THANKYOUUUUU SO MUCHHHH!! I've been struggling with this because I need someone to like explain every step by step and guess what?? YOU JUST DID IT. Thankyouuuu
You da man! ------ Struggled for eternity on understanding this from my professors and teachers. Learned it here in a little more than 8 minutes. One like for this vid.
Isn't it easier to use the 0.693/k = (half-life), solve for K and then use the first-order rate law ln(At/Ao)= --kt ? Substituting k in Ao = initial amount and At = amount remaining. I used these for each problem and got the same answers. Maybe it's just me, but this way seems much faster and easier to solve. Anyone else prefer this method?
+TheOomen2012 I understand and hope I didn't offend. I was just taught a different way and wanted to offer it up in case anyone else was struggling like me. I find that seeing alternatives sometimes helps me learn better. Thank you
When i enter 1440 divided by 58 i get the answer 24.82758621. When you do it you don't seem to get he decimal point after 24. Also the later calculation you get the correct amount of zeros before the numbers start whilst on my CASIO fx-85GT calculator i get 3.358550105x10-8. I know what 10-8 means i just wondered if you could tell me how i get my calculator to give the answers in the same form as you get?
Hi ChemistNATE and everyone, Could you please help me with this following question Radioactive materials are considered to be relatively safe when their activity has fallen below 0.1% of their initial value. (a) How much half-lives does this take? (Answer = 10 half-lives) (b) Plutonium-239 is a by product of nuclear reactors. Its half-life is 24 000 years. How long does the plutonium-239 have to be stored as nuclear waste before it is considered safe to handle? (Answer - 240 000 years)
Got a question saying " The activity of a sample falls to 0.60 of its original value after 100s. Find the decay constant." What formula should i use? How would you answer that?
IT WAS SERIOUSLY THAT EASY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! I SPENT HALF AN HOUR TO GET IT OUT AND ALL YOU HAD TO DO WAS TOO JUST PRESS IT :( Thank you so much!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! : )
you could just use the solve function in the calculator to find the t in the second problem. I assume your 10 canadian bucks calculator will have solve function as where i live in, almost every calculator do have the solve function if you know where to find it
I love when i go online and find a tutor thats high as fuck and teachs like a boss.
Lmaoo
Fr
did this man sneeze because bless this man for helping me.
I know your 6 years late but bro its 2020 cant make those jokes nomo
😂😂😂
Bars
that happened ?! 😂
Funny
Your explanations are great because you don't mention what the equations mean, you actually label them. Complete boss.
... and just like that, in 3 minutes, you did better than pages and hours of my chemistry book and lecture. Thank you!!!!
Very enthusiastic.
Enjoyable.
Concise.
I learned.
Nice Madotsuki pfp
Finals tomorrow anyone?
Yup
even 2 years after
@@zayedalkulaib9678 Finals today lol
even 3 years later
yeah
man I so wish you were my lecture. you just make things seem so easy and understandable.
Your the man, You explain better than a million teachers with their videos
I watched several videos on this topic and this is by far the most clear and concise explanation I was given! Thank you so much for making this video!
Been through tons of vids and this one finally helped me without all the other complicated stuff good work lol
dat intro
"Dont be a fool!" lol
I love watching 11 year old tutorials that still work and teach me chem simple
someone still watching in 2024 👀 same
THANKYOUUUUU SO MUCHHHH!! I've been struggling with this because I need someone to like explain every step by step and guess what?? YOU JUST DID IT. Thankyouuuu
This guy is a legend
Thank you so much. Why can't my teacher just say this?
Because teachers also have nice degrees, and they want to feel good about their fancy degrees.
Because they don't truly understand the concept well enough to simplify it.
***** highly agree!
So glad I can go online and find a great explanation from 11 years ago
rise and shine mr freeman
This man just single-handedly saved me for my chemistry test today
I love how you point to the words and numbers. Great video. Very helpful
Finished AP chem exam, still goes back to chemistnate for precalc help
your still saving lives 10 years later
God bless you Nate, had a test in 4 hours, and didn't know how to solve for exponents.
