thank you so much sir for doing all these videos for us, i really appreciate it ! please ignore all those haters, they're really ungrateful. there are many more people supporting you !
thank you so much sir! I tried the paper first on my own and then I relied to your video to the questions I got wrong or couldn't understand. RESPECT❤🔥
Great content Sir.🤩 Sir i would like to make a gentle request if you could do for June 2023 a level for both physics, chemistry and biology? This would really help us out. Loads of thanks😊
53:55 in drawing C) how do we know where to put the methyl group, there is no number indicating it? As it can be placed on the first, second or third carbon. So isn't what you drew for C called 1-iodo-2-methylpropane?
For propane, you dont HAVE to number the methyl group, because it is only a methyl group if it is placed on the 2nd carbon. On the 1st and 3rd carbons, its just a part of the main chain, and the molecule becomes butane. So whenever you see methylpropane, it is automatically assumed that its going to be 2-methlypropane. This applies ONLY to propane, not to any other molecule type. Hope that makes sense.
U say there is H bonding only if OH group is there as it forms H bond and is it is in a wide range there will be a broad peak from 3200 to 3650 for H bonds
Sir in question 24 why are u multiplying 0.025 mol into 24000?? 35:18 Anyways thanks for all these videos really helps me and I’m sure everyone else a lot
For the people who say you shouldn't copy the mark scheme, do they expect you to explain the wrong answers then? And say that the wrong answers are correct?! 🤨
@@CAIEPapersSolved curiosity is getting the best of me but if you don’t mind me asking how much do you manage to earn from UA-cam? The efforts put into making these is definitely sky high, hope you earn as much as you deserve!
thank you so much sir for doing all these videos for us, i really appreciate it ! please ignore all those haters, they're really ungrateful. there are many more people supporting you !
Hate comment to kisis nay kia hi nai
You're always a life saver for the students who sincerely prepare but do a bit late for exams!❤❤
This is literally saving my As-level grades 😭😭
you have no idea how helpful these are ✨
I'm so glad!
Thanks!! These videos are getting me through my AS exam prep!
These videos really help me out. Thank you very much!!!
thank you so much sir! I tried the paper first on my own and then I relied to your video to the questions I got wrong or couldn't understand. RESPECT❤🔥
Excellent! All the best ❤️❤️
Great content Sir.🤩
Sir i would like to make a gentle request if you could do for June 2023 a level for both physics, chemistry and biology?
This would really help us out.
Loads of thanks😊
As soon as possible! Processing
Soo helpful, thank you 🙏🏼
Glad it was helpful!
Binge watching your videos tomorrow's my exam
Good luck!!
Thank You Sir really helpful ❤
Great content as always keep it up
Appreciate it! :)
Ppl like you are doing god's work. Tysm. ❤
You’re welcome! ❤️
Here to help you guys
love your videos tbh, they helped me alott
Hi, can i know the Graphic tablet your using ...Thanks
Thank you for your help 👌
No problem 👍
TQ Sir!!!
for question 28, i thought alkenes also undergo oxidation??
49:09 Why will the double bonds not oxidise in question # 28?
The double bind is oxidised by kmno4 not k2cro7 which is being used
53:55 in drawing C) how do we know where to put the methyl group, there is no number indicating it? As it can be placed on the first, second or third carbon. So isn't what you drew for C called 1-iodo-2-methylpropane?
For propane, you dont HAVE to number the methyl group, because it is only a methyl group if it is placed on the 2nd carbon. On the 1st and 3rd carbons, its just a part of the main chain, and the molecule becomes butane. So whenever you see methylpropane, it is automatically assumed that its going to be 2-methlypropane. This applies ONLY to propane, not to any other molecule type. Hope that makes sense.
@@pratikharani Many thanks. Also, amazing explanation.
45:18 the 2^2=4 that you’ve written does it work for all number of chirals for example i had 5 chiral carbons total isomers would be 25?
Hi Sir, great video, could you further explain why there is no hydrogen bonding in question 38?
U say there is H bonding only if OH group is there as it forms H bond and is it is in a wide range there will be a broad peak from 3200 to 3650 for H bonds
Hope you got it
Sir in question 24 why are u multiplying 0.025 mol into 24000?? 35:18
Anyways thanks for all these videos really helps me and I’m sure everyone else a lot
because we need to convert it into cm3 because of the options. the formula n=v/24 is when v is in dm3
Really like you videos. I am curious, are you from Bangladesh??
Yes I am!
How can I pull this paper in one night????????
Thank u so much sir
Sir if you mind me asking but which country are you from ?
Bangladesh
@@CAIEPapersSolvedWow I am also from Bangladesh. But ur accent sounds like Malaysian lol
thank you daddy
For the people who say you shouldn't copy the mark scheme, do they expect you to explain the wrong answers then? And say that the wrong answers are correct?! 🤨
I know, right xD
51:06 Can somebody further explain this to me?
Wait bro, I am also from Bangladesh, but how old are u???
Currently 24!
@@CAIEPapersSolvedno way!!!!!! Woahhhh!!!!! Respect for you for being so intelligent at such a young age 🥳🎉🔥
Nice
Didnt understand Q29 and Q27 💔
crazy amount of ads
Need that ad rev 🫡
Gotta respect the grind 🫡 💀
@@CAIEPapersSolved curiosity is getting the best of me but if you don’t mind me asking how much do you manage to earn from UA-cam? The efforts put into making these is definitely sky high, hope you earn as much as you deserve!
@@aadityasrivastava6887first up, don’t ask that from him bud. Let him earn in peace. Secondly is your exam on the 4th?
SO MANY ADS how am i suppose to focus if a lame ad pops up ina middle of a question
Bruh let him have his revenue through that bud
bruv he needs to make money otherwise he can't make more videos if there's no ads