Use the circumradius formula for triangles. Circumradius = side/divided by 2sine of opposite angle. CB is 10 cm in length. / 2sine of angle CAB ( 53.13) degrees , is 1.599 = circumradius works out to 6.2539. Using area of circle formula. Area is: 122.8720
10=2*5 ; (12/2)=6=2*3 ---> h=2*4=8 ---> Potencia del punto medio de AB respecto a la circunferencia =6*6=8a---> a=9/2---> Radio =r=[8+(9/2)]/2 =25/4---> Área del círculo=πr² =625π/16 =122,71846...ud². Gracias y saludos.
cos(x)=(10^2+10^2-12^2)/2(10)(10) So cos(x)=7/25 Cos(2x)=(R^2+R^2-144)/2R^2 Cos(2x)=(R^2-72)/R^2 2cos^2(x)-1=(R^2-72)/R^2 So R=25/4 So area of the circle=π(25/4)^2=625π/16=122.72.❤❤❤
Thanks sir yours teaching is so sompel so good
Uwc sir!
Use the circumradius formula for triangles. Circumradius = side/divided by 2sine of opposite angle. CB is 10 cm in length. / 2sine of angle CAB ( 53.13) degrees , is 1.599 = circumradius works out to 6.2539. Using area of circle formula. Area is: 122.8720
Nice one 👍
10=2*5 ; (12/2)=6=2*3 ---> h=2*4=8 ---> Potencia del punto medio de AB respecto a la circunferencia =6*6=8a---> a=9/2---> Radio =r=[8+(9/2)]/2 =25/4---> Área del círculo=πr² =625π/16 =122,71846...ud².
Gracias y saludos.
Nice one 👍
cos(x)=(10^2+10^2-12^2)/2(10)(10)
So cos(x)=7/25
Cos(2x)=(R^2+R^2-144)/2R^2
Cos(2x)=(R^2-72)/R^2
2cos^2(x)-1=(R^2-72)/R^2
So R=25/4
So area of the circle=π(25/4)^2=625π/16=122.72.❤❤❤
Nice one 👍👍👍
Easy
Yea