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Ti faccio notare però che una volta rimosso il numero dal vettore, la memoria che il vettore occupa sulla scheda RAM è sempre la stessa poiché non è stata rimossa fisicamente la locazione di memoria del vettore nel momento della rimozione del numero.
No need to ask user for length of array Simply int Length = sizeof(arr) / sizeof(are[0]) It will calculate like Length as int byte size of a = 5*4 , byte size of a[0] = 4 Length = 20/4 = 5
It's wrong code..
It must be
For(i=position;i
I asked value as an input from the user and wasn't able to code well,but taking position seems much easier
How to delete multiple elements like taking the limit frm user and how to delete elements lzz tell me
In the second last loop
for(i=pos-1;i>=n-1;i++)
a[i]=a[i+1];
a[pos-1]=value;
we need to store it lastly in the value variable .
Ossm teaching after so many lectures this is best
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awesome explanation sir.thank you sir.
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How to free up the unnecessary space at the end of array after deleting
these are arrays it can't be changed... also array is made of size 100 it will be still there...To deal with this problem we use Linked Lists
Thank you so much sir.
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Great explanation sir ty❤
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Are you doing job rn?
Thank You So Much Sir!
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Good explanation sir easy to understand for me thank u sir
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Very very very good explanation
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excellent logic,thank you
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Thank you so much 🥰🥰🥰🥰🥰
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Thank you
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Ti faccio notare però che una volta rimosso il numero dal vettore, la memoria che il vettore occupa sulla scheda RAM è sempre la stessa poiché non è stata rimossa fisicamente la locazione di memoria del vettore nel momento della rimozione del numero.
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Awesome 👌
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Galat aa rha hai is code se
Video not show clearly
thanks sir
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Thnks vaiya❤
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No need to ask user for length of array
Simply
int Length = sizeof(arr) / sizeof(are[0])
It will calculate like
Length as int byte size of a = 5*4 , byte size of a[0] = 4
Length = 20/4 = 5
thank you so much sir
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Wrong program output wrong
one mistake in second for loop i
🙏
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Waste of memory ,the code can be more efficient
(Edited) nothing
No that's wrong
Thank you
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