Limits - Free Formula Sheet: bit.ly/3T3dD2X Final Exams and Video Playlists: www.video-tutor.net/ Math and Science Tutors: bit.ly/Find-a-Tutor Next Video: ua-cam.com/video/fHzmQmcvheI/v-deo.html
Your explanations are simply the best. I appreciate so much that you don't take shortcuts and aren't afraid to review the fundamentals during the examples. I wish I could pay you for my Calculus class instead of my university.
This man just proves how bad, some university teachers are, they are paid a bunch of money but can't teach shit. This man makes it so simple to understand. Thanks for this channel
you are really really really helping me in physics and also calculus, man you are really better than all the professors in my university you are a great teacher i am really rely on you man thank you soooooo much
This was helpful as always, yet it is still challenging to me a little bit because there's no consistency in the procedures so that we can use the same approach to every rational function.
G 191 11:38 note 5:25 any time the function is bottom heavy with infinity limits the functions is equal to zero note 5:25 any time degree is equal the ans is coefficient ratio
THANK YOU SO MUCH YOU DESERVE ALL THE MONEY IN THE WORLD!!! MY CALC 1 PROFESSOR TOOK 2 HOURS AND 30 MINUTES TO EXPLAIN THIS BUT I LEARNED WAY MORE FROM YOU IN THE SPAN OF 10 MINUTES!!! THANK YOU!!
i wish you could have been my lecturer at university, i would have understand it on the spot without wasting my time sitting there for 3 hours and don't understand anything, thank you for posting these videos, it's been really helpful
The best thing about this guy is how short his videos are I spent days and days studying with zero results…in less than twenty minutes it all makes sense
At 11:35, since x goes to infinity, I think that we have to consider both case: (1) x goes to positive infinity and (2) x goes to negative infinity. In case (1), the answer is 2 (positive 2), but in case (2) the answer is -2 (negative 2) . In this problem, the method divide both numerator and denominator by 1/x is not a good choice. Instead, divide both numerator and denominator by 1/abs(x) (abs(x): absolute value of x) would be more generally correct. In case (1), 1/abs(x) equals 1/x (positive 1/x) and in case (2), 1/abs(x) = 1/-x (negative 1/x).
I haven’t finished the video but I’ve been studying other calc sections for my quiz tomorrow and you just apply the power rule to top and bottom and you get the answer, so all constants = 0, for the constants that have a variable you multiply it by 1 and divide and get the answer. hopefully this helps someone in the future!
One short cut rule you didn't seem to cover was when the x value is greater in the numerator (ex: 3x^4-10/6x^2+20) the limit will be +/- infinity since the top is outgrowing the bottom.
Mate I love your videos, I've been writing out the theory understanding as best I can and as soon as I hit a road block your the man I come to, and everything I've learnt makes fence
I am here before every test, this time I am here before my final. Somehow just from watching these videos for like 2 days, I manage to always ace my tests, even though I slacked off the entire semester. LOL
Thank you very much at least you have given me directions and I would like you to give us as more examples as possible for me to be in a good position..
Dude I fucking love you man thank you so much for making videos I know you get these kinds of comments on all your video but they help so much I just watched a 10 minute video from a University professor who basically explained nothing then to come here and learn everything in 2 minutes is crazy
16:14 Why did he multiply the radical in the denominator by 1/x^2, but the rest of the denominator by 1/x? I'm guessing it's because in the end, you're taking the limits individually, but I don't get the rule
"Inside a radicle, we need to multiply by 1/x^2" is what he says. Because the 1/x is going under the radicle, its supposed to turn into 1/x^2. Hope this helps!
ok im a year late but it turns out to be 9 because to be able to multiply √(9x^2) by (1/x) to cancel out the highest exponent, you need to get into the radical. So what he did without explaining was he converted (1/x) into (1/√x^2) bc they're the same, so √(9x^2)/(1/x) = √(9x^2)/√(1/x^2) which makes it √9. -bored college student
Can you.please show these carrying the proper Lim notation through the whole problem? Even with the "work" shown, it skips steps or notation which we need to show on every step.
quick question, for the problem w (square root of 9x^2+x) - 3x, why couldnt we plug in infinity right away? x^2 is the biggest term, so wouldn't it determine the behavior of the limit and cause it to tend towards infinity?
