THANKYOUUUUU SO MUCHHHH!! I've been struggling with this because I need someone to like explain every step by step and guess what?? YOU JUST DID IT. Thankyouuuu
You da man! ------ Struggled for eternity on understanding this from my professors and teachers. Learned it here in a little more than 8 minutes. One like for this vid.
When i enter 1440 divided by 58 i get the answer 24.82758621. When you do it you don't seem to get he decimal point after 24. Also the later calculation you get the correct amount of zeros before the numbers start whilst on my CASIO fx-85GT calculator i get 3.358550105x10-8. I know what 10-8 means i just wondered if you could tell me how i get my calculator to give the answers in the same form as you get?
Isn't it easier to use the 0.693/k = (half-life), solve for K and then use the first-order rate law ln(At/Ao)= --kt ? Substituting k in Ao = initial amount and At = amount remaining. I used these for each problem and got the same answers. Maybe it's just me, but this way seems much faster and easier to solve. Anyone else prefer this method?
+TheOomen2012 I understand and hope I didn't offend. I was just taught a different way and wanted to offer it up in case anyone else was struggling like me. I find that seeing alternatives sometimes helps me learn better. Thank you
Got a question saying " The activity of a sample falls to 0.60 of its original value after 100s. Find the decay constant." What formula should i use? How would you answer that?
I don't even care tht he was a bit cocky anymore I understood here out of all the other 10+ videos I watched thanks nate! *oh and yea exam in an hour!!!
Hi ChemistNATE and everyone, Could you please help me with this following question Radioactive materials are considered to be relatively safe when their activity has fallen below 0.1% of their initial value. (a) How much half-lives does this take? (Answer = 10 half-lives) (b) Plutonium-239 is a by product of nuclear reactors. Its half-life is 24 000 years. How long does the plutonium-239 have to be stored as nuclear waste before it is considered safe to handle? (Answer - 240 000 years)
you could just use the solve function in the calculator to find the t in the second problem. I assume your 10 canadian bucks calculator will have solve function as where i live in, almost every calculator do have the solve function if you know where to find it
I love when i go online and find a tutor thats high as fuck and teachs like a boss.
Lmaoo
Fr
did this man sneeze because bless this man for helping me.
I know your 6 years late but bro its 2020 cant make those jokes nomo
😂😂😂
Bars
that happened ?! 😂
Funny
Your explanations are great because you don't mention what the equations mean, you actually label them. Complete boss.
... and just like that, in 3 minutes, you did better than pages and hours of my chemistry book and lecture. Thank you!!!!
Finals tomorrow anyone?
Yup
even 2 years after
@@zayedalkulaib9678 Finals today lol
even 3 years later
yeah
Very enthusiastic.
Enjoyable.
Concise.
I learned.
Nice Madotsuki pfp
man I so wish you were my lecture. you just make things seem so easy and understandable.
dat intro
Been through tons of vids and this one finally helped me without all the other complicated stuff good work lol
I love watching 11 year old tutorials that still work and teach me chem simple
someone still watching in 2024 👀 same
Your the man, You explain better than a million teachers with their videos
Thank you so much. Why can't my teacher just say this?
Because teachers also have nice degrees, and they want to feel good about their fancy degrees.
Because they don't truly understand the concept well enough to simplify it.
***** highly agree!
I watched several videos on this topic and this is by far the most clear and concise explanation I was given! Thank you so much for making this video!
So glad I can go online and find a great explanation from 11 years ago
THANKYOUUUUU SO MUCHHHH!! I've been struggling with this because I need someone to like explain every step by step and guess what?? YOU JUST DID IT. Thankyouuuu
rise and shine mr freeman
This guy is a legend
your still saving lives 10 years later
"Dont be a fool!" lol
This man just single-handedly saved me for my chemistry test today
I love how you point to the words and numbers. Great video. Very helpful
Finished AP chem exam, still goes back to chemistnate for precalc help
After watching numerous videos, I was still lost! This is The Best and easiest way to calculate Half life problems!!! I finally got it, thank you!!
This man just saved my semester, I appreciate you
God bless you Nate, had a test in 4 hours, and didn't know how to solve for exponents.
Taught me half life calcs before my mid year exam, legend!!
it's like the textbooks make it hard on purpose or something
This is the best video on the topic. It uses the best formula and shows how to solve for the exponent with logs. Thank you so much.
This video helped me sooo much and I really like the way you teach definitely subscribing!
Maaaannn thank you so much i was finding easy way to teach my students and here i met you. Excited to go to class now. Thanks alot.
you are the greatest teacher i have ever seen. Im not even exaggerating.
you're killing me XD "yo just guess..I'm a math wiz fyi"
Please help. For the first problem. How come that
(.5^24.82758621=0.0000336?)
This guy is really goofy, but I like that, makes things interesting
The real antidote of radioactivity calculation. Thanks alot sir.
Even just the formula has saved my life, especially with the teacher never teaching this and proceeding to put it on the quiz :))))))))))))
Wow did not expect the last part.
Thank you so much for the formula, really appreciate that and I liked and shared it too. Only 8 days left for IGCSE physics exam,soooo.
this saved my life 🙏🏻 chem test cram
chemistNATE, thank you so so much! I figured this out now, my teacher doesn't teach properly, but you solved my problem. Thanks again!
0.51...the idrc had me
3.33...use BODMAS, don't be fOOl
5.36...im also a math whiz fyi
It's 2024, best teacher ever 😂
He's so excited its so cute
your videos are better than any others
THANK YOU SO MUCH!!!! My teacher just handed these problems to us when we were leaving class!! Gotta Love Honors Chem.....(Sarcasm)
Thank you so much. I just watched this and am amazed about how my physics test is going to be made easier. May God bless you for me.
