DL24MP cheap solution dissipating 600W on a single 150W module electronic load atorch

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  • Опубліковано 18 тра 2023
  • In the current video I wanted to show you the simple idea (there are more) how I diverted 90% of the power from the electronic load to an external FIXED load, a high power resistor.
    In the present case, we diverted 90W and 10W are dissipated by the electronic load.
    What this idea offers:
    - low costs, you can use a single 150W module, set the max 600W in the menu and then mount one or more external resistors (which type is desired)
    - long life of the electronic module because over 90% of the power is diverted externally, resulting in a reduced temperature of the mosfets
    Careful!
    The power of the external load (you calculate it: P= U*I) must always be lower than the power set in the module. If this power is higher than what is set in the menu, the electronic load goes into self-oscillation by the fact that it keeps trying to reduce the power in the mosfets lower then physical is possible but he can't go "negative". The electronic load module becomes unstable and may burn.

КОМЕНТАРІ • 20

  • @mateuszmazur1482
    @mateuszmazur1482 6 місяців тому

    Great idea! Please explain once again. I would like to test battery pack starting from 58V and stopping at 45V (tipical lifepo4 16s setup). I would like to have full 600W load. 100W for main unit and 500W for resistor. So I could get 5x100W resistor in series. And about resistance I get 500W/58V=8.6A, then 58V/8.6A=6.7Om 6.7/5=1.34Om per resistor. But... When I get 45V at the bottom I won't get full 600W in this case. Am I right? If I calculating right if there is such big range of voltage max power at 45V would be around 480W. Electronic load wouldn't compensate power up to 600W. True?

    • @electronistul
      @electronistul  6 місяців тому +1

      Hello, yes you are right, if you want to go with this method divert part of the power to the resistor (as in the video) and use a single 150W module set as 600W.
      Before I start to explain a few things, the battery capacity test is done by constant current (CC), you want to do constant power (CP), I don't think it's right unless you have something special in your projects (each to his own)
      Let's take your case, you want to divert 600W (500W resistor + 100W module) and as you calculated 500W/58V=8.6A, the resistance is 58V/8.6A=6.74 ohm. At 45V you will have 45V/6.74 ohm 6.67A => 300W + 100W electronic load max 400W.
      In the end, regardless of which method you choose, it would be ideal to use the 0-150W electronic load as a compensation for the entire test range of the 45V-58V battery. For example, at 58V, divert 1-5% of the power to the electronic load (5-10W...) and the remaining 95-99% to the power resistor. And at 45V, the electronic load should be around 135-145W and the rest on the resistance. Here you do your own calculations.
      It is possible that 2 x 150W modules can provide you with 0-300W compensation for constant power (CP) testing, although I told you it is not correct to test the battery capacity. Battery capacity testing is done by constant current (CC).

    • @mateuszmazur1482
      @mateuszmazur1482 6 місяців тому

      ​@@electronistul Thank you very much for such detailed answer and explanation. P. S. Yes... So I did some test in a wrong approach (CP). I must change it for CC. If you may. Why it is the better way to test battery (CC vs CP)?

    • @electronistul
      @electronistul  6 місяців тому +1

      @@mateuszmazur1482 it's not a better way it's the correct way to test a battery capacity with (CC) function.

  • @MOZARTF
    @MOZARTF 11 місяців тому

    Hi. Congrats for this enginius mod for the DL24MP electronic load. Could you please inform how to calculate the external resistor value to obtain 600w testing capability for 21v tension power supply? My anticipated thanks.

    • @electronistul
      @electronistul  11 місяців тому +2

      Hello, thanks, it's very simple: 600W at 21V means 600W/21V = 28.6A and the resistor is 21V/28.6A = 0.7 Ohm. But I recommend if you want to use 600W on an single board of 150W, leave at least 50-100W to dissipate on the board and the rest of 500-550W to resistor. You have leave the controller work properly to make CC and other functions to be stable.

    • @MOZARTF
      @MOZARTF 11 місяців тому +1

      @@electronistul really thanks. Appreciate. I'll try this solution. It looks like the best of both words, the simplicity of a load based on resistors, and the versatility of an electronic load.

    • @electronistul
      @electronistul  11 місяців тому +2

      @@MOZARTF And cheaper

  • @leerzeichen1910
    @leerzeichen1910 Рік тому +1

    Nu am inteles ce vrei sa zici cu toate ca nu sunt paralel cu electronica.
    Unde ar putea fi aplicata aceasta functie electronica in viata unui om?

