It is arbitrary how many field lines we draw to represent the field. The field lines don't really exist, and are simply a tool for visualizing the vector field. We draw them with a density that is proportional to the field strength, which means the "number of lines" works as an introductory explanation for what flux is. You need vector calculus to give a more complete explanation for electric flux, but this gives the general idea. It is the accumulation of the amount of the field across a given surface area.
The charge density is total charge inside a closed surface surrounding the charge divided by the surface area of the closed surface. For this problem, there is no charge perpendicular to the circular side wall, so the only charge emitted is through the ends of the cylinder. But because of symmetry, you can just calculate it for one end. So the charge density for the cylinder is the charge inside divided by the area of one end.
We can draw infinite field line from a point charge.Then how electric flux tells about no.of field line?Could you explain sir
I am not really sure what you are asking, however, perhaps I answer the question in this video:
www.flippingphysics.com/gauss-law-point-charge.html
It is arbitrary how many field lines we draw to represent the field. The field lines don't really exist, and are simply a tool for visualizing the vector field. We draw them with a density that is proportional to the field strength, which means the "number of lines" works as an introductory explanation for what flux is. You need vector calculus to give a more complete explanation for electric flux, but this gives the general idea. It is the accumulation of the amount of the field across a given surface area.
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Could someone explain the Q/A = Q_in/A_end part, I dont really get that.
The charge density is total charge inside a closed surface surrounding the charge divided by the surface area of the closed surface. For this problem, there is no charge perpendicular to the circular side wall, so the only charge emitted is through the ends of the cylinder. But because of symmetry, you can just calculate it for one end. So the charge density for the cylinder is the charge inside divided by the area of one end.