Truly a one of a kind wizard, thank you wise stranger...
thank you for the video. for these 7 minutes I understood more then from 3 weeks of lectures!!!
You da man!
------
Struggled for eternity on understanding this from my professors and teachers.
Learned it here in a little more than 8 minutes.
One like for this vid.
This guy teaches so much better than my actual school teacher
This man just single handedly saved my semester.😭🔥
thank u sir i learnt a lot
Many many manyyyyyyyyyyyyyyy Thanks Sir... a lesson forgotten for so many years... thanks for making it easy for me...
Its been 10 YEARS woh!
When i enter 1440 divided by 58 i get the answer 24.82758621. When you do it you don't seem to get he decimal point after 24. Also the later calculation you get the correct amount of zeros before the numbers start whilst on my CASIO fx-85GT calculator i get 3.358550105x10-8. I know what 10-8 means i just wondered if you could tell me how i get my calculator to give the answers in the same form as you get?
Mine is doing that too
Thank you so much. You're a fricking legend.
I love this guys attitude
Without this Math Wizz..
I'm totally insane..xD
Thanks^^
I love you you may have inspired me to get back into some math after a lot of bad teachers
damn ! my physics teacher couldnt explain this to his class in two weeks, and u did it in 7 mins ! thanks!
thank you very much...you have made me a master in solving half life problems.
You the best teacher 👑
Your way of explaining is so amazing and simple. Thank you
yo chemisNate, thanks a lot for the problem 2 you showed. I was looking for it in the internet. gladly found it in your vid. thanks
AWESOME DUDE. I have a prelim exam tomorrow and I had no idea how to do it until now.
This is the best teacher ever!!!
chemistNATE absolute baller
Takes one to know one
Thanks for giving a easy way to check out half life 😊😊
I have an exam tomorrow and this video from so long ago helped😍
Isn't it easier to use the 0.693/k = (half-life), solve for K and then use the first-order rate law ln(At/Ao)= --kt ? Substituting k in Ao = initial amount and At = amount remaining. I used these for each problem and got the same answers. Maybe it's just me, but this way seems much faster and easier to solve. Anyone else prefer this method?
+Rachel Manno.I wud but i didn't really get what you said, can you do video on that?
+Rachel Manno All roads lead to rome, I prefer using logarithm just because I use it allot but I guess your method also works well.
+TheOomen2012 I understand and hope I didn't offend. I was just taught a different way and wanted to offer it up in case anyone else was struggling like me. I find that seeing alternatives sometimes helps me learn better. Thank you
@@rae7305 Sorry Rae.. His way is soooo much easier especially for those whom are a little weaker in the Math Department
Wow, corny and bland jokes. But, literally the best explanation of half-life calculation I have seen... Great job Nate...
Thank you god! i understood a 2 hr lecture in7.4 minutes!! thanks!
John Malovich is teaching me halflife calculations!
"use bedmas DONT BE A FOOL!!!"
hhaahahah made me laff (im sad)
Cheer Up! It's chemistry!
I am entering the same numbers etc into my calculator and i am coming up with different answers to you?
There is also A=Ao x e^( - decay constant x t )
I love you, thanks for telling us to work it backwards!!! Greetings from Houston, Texas..
Got a question saying " The activity of a sample falls to 0.60 of its original value after 100s. Find the decay constant." What formula should i use? How would you answer that?
Thank you my guy for explaining. It truly helps a lot!
how do you calculate how much time for a reaction to occur using half-life?
Thank you so much sir, I felt lost earlier but this really helped me
whos ready for finals this week?
stg, this dude is gonna be getting me through my bioengineering degree
THANKS ALOT!
QUESTION- does this work for all half life calculations? including second order reaction half-life?
Thank you so much! This formula is the best!
as for "don't be a fool.." and "I don't care" :v :v :v I enjoyed this tutorial
can you reverse calculate the half life if given that 20 % of a substance decays after a year?
okat this was very helpful but what if i have how much is left and im trying to calculate how long it has been
I don't even care tht he was a bit cocky anymore
I understood here out of all the other 10+ videos I watched
thanks nate!
*oh and yea exam in an hour!!!
THANK YOU SOOOO MUCH! BEST VIDEO I HAVE Found ONLINE!!!! YOU SAVED MY LIFE❤️❤️
You made this very easy to comprehend. Thank you!
would it be a log or ln? Ive seen others use a ln and not a log
+Leigh Anne Fish log and natural log are basically the same log uses base of 10 and ln uses base of e but same answer
ok, how was these hallife tables calculated for the substances?
I didn't know canon made calculators
you are so funny and your video is really helpful, your video just helped me with the doubts that i have .
Hi ChemistNATE and everyone,
Could you please help me with this following question
Radioactive materials are considered to be relatively safe when their activity has fallen below 0.1% of their initial value.
(a) How much half-lives does this take? (Answer = 10 half-lives)
(b) Plutonium-239 is a by product of nuclear reactors. Its half-life is 24 000 years. How long does the plutonium-239 have to be stored as nuclear waste before it is considered safe to handle? (Answer - 240 000 years)
Bruh I have a science exam tomorrow and this is the only thing I don’t know
you could just use the solve function in the calculator to find the t in the second problem. I assume your 10 canadian bucks calculator will have solve function as where i live in, almost every calculator do have the solve function if you know where to find it
Thank you, thank you, thank you for your clear and straight to the point explanations!
how do you solve for the half life?
how do i solve for the number of half lives that have occurred... in other words, how to i solve for "h" in the equation given in the video?