Dimensional Analysis in Detail | Physics

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  • Опубліковано 18 гру 2024

КОМЕНТАРІ • 33

  • @PhysicsTutoringHub
    @PhysicsTutoringHub  11 місяців тому +4

    If you want a quicker overview of Dimensional Analysis, I have a 5 minute video here 👉 ua-cam.com/video/-4G0Ib1JVQw/v-deo.html
    📄 And Practise Exam Questions 👉 ua-cam.com/video/FOIE7ja96-M/v-deo.html

  • @aslanglimpse-
    @aslanglimpse- Рік тому +6

    Thank so much sir it is definitely beautiful explanation

    • @PhysicsTutoringHub
      @PhysicsTutoringHub  Рік тому

      That's really kind of you Aslan. I'm glad it has helped you ☺

  • @norawallberg1345
    @norawallberg1345 3 місяці тому +2

    Hello, what a fantastic video. Thank you very much. If I may ask a question, in 18:41 you say first that r1 + r2 is equal to a length, and afterwards you say that the sum of r1 and r2 won't equal a length. I am confused, could you plesase explain? Thank you.

    • @PhysicsTutoringHub
      @PhysicsTutoringHub  3 місяці тому +1

      Hello Nora. I'm really glad the video is helping 😊. I had a quick look back at the part you mentioned. I don't think I said that the sum of r1 and r2 is not a length, but I did say when you multiply two lengths together you'd get an area. So at 18:55 I say that the height itself is a length, but when you square a length, you're effectively multiplying it by itself -- it becomes an area. At 19:35 I say that when we square the sum (r1- r2) it turns into an area, because we are multiplying two lengths together -- (r1-r2)^2 = (r1-r2)*(r1-r2) = L * L = A
      I hope this clears things up.

    • @norawallberg1345
      @norawallberg1345 3 місяці тому

      Hello. Thank you. Yes, the video is helping a lot. I did not understand much of my lecture but I was able to understand your video. 🙏
      Maybe my hearing is wrong, because it still seems to me that from 18:43 you say "...and we can see this, because the sum of r1 and r2 won't result in a length."
      Anyways, thank you.

    • @PhysicsTutoringHub
      @PhysicsTutoringHub  3 місяці тому

      @@norawallberg1345 That's okay 😊. I just listened back to this and I did say "will" but my pronunciation of it was a bit off (I don't know why this is, I am a native English speaker 😄). The subtitles do say "won't" which is wrong. So, long story short, I will try and say "will" more clearly next time 😊.
      I'm really glad the video is helping as well. I always found lectures to be hard to understand. All this physics stuff takes time to fully absorb and understand. So, please keep going with it and don't be afraid to ask more questions in the future and I'll do my best to answer them. Take care.

    • @norawallberg1345
      @norawallberg1345 3 місяці тому

      @@PhysicsTutoringHubI understand! That explains it.
      Thank you for the inspiring words, I will keep them in mind. Just started studying physics at university. Take care. 😊

    • @PhysicsTutoringHub
      @PhysicsTutoringHub  3 місяці тому

      @@norawallberg1345 That's brilliant. I wish you the best of luck at uni 😊

  • @alhamdulilah6892
    @alhamdulilah6892 Рік тому +1

    Thanks man, very well explained 💯

  • @naren5312
    @naren5312 5 місяців тому

    Hi sir at 15:48 when we square both sides we would end up with t^2 = R^2 ( h/g)

    • @PhysicsTutoringHub
      @PhysicsTutoringHub  5 місяців тому +1

      Hi Naren yes you're right, I made a mistake there.The point I was trying to make here, though, was that this dimensional analysis was able to help us come up with one of the equations of kinematics. The constant at this point is an unknown value which we can only obtain through experimental data or geometric reasoning. So, K here is really just a placeholder for an unknown non-dimensional value.
      Hope this helps.

  • @CollinsUc
    @CollinsUc 3 дні тому

    I have a question at 12: 49 why did you put square root

  • @ahmedbendada1378
    @ahmedbendada1378 2 місяці тому +1

    You are amazing ❤

  • @adityanshuraj2963
    @adityanshuraj2963 7 місяців тому +1

    Sir, let there be a physical quantity X raised to the power of another physical quantity Y. In this case my teacher taught me that Y being a number is dimensionless quantity which i aggre with but also he said X is dimensionless for which he doesn't has any explanation...Plz sole my doubt . Is he right?