@@BNETTERS we always multiply by the reciprocal of the highest powered x in the denominator The highest power in that denominator was 1 which is x so it’s reciprocal is 1/x We do that to reach the formula 1/x^r which is equal 0
Limits - Free Formula Sheet: bit.ly/3T3dD2X
Final Exams and Video Playlists: www.video-tutor.net/
Math and Science Tutors: bit.ly/Find-a-Tutor
Next Video: ua-cam.com/video/fHzmQmcvheI/v-deo.html
Can someone please explain why at 10:13 he multiplied both top and bottom by 1/x instead of 1/x²
@The Organic Chemistry Tutor
Tnx ❤️
Your explanations are simply the best. I appreciate so much that you don't take shortcuts and aren't afraid to review the fundamentals during the examples. I wish I could pay you for my Calculus class instead of my university.
AGREED
i wasted my 3 hrs listening to my calculus teacher without learning it. and now, i learned it instant for only 20 min. wow. thanks
x2 the speed and learn it in 10 min
My calculus teacher dint even teach how to find the limit of infinity
@@alikhidzam3749 you serious? That should be one of the first things you learn in calc 1
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You’re a life saver man I love your videos, you explain better than my college professor lol
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This man just proves how bad, some university teachers are, they are paid a bunch of money but can't teach shit. This man makes it so simple to understand. Thanks for this channel
I actually dont know how many extra hours I would spend on calc without your videos. Thanks so much. Youre a god.
In 20 mins i have learned more than I ever did from my prof's lectures.
MR. Organic Chemistry Tutor, thank you for an excellent explanation of Limits at Infinity and Horizontal Asymptote in Calculus One/Two.
you are really really really helping me in physics and also calculus, man you are really better than all the professors in my university you are a great teacher i am really rely on you man thank you soooooo much
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This was helpful as always, yet it is still challenging to me a little bit because there's no consistency in the procedures so that we can use the same approach to every rational function.
I understand Math with you better than my prof. Your voice helps me
ditto, like same
G 191 11:38
note 5:25 any time the function is bottom heavy with infinity limits the functions is equal to zero
note 5:25 any time degree is equal the ans is coefficient ratio
THANK YOU SO MUCH YOU DESERVE ALL THE MONEY IN THE WORLD!!! MY CALC 1 PROFESSOR TOOK 2 HOURS AND 30 MINUTES TO EXPLAIN THIS BUT I LEARNED WAY MORE FROM YOU IN THE SPAN OF 10 MINUTES!!! THANK YOU!!
i wish you could have been my lecturer at university, i would have understand it on the spot without wasting my time sitting there for 3 hours and don't understand anything, thank you for posting these videos, it's been really helpful
The best thing about this guy is how short his videos are I spent days and days studying with zero results…in less than twenty minutes it all makes sense
u have the most positive effect on this humanity only god knows how to reward u..... class of 2023 appreciates u 🙏🙏🙏
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Thanks
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"The exponent doubles once you move it inside" 19: 21 I bet many of you are confused but hopefully this one sentence help just like it helped me lol
thank youuuu I was confused on that
bruh i was hella confused about this before i saw this video
At 11:35, since x goes to infinity, I think that we have to consider both case: (1) x goes to positive infinity and (2) x goes to negative infinity. In case (1), the answer is 2 (positive 2), but in case (2) the answer is -2 (negative 2) . In this problem, the method divide both numerator and denominator by 1/x is not a good choice. Instead, divide both numerator and denominator by 1/abs(x) (abs(x): absolute value of x) would be more generally correct. In case (1), 1/abs(x) equals 1/x (positive 1/x) and in case (2), 1/abs(x) = 1/-x (negative 1/x).
thank you so much, you're saving my calculus grade and i'm actually learning and understanding what to do
I haven’t finished the video but I’ve been studying other calc sections for my quiz tomorrow and you just apply the power rule to top and bottom and you get the answer, so all constants = 0, for the constants that have a variable you multiply it by 1 and divide and get the answer. hopefully this helps someone in the future!
Notice that he never asks you to subscribe😂😂😂. Legendary
Coz he knows you'll be watching his videos when exams arrive 😂😂😂
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i have my test tommorow and you saved my life, thanks
One short cut rule you didn't seem to cover was when the x value is greater in the numerator (ex: 3x^4-10/6x^2+20) the limit will be +/- infinity since the top is outgrowing the bottom.