Taught me half life calcs before my mid year exam, legend!!
After watching numerous videos, I was still lost! This is The Best and easiest way to calculate Half life problems!!! I finally got it, thank you!!
you're killing me XD "yo just guess..I'm a math wiz fyi"
Please help. For the first problem. How come that
(.5^24.82758621=0.0000336?)
Maaaannn thank you so much i was finding easy way to teach my students and here i met you. Excited to go to class now. Thanks alot.
This video helped me sooo much and I really like the way you teach definitely subscribing!
it's like the textbooks make it hard on purpose or something
This is the best video on the topic. It uses the best formula and shows how to solve for the exponent with logs. Thank you so much.
you are the greatest teacher i have ever seen. Im not even exaggerating.
This guy is really goofy, but I like that, makes things interesting
This man just saved my semester, I appreciate you
You da man!
------
Struggled for eternity on understanding this from my professors and teachers.
Learned it here in a little more than 8 minutes.
One like for this vid.
Thank you so much for the formula, really appreciate that and I liked and shared it too. Only 8 days left for IGCSE physics exam,soooo.
Even just the formula has saved my life, especially with the teacher never teaching this and proceeding to put it on the quiz :))))))))))))
this saved my life 🙏🏻 chem test cram
chemistNATE, thank you so so much! I figured this out now, my teacher doesn't teach properly, but you solved my problem. Thanks again!
The real antidote of radioactivity calculation. Thanks alot sir.
Truly a one of a kind wizard, thank you wise stranger...
0.51...the idrc had me
3.33...use BODMAS, don't be fOOl
5.36...im also a math whiz fyi
It's 2024, best teacher ever 😂
He's so excited its so cute
Thank you so much. I just watched this and am amazed about how my physics test is going to be made easier. May God bless you for me.
as for "don't be a fool.." and "I don't care" :v :v :v I enjoyed this tutorial
thank you for the video. for these 7 minutes I understood more then from 3 weeks of lectures!!!
"use bedmas DONT BE A FOOL!!!"
hhaahahah made me laff (im sad)
Cheer Up! It's chemistry!
AWESOME DUDE. I have a prelim exam tomorrow and I had no idea how to do it until now.
damn ! my physics teacher couldnt explain this to his class in two weeks, and u did it in 7 mins ! thanks!
Wow did not expect the last part.
Isn't it easier to use the 0.693/k = (half-life), solve for K and then use the first-order rate law ln(At/Ao)= --kt ? Substituting k in Ao = initial amount and At = amount remaining. I used these for each problem and got the same answers. Maybe it's just me, but this way seems much faster and easier to solve. Anyone else prefer this method?
+Rachel Manno.I wud but i didn't really get what you said, can you do video on that?
+Rachel Manno All roads lead to rome, I prefer using logarithm just because I use it allot but I guess your method also works well.
+TheOomen2012 I understand and hope I didn't offend. I was just taught a different way and wanted to offer it up in case anyone else was struggling like me. I find that seeing alternatives sometimes helps me learn better. Thank you
@@rae7305 Sorry Rae.. His way is soooo much easier especially for those whom are a little weaker in the Math Department
Without this Math Wizz..
I'm totally insane..xD
Thanks^^
THANK YOU SO MUCH!!!! My teacher just handed these problems to us when we were leaving class!! Gotta Love Honors Chem.....(Sarcasm)
I love you you may have inspired me to get back into some math after a lot of bad teachers
This guy teaches so much better than my actual school teacher
yo chemisNate, thanks a lot for the problem 2 you showed. I was looking for it in the internet. gladly found it in your vid. thanks
thank you very much...you have made me a master in solving half life problems.
