Super sir 😁😁😁😁😁
is this related with super mesh analysis as u r avoiding the current sources ?
sir,,plz kindly upload all the lectures,,,so that one can complete the syllabus in one go...
VA-VB= 5v and current in 1ohm is -1amp. also current in 2 ohm is 1amp.
current through 1 ohm is -1 amp..how do u get current through 2 ohm is 1 amp...plz reply
Current through 2-ohm resistor should be -2A because the total current in the circuit is -1 A and V=IR
Does it mean the direction of current in 1ohm and 2ohm is different?
How
Amazing
Perez Daniel Lopez Eric Martinez Timothy
Sir how your are taking resistor signs
I general resistors don't have any sign the default sign is +
E=e1/r1+e2/r2+e3/r3......./1/r1+1/r2.....
God will bless u
Sir if we have voltage source then votlage across all elements in circuit same or differ?
no it will differ..if all elements are placed in series...and if all elements are in parallel then the voltage is same in all elements
Vab= 5v
my answer for I is 1.5 and it makes more sense
By source transformation answer is 5 volts
any can explain more i didnt get 5
🔥🔥🔥🔥
Ans 5volt , using Va-Vb=6-3+2I
Where I is 2A
So Va-Vb=6-3+2
=5volt
Best one 😂
how did u find i
Jarred Points
doing kvl rule for this circuit is better 👍
first we find out value of I in closed path by applying KVL ie I=-2AMP .. then Va-Vb =5 volt
-6-i-2i+3=0, i=-1, Va-Vb=5v
For given homework problem
Use source transformation then both branches will get 6V
Voltage across AB is 5V
How ??
Gabriella Inlet
My answer Va-Vb = 5V
Ans is 5v
My ans is 5 volt...😁😁😁🤗🤗🤗...
Tq so much sir
Hlo
+5v
Source transformation
IN 2010 ka nhi EC 2010 ka h .nice lecture sir
Wilkinson Brook
Winifred Circle
Bartell Court
Answer is 5
Please can you explain 🙏
Sir please upload the lectures about soft computing
If the voltage source is not of 10V, there would have been a power flow
Flo Springs
sir why did u take the flow of electric current from positive to negative
Because, protons are flowing in the name of current. Since protons have positive charge and positive charges are attracted towards negative. The current(protons) flow from positive to negative
sir why did you leave those current sources and 1 ohm resistor .yes u have told it in the previous lectures ,but is it possible to remove those ?????????? pls any one clear my doubt
He just applied kvl to outer loop.
@@kedar2239 thanks bro now i understood .
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-3V?
Answer is, 15V
How. Please type
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Do 0w exists in real life
5 volts
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V =3
Answer is 5 volts
-Va+6-1+Vb=0
Vab+5=0
Vab=-5V
shashi uppuloori how did you do that
Va-Vb=5V
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The words of the lecture are typed on the circuit that makes the understanding very difficult.
You can turn it off.
10 v - 10 A can we sub it sir?
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3V
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Hall Ronald Gonzalez Jeffrey Walker Melissa
Anyone please send homework proper solution.
5volt
Please caption kr diya kare
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Which website sir is talking about ??
Vab =5 volts
VA -VB =5
3v
Doyle Spurs
Vab = 5V
Hi
@@sathiyaseelanm905 hi !
H r u?
@@sathiyaseelanm905 Fine.
Who are you?
@@GV_Stories my name sathiya seelan i am live in tamilnadu
Va-vb=9
5volts
5v
5 volt
5 V