Mate I love your videos, I've been writing out the theory understanding as best I can and as soon as I hit a road block your the man I come to, and everything I've learnt makes fence
every time when i fell hopeless for math, you came out
You are a best of all the tutors I came across 🤝💯👍
watched your vids for my igcse revision. I'm in college now and I still watch your vids to understand better. Thank you!
You made limits so so so so so so so so soooooo much easier. Thank you. For realsies.
I am here before every test, this time I am here before my final. Somehow just from watching these videos for like 2 days, I manage to always ace my tests, even though I slacked off the entire semester. LOL
Thanks a lot 😊😊... Your videos help me a lot in my college 👌👌
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The x doubles inside the sqr rt! Omg thank goodness I was so confused thanks!!!!
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Your explanation are really clear and understandable. Your videos are really helping me
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first calc test tomorrow and I think you'll be the reason I pass :) thank you
The answer at 9:20 really helped me out. Thanks a lot!
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well articulated and i could go on and work out on the rest of the questions on my own.
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Thank you so much Mr Julius Gonzalex
This is the insanely interesting actually.
Thank you very much at least you have given me directions and I would like you to give us as more examples as possible for me to be in a good position..
This was so unbelievably helpful thank you
Your videos really are a big help to me. Thank You!
At 11:35 the answer should be -2 because when x enters inside the square root it becomes x^2 and you have to multiply the limit by a negative sign.
What you are saying is true when x -> - infinity, not when x -> infinity
Best maths teacher
Thanks a lot for all the help
Ur video's are the best 💯 thank you for helping me 🙏
may i ask on the second to the last problem, why do we need to multiply
1/x on both sides?
Dude I fucking love you man thank you so much for making videos I know you get these kinds of comments on all your video but they help so much I just watched a 10 minute video from a University professor who basically explained nothing then to come here and learn everything in 2 minutes is crazy
16:14 Why did he multiply the radical in the denominator by 1/x^2, but the rest of the denominator by 1/x? I'm guessing it's because in the end, you're taking the limits individually, but I don't get the rule
"Inside a radicle, we need to multiply by 1/x^2" is what he says.
Because the 1/x is going under the radicle, its supposed to turn into
1/x^2.
Hope this helps!
Because √(x²) = x for x ≥ 0
thank you ,learned a lot in this video and you are a huge help
The best freaking video on UA-cam
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THANK U, some other vid just showed dthe tricks on how to figure it out but didn't explain y, thanks man
I don t have any test . But it looks more fun than boring algebra i study in school. That s why i am learning this for fun
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this is so much easier I honestly wish they taught us in precalc
So ur learning calculus in precalculus makes no sense
this tutorial
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My savior, year to year
Thank your so much ,I really struggling to this
at 16:06 shouldntthe 9 be multiplied by 1/x^2 instead of 1/x because x^2/x is still x???? im confused pls help
ok im a year late but it turns out to be 9 because to be able to multiply √(9x^2) by (1/x) to cancel out the highest exponent, you need to get into the radical. So what he did without explaining was he converted (1/x) into (1/√x^2) bc they're the same, so √(9x^2)/(1/x) = √(9x^2)/√(1/x^2) which makes it √9. -bored college student
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my sir took x^m as common and divide so we have up to x^3 so we can write it as a(1/X^1or 2 or 3)=a(0)=0
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why do we have to multiply the fraction by 1/x😢
to make sure that the x become a denominator with a value of 0
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Sir please solve the question.
Evaluate lim n tends to infinite x to the power n divided by e to the power x
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Can you.please show these carrying the proper Lim notation through the whole problem? Even with the "work" shown, it skips steps or notation which we need to show on every step.
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Test in 45 mins 🗿
Thank you for the video 😊🎉
quick question, for the problem w (square root of 9x^2+x) - 3x, why couldnt we plug in infinity right away? x^2 is the biggest term, so wouldn't it determine the behavior of the limit and cause it to tend towards infinity?
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In the beginning around 4:10 do you know why he divided the top and bottom by 1/x?
@@BNETTERS we always multiply by the reciprocal of the highest powered x in the denominator
The highest power in that denominator was 1 which is x so it’s reciprocal is 1/x
We do that to reach the formula 1/x^r which is equal 0
You are very very good
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