When i enter 1440 divided by 58 i get the answer 24.82758621. When you do it you don't seem to get he decimal point after 24. Also the later calculation you get the correct amount of zeros before the numbers start whilst on my CASIO fx-85GT calculator i get 3.358550105x10-8. I know what 10-8 means i just wondered if you could tell me how i get my calculator to give the answers in the same form as you get?
Mine is doing that too
Wow, corny and bland jokes. But, literally the best explanation of half-life calculation I have seen... Great job Nate...
Thank you so much. You're a fricking legend.
your videos are better than any others
chemistNATE absolute baller
Takes one to know one
This man just single handedly saved my semester.😭🔥
Many many manyyyyyyyyyyyyyyy Thanks Sir... a lesson forgotten for so many years... thanks for making it easy for me...
Hi ChemistNATE and everyone,
Could you please help me with this following question
Radioactive materials are considered to be relatively safe when their activity has fallen below 0.1% of their initial value.
(a) How much half-lives does this take? (Answer = 10 half-lives)
(b) Plutonium-239 is a by product of nuclear reactors. Its half-life is 24 000 years. How long does the plutonium-239 have to be stored as nuclear waste before it is considered safe to handle? (Answer - 240 000 years)
I love this guys attitude
I love you, thanks for telling us to work it backwards!!! Greetings from Houston, Texas..
Your way of explaining is so amazing and simple. Thank you
You the best teacher 👑
Thanks for giving a easy way to check out half life 😊😊
Its been 10 YEARS woh!
would it be a log or ln? Ive seen others use a ln and not a log
+Leigh Anne Fish log and natural log are basically the same log uses base of 10 and ln uses base of e but same answer
John Malovich is teaching me halflife calculations!
QUESTION- does this work for all half life calculations? including second order reaction half-life?
This is the best teacher ever!!!
I am entering the same numbers etc into my calculator and i am coming up with different answers to you?
whos ready for finals this week?
how do you solve for the half life?
I have an exam tomorrow and this video from so long ago helped😍
Thank you god! i understood a 2 hr lecture in7.4 minutes!! thanks!
how do you calculate how much time for a reaction to occur using half-life?
Got a question saying " The activity of a sample falls to 0.60 of its original value after 100s. Find the decay constant." What formula should i use? How would you answer that?
Is.it.a must to introduce logarithm in
Each number they give me involving how
Hey guys I've seena nother equation for radioactive decay and it goes something like A(t)=Ae^kt. Whats the difference between these equations?
First math Video that made me laugh !! XDDD Thanks for your energy and explanation. That was.... fun ? 0o
"Use BODMAS. Don't be a fool"
I felt called out lmao
Why did you use log instead of LN? Does it make a difference?
no it does not
The great British baking show
The
only when the problem has e in it but the problem he used didn't so you would use log
Thank you so much sir, I felt lost earlier but this really helped me
You made this very easy to comprehend. Thank you!
stg, this dude is gonna be getting me through my bioengineering degree
can you reverse calculate the half life if given that 20 % of a substance decays after a year?
the intro is giving vine energy
ok, how was these hallife tables calculated for the substances?
Thank you my guy for explaining. It truly helps a lot!
How many atoms and grams of 90Y are in secular equilibrium with 50 mCi of
90Sr?
Bruh I have a science exam tomorrow and this is the only thing I don’t know
i didn't get where you do the power of .5 in 1440 can u explain it to me a little better
IT WAS SERIOUSLY THAT EASY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
I SPENT HALF AN HOUR TO GET IT OUT AND ALL YOU HAD TO DO WAS TOO JUST PRESS IT :(
Thank you so much!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! : )
you could just use the solve function in the calculator to find the t in the second problem. I assume your 10 canadian bucks calculator will have solve function as where i live in, almost every calculator do have the solve function if you know where to find it
how do i solve for the number of half lives that have occurred... in other words, how to i solve for "h" in the equation given in the video?
HOw to calculate half life without given quantity? only the percentage of decay and years are given.