Ans of last question are- No of no defective blade - 9802 No of one defective - 196 No of two defective - approx 2 Please check it out sir if it is correct or not 🙏🏻
Sir Poisson distribution ka formula book meh dusra dia hua hai or aap kuch or formula btaye hai book e pe power -mew hai lekin aap e to the power -i btaye hai Please explain sir 4:35
The answers of the last question are Number of packets:- i) no defective blade= 0.9802 ii) one defective blade= 0.019604 iii) two defective blades = 1.96041*10 to the power -4
sir , is ' >> ' a valid logic for poisson distb..?? cause no. of trials to hamesa bada hi lagega w.r.t p(success), Qki wo to always 0-1 ke bich hi rahegaa na!!! to matlab kab hum ye decide krenge ki ye ques Binomial se solve hoga ...like jab P(success) ....60-90% ko touch kre or something ????????
Sir csbs walo se apka hi naam roshan hoga , bahut panic situation create ho skti hai....but ap control kardo probab achche se imp sab kuch padha karrr jald se jald sirrrr .😶😶😶
Ans of last question are- No of no defective blade - 9802
No of one defective - 196
No of two defective - approx 2
Please check it out sir if it is correct or not 🙏🏻
Sir please upload next video.
Sit you help all makaut students ❤
Sir Poisson distribution ka formula book meh dusra dia hua hai or aap kuch or formula btaye hai book e pe power -mew hai lekin aap e to the power -i btaye hai
Please explain sir 4:35
wo sir suru me galat bataye the par uske bad sara question sahi hi banaye hai
Thank you ankush... Please do me a favour.. mention the timestamp and write the issue properly and I'll pin the comment.
That I have rectified later... Don't worry 🤗
Suru mein thoda sa typing mistake ho Gaya tha 🙂
0.07 First slide sir@@TendingtoInfinity
@@TendingtoInfinity 2:45 me sir
last question ans
if X=0, P(X=0)=0.9802
P(X=1)=0.019604
P(X=2)=0.00039208
The answers of the last question are
Number of packets:-
i) no defective blade= 0.9802
ii) one defective blade= 0.019604
iii) two defective blades = 1.96041*10 to the power -4
bro thats for pack of 10, multiply each by 10000 to get the final ans of each probability
@@adityakumarshaw1598 yup thanks buddy
Sir please bivariate distribution krwa do
sir , is ' >> ' a valid logic for poisson distb..?? cause no. of trials to hamesa bada hi lagega w.r.t p(success), Qki wo to always 0-1 ke bich hi rahegaa na!!! to matlab kab hum ye decide krenge ki ye ques Binomial se solve hoga ...like jab P(success) ....60-90% ko touch kre or something ????????
Yes that is a valid symbol..
Sir sampling and it's distribution chapter ta koriye din na
sir last question me u=np ka formula lageka....(n=10000,p=1/50=0.02). mujhe to yhi lag rha hai. Agar mai galat hu toh bata dijiye pls.🙏
Sir csbs walo se apka hi naam roshan hoga , bahut panic situation create ho skti hai....but ap control kardo probab achche se imp sab kuch padha karrr jald se jald sirrrr .😶😶😶
The answers of the last question are
Number of packets i) no defective blade 9802
ii) one defective blade 196
iii) two defective blades 4
Sir please bring practice live session 🙏 sem 2 maths
Sir probability 13 Tarik k pehle complete ho jayega kya?
Same Mera bhi 13 ko math hain
Sir bsm202 er video ki ar asbe na ai sem er jonno...
Sir apka personal ph number hota to bohot helpful hota humare liye❤........
I wish I could!