  • @God_ourmaker353
    @God_ourmaker353 2 місяці тому

    Hello im middle school student, so i might be wrong but the first question there is a "(r1-r2)^2 and it gives an area how does that work? 😕

    • @PhysicsTutoringHub
      @PhysicsTutoringHub  2 місяці тому

      Hi 😊 That's a good question. So, with this equation, it's best if we break it down into parts rather than trying to understand the whole eqn in one go.
      r1 and r2 represent lengths. If r1 = 10 ft and r2 = 2 ft, then (r1 - r2) = 10ft - 2ft = 8ft
      You can see here that our answer for (r1 - r2) = 8ft has dimensions of length (8ft is a measurement along a 1 dimensional line).
      But, (r1 - r2) has been squared using the ^2 symbol, this means that we are multiplying a length by a length -> (r1 - r2)*(r1 - r2) = 8ft * 8ft = 64ft^2 (64 feet squared)
      When we multiply two lengths together we get an area.
      If you look at your bedroom wall, for example, the height of the wall will be around 8ft tall. It's width along the bottom might also be 8ft, which means the total surface area is 8*8 = 64ft^2. This comes in useful if you need to calculate how much paint you'd need to cover your entire wall.
      Don't worry if you don't understand right away, this video is meant for students aged 16 and above, so you're doing really well getting this far. 😊

  • @OvayoInam024
    @OvayoInam024 8 місяців тому

    sorry sir ,if i may ask ,how did we drop r and p from being endices whilst our bases are not the same?

    • @PhysicsTutoringHub
      @PhysicsTutoringHub  8 місяців тому +1

      @10:18 we isolated the bases on both sides of the equation. On the left hand side we have L^0 and on the right hand side we have L^p * L^r. When we multiply indices (exponents) with the same base, the indices add together. So, we get:
      L^0 = L^(p+r)
      Because we can treat the base L like an algebraic quantity, we can cancel the L on both sides of the eqn, leaving us with:
      0 = p + r

  • @heytherehi7674
    @heytherehi7674 Рік тому

    Thank you so muchhh

  • @lost_cloud_0_
    @lost_cloud_0_ 6 місяців тому +1

    Thank you soo much for this, this really helped allloooooottttttt ❤❤❤❤
    You just gained a new subscriber (゚▽^*)☆

    • @PhysicsTutoringHub
      @PhysicsTutoringHub  6 місяців тому +1

      I'm really glad it has helped 😁- Brilliant. Take care.

  • @SyethembaMyeni
    @SyethembaMyeni 10 місяців тому

    The video is helpful thank you but i need more assistance, can i email you ?

    • @PhysicsTutoringHub
      @PhysicsTutoringHub  10 місяців тому +1

      I'm not providing a one-on-one tuition service at the moment. But, you can post questions here in the comments and I'll try and answer them as best as I can.

    • @SyethembaMyeni
      @SyethembaMyeni 10 місяців тому

      V^2 = Vo + 2b( X - Xo). Here , they want me to find the dimensions of b
      V^n=ka^iX here, they want me to find number n and I would be to make equation dimensional correct

    • @PhysicsTutoringHub
      @PhysicsTutoringHub  10 місяців тому +2

      If this is a homework question, I can't just give you the answer, But, to answer these questions you need to make sure what these variables represent: V and Vo are velocities, X and Xo are distances. and this equation above is a 1D kinematics eqn. and the Vo should be raised to power of 2 --
      V^2 = Vo^2 + 2b( X - Xo). You need to convert these variables into dimension of Length or Time (i.e. Velocity is L/T) and there must be the same dimensions on both side of the equal sign. You're asked to find b, so rearrange the eqn to make b the subject and convert all the known variables into their corresponding dimensions. Remember these dimansions can also be manipulated like normal algebraic expressions. Goodluck with your homework 😁 @@SyethembaMyeni

    • @SyethembaMyeni
      @SyethembaMyeni 10 місяців тому

      @@PhysicsTutoringHub thank you sir I really appreciate it. But it wasn't a homework I just came across with it when I was studying. Thanks a lot

    • @SyethembaMyeni
      @SyethembaMyeni 10 місяців тому

      Sir I think it would be a good idea if you can open a live class where we will be able to ask questions based on that topic