    • @electronistul
      @electronistul  Рік тому

      EN: First of all, the "electronic load" has no application in human life, but is a laboratory tool in industry (repairs, service...etc)
      If we refer to the idea (there are more), I also wrote in the video description: "low costs, you can use a single 150W module, set the max 600W in the menu and then mount one or more external resistors (which type is desired), long life of the electronic module because over 90% of the power is diverted externally, resulting in a reduced temperature of the mosfets"
      If we talk about what "electronic load" means and what it helps us with here, you must know how this tool helps us, you said that you are not parallel with electronics.
      RO: In primul rand "sarcina electronica" nu are nici o aplicatie in viata unui om ci este o scula de laborator in industrie (reparatii, service ... etc)
      Daca ne referim la idee (sint mai multe) am scris si in descriere video: "costuri reduse, puteți folosi un singur modul de 150W, setați maximul de 600W în meniu și apoi montați unul sau mai multe rezistențe externe (de ce tip se dorește), durata mare de viata a modulului electronic deoarece peste 90% din putere este deviata spre exterior, rezultand o temperatura redusa a mosfet-urilor"
      Daca vorbim ce inseamna "sarcina electronica" si cu ce ne ajuta aici trebuie sa stii cum ne ajuta aceasta scula, ai spus ca nu esti paralel cu electronica.

  • @gemisolaris777
    @gemisolaris777 5 місяців тому

    Buna. Am vazut la comentarii pe canalul lui Marius Vâlceanu divergentele intre tine si el legate de diverterul legat la huawei. Spuneai ceva de o eficientă 100% pe off-grid. Poti face un tutorial mai explicit, schema, conexiuni, etc.

    • @electronistul
      @electronistul  5 місяців тому

      Salut, pentru offgrid (fara legatura la retea) solutia lui e 100% ok - o poti face si tu cu un dimmer clasic de leduri/becuri, dar la solutia pentru cei cu injectare in retea si doar suplusul (oricare putere) sa fie divertat aici imi pare rau, am invatat ca facerea de bine strica. Schema la solutia ongrid este publica (bucati pe net) le-am pus cap la cap si am facut, nimic special.

    • @electronistul
      @electronistul  5 місяців тому

      Fi atent acum mi-am adus aminte, poti folosi pentru off-grid asa ceva 100% www.publi24.ro/anunturi/electronice/accesorii-electronice/accesorii-telefoane-mobile/anunt/controler-dumploader-6-80v-30a-230v-ac-dc-baterii-lithium-plumb/107278h168067dd51hif73g038e80825.html

    • @electronistul
      @electronistul  5 місяців тому

      iar aici ai demonstratia facuta: ua-cam.com/video/JJwhOYRmE4M/v-deo.html

    • @gemisolaris777
      @gemisolaris777 5 місяців тому

      Mulțumesc. Acel dumploader pare sa fie ok.

  • @ericklein5097
    @ericklein5097 9 місяців тому

    The slave modules are less than $20 each. Where are you going to find a resistor that can handle the power (500W'ish) that is cheaper than just buying the whole 600W setup? I got mine for $70 after taxes and shipping

    • @electronistul
      @electronistul  9 місяців тому +1

      Hello, check this almost 1US$ / 100W: www.aliexpress.com/item/1005005681408770.html

  • @immrnoidall
    @immrnoidall Місяць тому

    OMG. CAN SOMEONE PLEASE LINK ME TO DIRECTIONS TO TEST CAPACITY OF MY LIFEPO4 CELLS. DO I NEED TO FULLY CHARGE THEM FIRST. WHY SO MANY SETTINGS. I JUST WANT TO FIND CAPACITIES TO MATCH CRAP BATTERY CELLS. SEND LINKS TO SIMPLEST TESTER OR DIRECTIONS TO THIS SO IT DOES NOT END UP IN THE TRASH.

    • @electronistul
      @electronistul  Місяць тому

      Hello, is very simple, charge the battery, set-up DL24MP in CC, set de current (0.5C or 1C) and set de cutoff voltage, and that it. Capacity test.
      and the manual: www.eevblog.com/forum/testgear/atorch-dl24mp-150w-purple-questions/?action=dlattach;attach=1907190

    • @immrnoidall
      @immrnoidall Місяць тому +1

      @@electronistul Thank you so very much. It worked easy. Although, the DL24MP says it is a 30 amp load, yet took 7 hours to measure a fully charged 100Ah lifepo cell. telling me what I suspected, It only held 70 AMP HOURS OF POWER.
      These batteries were really cheap. out of 16 this first one I tested, was the only one not bloated after 5 years of light use. They will still be fine once matched up a bit better, for some solar lights in the wood shed though. Thanks so much. I can always throw a 10 amp active balancer on it if needed. the instruction link is awesome. I just dropped it on the desktop for latter to add to my manual collection. No one sends manuals with stuff anymore. lol. Not even a link.