Limits at Infinity & Horizontal Asymptotes
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- Опубліковано 20 лют 2018
- This calculus video tutorial explains how to evaluate limits at infinity and how it relates to the horizontal asymptote of a function. Examples include rational functions, radical functions, inverse trigonometric functions and exponential functions. This video contains plenty of practice problems on evaluating limits at infinity analytically with radicals, square roots, and trig functions.
Introduction to Limits:
• Calculus 1 - Introduct...
How To Evaluate Limits From a Graph:
• How To Evaluate Limits...
Evaluating Limits By Factoring:
• Evaluating Limits By F...
Limits of Rational Functions :
• Limits of Rational Fun...
Limits of Radical Functions:
• How To Evaluate Limits...
Limits of Trigonometric Functions:
• Limits of Trigonometri...
___________________________________
How To Find The Limit at Infinity:
• How To Find The Limit ...
Infinite Limits + Vertical Asymptotes:
• Infinite Limits and Ve...
Limits at Infinity With Radicals:
• Limits at Infinity Wit...
Limits of Absolute Value Functions:
• Limits and Absolute Value
Limits of Composite Functions:
• How To Find The Limit ...
The Squeeze Theorem:
• Squeeze Theorem
____________________________________
Limits and Logarithms:
• Limits and Logarithms
Limits of Exponential Functions:
• Limits of Exponential ...
Piecewise Functions - Limits:
• Piecewise Functions - ...
3 Step Continuity Test:
• 3 Step Continuity Test...
Continuity and Differentiability:
• Continuity and Differe...
Limits - Test Review:
• One Sided Limits, Grap...
_____________________________________
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Can someone please explain why at 10:13 he multiplied both top and bottom by 1/x instead of 1/x²
@The Organic Chemistry Tutor
Tnx ❤️
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Your explanations are simply the best. I appreciate so much that you don't take shortcuts and aren't afraid to review the fundamentals during the examples. I wish I could pay you for my Calculus class instead of my university.
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i wasted my 3 hrs listening to my calculus teacher without learning it. and now, i learned it instant for only 20 min. wow. thanks
x2 the speed and learn it in 10 min
My calculus teacher dint even teach how to find the limit of infinity
@@alikhidzam3749 you serious? That should be one of the first things you learn in calc 1
You’re a life saver man I love your videos, you explain better than my college professor lol
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MR. Organic Chemistry Tutor, thank you for an excellent explanation of Limits at Infinity and Horizontal Asymptote in Calculus One/Two.
In 20 mins i have learned more than I ever did from my prof's lectures.
I actually dont know how many extra hours I would spend on calc without your videos. Thanks so much. Youre a god.
This man just proves how bad, some university teachers are, they are paid a bunch of money but can't teach shit. This man makes it so simple to understand. Thanks for this channel
This was helpful as always, yet it is still challenging to me a little bit because there's no consistency in the procedures so that we can use the same approach to every rational function.
My prof is a German teacher with the heaviest accent ever, I also don’t really understand her method, but this one man explains in one clear shot 💯
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watched your vids for my igcse revision. I'm in college now and I still watch your vids to understand better. Thank you!
At 11:35, since x goes to infinity, I think that we have to consider both case: (1) x goes to positive infinity and (2) x goes to negative infinity. In case (1), the answer is 2 (positive 2), but in case (2) the answer is -2 (negative 2) . In this problem, the method divide both numerator and denominator by 1/x is not a good choice. Instead, divide both numerator and denominator by 1/abs(x) (abs(x): absolute value of x) would be more generally correct. In case (1), 1/abs(x) equals 1/x (positive 1/x) and in case (2), 1/abs(x) = 1/-x (negative 1/x).
why do we have to multiply the fraction by 1/x😢
you are really really really helping me in physics and also calculus, man you are really better than all the professors in my university you are a great teacher i am really rely on you man thank you soooooo much
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Thanks
G 191 11:38
note 5:25 any time the function is bottom heavy with infinity limits the functions is equal to zero
note 5:25 any time degree is equal the ans is coefficient ratio
Thank you so much, the wide range of examples really helped me out!
well articulated and i could go on and work out on the rest of the questions on my own.
