Electrode Potentials | Electrochemical Series | A level Chemistry | Exam Question Walkthrough

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  • Опубліковано 8 кві 2023
  • Electrode Potentials and Electrochemical series.
    Physical Chemistry.
    A level Chemistry
    Question download:
    drive.google.com/file/d/14-J3...

КОМЕНТАРІ • 34

  • @peachtea532
    @peachtea532 Рік тому +3

    I had just done these questions and hour before this was uploaded ahaha ,, the explanations were really helpful, thank you!

  • @Mendeleev-hh8po
    @Mendeleev-hh8po Рік тому +4

    Thanks for this. One of my hardest topics!

  • @Masowe.
    @Masowe. Рік тому +2

    Thank you sir, you give me hope about this topic and the subject overall. Thank you

    • @chemistrytutor
      @chemistrytutor  Рік тому +1

      Very kind of you to say so. Keep going at it!

    • @Masowe.
      @Masowe. Рік тому +1

      @@chemistrytutor thank you

  • @hiranixa7494
    @hiranixa7494 4 місяці тому +3

    I don't understand part 9a. Both electrode potentials of iodine and water is more positive than lithium's. So won't lithium react the same way with iodine?

    • @chemistrytutor
      @chemistrytutor  4 місяці тому +2

      That's true, but you were not asked to consider the bottom half equation. You were only asked why water wasn't used as the electrolyte. The job of the electrolyte is to complete the circuit and maintain charge balance. It should do this by allowing the ions dissolved in it to move and cancel the effect of charges that have been generated/used. If the electrolyte reacts, it will get used up and won't be able to perform the job it needs to.

    • @hiranixa7494
      @hiranixa7494 4 місяці тому +1

      ​@@chemistrytutor Oh okay, thank you!

  • @dno.16
    @dno.16 Рік тому +2

    for question 8d- did you add the two iron half equations?( so you used 3 half equations?) and how did you know that the final product would be fe3+ hexaquaion and not the fe2+ one?

    • @chemistrytutor
      @chemistrytutor  Рік тому +1

      You could do it that way, but if you know the starting chemical and the final chemical you can devise your own half equation, which is what I did.
      I knew which iron product it would be because the vanadium electrode Potential is large enough that it can oxidise the iron from 0 to + 2
      And then from +2 to plus 3 (a total of 3 e lost)
      I knew this because vanadium's electrode potential is larger than the value for both iron half Equations

    • @dno.16
      @dno.16 Рік тому +1

      @@chemistrytutor thank you!

    • @chemistrytutor
      @chemistrytutor  Рік тому

      @@dno.16 😀👍

    • @Charlotte-hf5jz
      @Charlotte-hf5jz 5 місяців тому +1

      @@chemistrytutori don’t understand this? how can i combine the two fe half equations?

    • @chemistrytutor
      @chemistrytutor  5 місяців тому

      @Charlotte-hf5jz how do you mean? Which question? 8d? In a way you don't need to combine them... you need to know iron starts as Fe 0 and then turns into Fe3+. Then balance that with 3 e- on the right

  • @kavishkumar9
    @kavishkumar9 Рік тому +1

    Really good video. Thanks sir

  • @thikkaperera2644
    @thikkaperera2644 Рік тому +2

    very educative can ya do one for inorganic too (mcq)

    • @chemistrytutor
      @chemistrytutor  Рік тому

      I've done some periodicity MCQs.
      Here is a full links document:
      drive.google.com/file/d/19yYWdu3bczjCyeSC-NFp6_V781IRwcvU/view?usp=drivesdk

  • @BANCAIES-bz7vj
    @BANCAIES-bz7vj Рік тому +1

    Underrateddddd

  • @noveawalters4339
    @noveawalters4339 Рік тому +1

    I’m confused on question 8d. If VO2+ goes to VO^2+ doesn’t that mean that it’s being oxidised and not reduced as it goes from a +1 to +2 charge

    • @chemistrytutor
      @chemistrytutor  Рік тому +1

      It's actually going from +5 to +4
      V -2 -2 = +1 so V is +5 at first
      V -2 = +2 so V is +4

    • @noveawalters4339
      @noveawalters4339 Рік тому

      @@chemistrytutor But isn’t +5 to + 4 still oxidation and not reduction as the charge has got more positive meaning a loss of electron and therefore oxidation?

    • @chemistrytutor
      @chemistrytutor  Рік тому

      @@noveawalters4339 if somethings charge gets less positive it must have gained a negative election... reduction

    • @noveawalters4339
      @noveawalters4339 Рік тому +1

      @@chemistrytutor oh yes, that makes sense! Sorry redox isn’t my best topic so I get easily confused. Thank you!!

    • @chemistrytutor
      @chemistrytutor  Рік тому

      @@noveawalters4339 no problem at all.
      I've made a video about redox if that's useful?
      ua-cam.com/video/bjtO_PEgd64/v-deo.html

  • @MK-sh7ol
    @MK-sh7ol 5 місяців тому +1

    I don’t understand why you picked the fourth one down rather than the first one (the iron equation).

    • @chemistrytutor
      @chemistrytutor  5 місяців тому

      I'm presuming you mean part (e)
      Since the substance the [Co(H2O)6]3+ is on the left hand side of its half equation (its an oxidising agent) then the Fe(H2O)6]2+ *has* to be on the right hand side of its half equation (and be acting as a reducing agent). If they were both on the same side they'd both be wanting to gain electrons

    • @safaakbari
      @safaakbari 4 місяці тому

      It’s because the reaction can further occur to break the product of the Fe2+ complex down into the other Fe3+ complex (both reactions go left ways) so you can combine them together as long as you balance the electrons, hope that helps!

    • @chemistrytutor
      @chemistrytutor  4 місяці тому

      If you meant 8d... I chose both the 1st and the 4th.
      The Fe in the first equation is oxidised to Fe2+. This is then a reactant in the 4th equation and can be oxidised further to Fe3+.
      So both oxidation occur and ultimately Fe loses 3 electrons to form Fe3+

  • @syyahahhs6353
    @syyahahhs6353 3 місяці тому +1

    can you do six mark questions please

    • @chemistrytutor
      @chemistrytutor  3 місяці тому +1

      A variety of exam questions are in my plans!