IQIS Lecture 6.8 - Simon's algorithm

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  • Опубліковано 25 бер 2021

КОМЕНТАРІ • 13

  • @akeelmedina7559
    @akeelmedina7559 2 роки тому +2

    love this series! very helpful and clearly explained

  • @arkadijorlov
    @arkadijorlov Рік тому

    Absolutely fantastic lecture series. Pure masterclass!

  • @zhengtongyan8451
    @zhengtongyan8451 2 роки тому

    very clear about the steps of Simon's algorithm, thanks!

  • @keesret
    @keesret 2 роки тому +1

    Very useful and clear, thanks!

  • @yutong9127
    @yutong9127 27 днів тому

    thanks!!!

  • @nilamonidaloi3713
    @nilamonidaloi3713 Рік тому +1

    The step at 11:58 where (-1)^(a.y) is factored out seems confusing as ``(a XOR s). y" is not equal to ``(a.y XOR s.y)" also ``s.y = s1*y1 + s2*y2 + s3*y3 ..... sn*yn", therefore its not guarenteed to be either 0 or 1 it can be 2 or 3 also, e.g., if s = (011) and y = (111) then, s.y = 2.

    • @fatemehrezaie8431
      @fatemehrezaie8431 3 місяці тому

      1. Constant factors is just a phase and is not important for calculating probability amplitudes.
      2. The inner product is modulo 2, so the result is 0 or 1.

  • @eriknelson2559
    @eriknelson2559 Рік тому

    What if "Wave Function Collapse" involves an annihilation + creation interaction with the Quantum Vacuum? The portion of the original "foreground" wave-function which collapses away is annihilated with "background" virtual (partial, off-mass-shell) anti-particles. The new portion of the "foreground" wave-function which regenerates into existence similarly arises from "background" virtual (partial, off-mass-shell) particles.
    If so, and if you could affect the background population of virtual particles & anti-particles -- as with, say, some Casimir plates or something along those lines -- then you could affect wave-function collapse and (perhaps) skew probabilities in your favor.
    Quantum Casinos can stack quantum decks in their favor?

  • @viktorkarpilov4181
    @viktorkarpilov4181 2 роки тому +2

    why do we can't just put 0 in black box ? 0 + s = s

    • @gubunki
      @gubunki Рік тому

      i was going to ask the same

    • @laaori
      @laaori Рік тому +1

      @@gubunki We can, it's just a trivial case that we do not care about.

    • @fatemehrezaie8431
      @fatemehrezaie8431 3 місяці тому

      You mean in classical solution? How do you want to find s from f(0)=f(s)? It is impossible.