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"The exponent doubles once you move it inside" 19: 21 I bet many of you are confused but hopefully this one sentence help just like it helped me lol
thank youuuu I was confused on that
bruh i was hella confused about this before i saw this video
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thank you ,learned a lot in this video and you are a huge help
Your explanation are really clear and understandable. Your videos are really helping me
may i ask on the second to the last problem, why do we need to multiply
1/x on both sides?
Best maths teacher
Thanks a lot for all the help
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quick question, for the problem w (square root of 9x^2+x) - 3x, why couldnt we plug in infinity right away? x^2 is the biggest term, so wouldn't it determine the behavior of the limit and cause it to tend towards infinity?
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The answer at 9:20 really helped me out. Thanks a lot!
THANK U, some other vid just showed dthe tricks on how to figure it out but didn't explain y, thanks man
16:14 Why did he multiply the radical in the denominator by 1/x^2, but the rest of the denominator by 1/x? I'm guessing it's because in the end, you're taking the limits individually, but I don't get the rule
"Inside a radicle, we need to multiply by 1/x^2" is what he says.
Because the 1/x is going under the radicle, its supposed to turn into
1/x^2.
Hope this helps!
Kudos to this guy u really save me in my online class frustration
This was so unbelievably helpful thank you
this tutorial
is really helpful to me
One short cut rule you didn't seem to cover was when the x value is greater in the numerator (ex: 3x^4-10/6x^2+20) the limit will be +/- infinity since the top is outgrowing the bottom.
Amazing video! Cheers!!
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Thank your so much ,I really struggling to this
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Thank you for uploading this video! It was such a big help.
at 16:06 shouldntthe 9 be multiplied by 1/x^2 instead of 1/x because x^2/x is still x???? im confused pls help
ok im a year late but it turns out to be 9 because to be able to multiply √(9x^2) by (1/x) to cancel out the highest exponent, you need to get into the radical. So what he did without explaining was he converted (1/x) into (1/√x^2) bc they're the same, so √(9x^2)/(1/x) = √(9x^2)/√(1/x^2) which makes it √9. -bored college student
The best freaking video on UA-cam
I haven’t finished the video but I’ve been studying other calc sections for my quiz tomorrow and you just apply the power rule to top and bottom and you get the answer, so all constants = 0, for the constants that have a variable you multiply it by 1 and divide and get the answer. hopefully this helps someone in the future!
Honestly, Thank you so much!
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King 👑 of maths,, gifted mind
Great video, very helpfull
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Can you.please show these carrying the proper Lim notation through the whole problem? Even with the "work" shown, it skips steps or notation which we need to show on every step.
can i know how to solve the question at @14.35 if the limit is at negative infinity
wish i could write and listen as fast as you man
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great video!
thank you so much sir
hey at 12:56 why did the square root of 1/x^6 (9x^6 - x^2) turn into square root (9 + ....) which is addition now? where did the addition sign come from??
Same question right here too😂😅
Why go to school when we have UA-cam
Sir please solve the question.
Evaluate lim n tends to infinite x to the power n divided by e to the power x
Thank You so much Sir
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what would be a genral equation to write for the definition of vertical and horizontal asymptotes using limits.
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Thanks my techer
Thank you so much
At 11:35 the answer should be -2 because when x enters inside the square root it becomes x^2 and you have to multiply the limit by a negative sign.
What you are saying is true when x -> - infinity, not when x -> infinity
My savior, year to year
Thank you man
In 11:51 why are we multiplying by 1/x³ instead of 1/x since this question is bottom heavy?
Does anyone know?
@ 12:54 why did the sign change from - to +?
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do u have limit at infinity with table of values??
Thank you
I don t have any test . But it looks more fun than boring algebra i study in school. That s why i am learning this for fun
When you multiplied 1/x with √9x^2 +, is it not suppose to be √9x+
Thank you sir🤩
Can I request a video that shows the behavior of the graph of the limits of infinite and infinity. Please :
hi, what is the answer if infinity of a limit of n^2/2^n?
Sir Thank you Very Muchhh