L25.1 The method of images

#electrodynamics #griffiths #sayphysics
The method of images in electrodynamics involves a clever mathematical technique to simplify complex boundary value problems. This method leverages the principle of mirror charges to create a virtual image system that mimics the behavior of the actual charge distribution. By strategically placing these imaginary charges, one can construct a scenario with known boundary conditions, facilitating the solution of electrostatic and magnetostatic problems. DJ Griffiths' elucidation of the method of images provides.
"method of images," "electrodynamics," "DJ Griffiths," "mirror charges," "boundary value problems," "electromagnetic theory," "virtual image system," "charge distribution," "electrostatic problems," "magnetostatic problems."

[@AhmedKhaleelAhmedAhmed]

قادر جدا تخلي أي حد يحب الفيزياء حتى لو كانت عقدة حياتو ، أسلوبك ف الكلام وشخصيتك وكونك شخص نبغة وعبقري بهذا الشكل بيجذبوا أي حد ليك ، حقيقي من الناس المميزة ال يستحقوا وبجدارة يتقال عليهم دكاترة جامعيين " الله يزيدك من علمه

[@SAYPhysics]

شكرًا جزيلًا على كلماتك الرائعة ودعمك الكريم! أنا سعيد جدًا أن أسلوبي وشخصيتي أعجبوك، ويشرفني أن أكون سببًا في جعل الفيزياء أكثر جذبًا لك ولغيرك. دعواتك وتقديرك تعني لي الكثير، وأتمنى دائمًا أن أستمر في تقديم الأفضل وأساهم في نشر حب العلم. الله يزيدك من فضله ويسعدك دائمًا!

[@AhmedKhaleelAhmedAhmed]

@@SAYPhysics بارك الله فيكم

[@user-bi2tq5mi6n]

a point charge q is placed at a distance d from the centre of infinite conducting plane using method of image,calculate the electric potential and then electric field (e)

[@SAYPhysics]

To calculate the electric potential and electric field using the method of images for a point charge q placed at a distance d from the center of an infinite conducting plane, we introduce an image charge (-q) on the other side of the conducting plane at the same distance d from the plane's center. This creates a symmetric system. The electric potential due to the point charge and its image charge can be calculated using the formula for the potential of a point charge. Once we have the electric potential, we can find the electric field using the relation E = -∇V, where ∇V is the gradient of the electric potential. Since the problem has cylindrical symmetry, we can express the electric field as a function of distance from the plane. Thanks

[@user-bi2tq5mi6n]

@@SAYPhysics sir plz detail say bta day ya numerical kasy solve hoga

[@SAYPhysics]

@user-bi2tq5mi6n first I'm covering the lectures, then, in phase two, I'll come towards the problems. Thanks

[@PerJohannessen]

yes! keep going professor 🥳

[@SAYPhysics]

Sure dear. Thanks 👍

[@vishnuvpriya9470]

Thanks alot sir

[@SAYPhysics]

You're welcome dear

[@roccom.3924]

thank you sir!

[@SAYPhysics]

You're welcome dear

[@roccom.3924]

Question: x^2 + y^2 + z^2 is much much greater than d or d^2?

[@SAYPhysics]

d2, to be dimensionally correct. Thanks