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statistics - binomial distribution - finding probability - examples 1
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- Опубліковано 18 сер 2024
- I show two examples of finding probability for a binomial distribution.
Check out the link below to learn how to do similar examples with the TI-84 plus:
• Binomial Distribution ...
1/2. Because the probability of getting heads or tails is 50 50. 50%=0.50=1/2. In this example success and failure are both 1/2. If it were a six sided dice, then success would be 1/6 and failure would be 5/6. In both cases, success and failure combine to equal 1. P=success and q=failure
Yo can you use the first formula why would you put it up if you're just gonna use the second one. I need to know how to use the first one
U? You?
Well done video; comfortable pace and explanation for beginners in statistics.
H. Joyner
for the second part, we have to calculate the probability for each value of x and do a summation. That seems extremely tedious, even on the calculator, especially when n=25, and you need to calculate P(x>=9), with p=0.5. If anyone knows a simpler, efficient way of doing this on the calculator, please share.
coin = (du-it) syi-ling
In page 152
1 gam-bar = picture
win = me-nang
win-dow = jen-de-la = ting-kap
widow = jan-da
thread = be-nang
2 ang-ka = number (no.) = digit = numerics
goose = ang-sa
shoulder = ba-hu
how did you get 1 over 2
Hi there. I would like to know how did you get the 1/2 in brackets?
Flipping a coin produces 50 50 chance of heads or tails. 50%=0.50=1/2. In this case, success and failure are both 1/2. If it were a six sided dice, success=1/6 and failure=5/6. In both cases, success and failure combine to equal 1.
The p is 1/2 you could either get a head or tail
You have to use a calculator to get the factorial equation?
how did you get p=1/2 ?
p=1/2 is the same as saying 50% it will be heads and 50% it will be tails since there is only 2 possible outcomes
its a coin toss either h/t
If there are two coins then what will become"p"?
How do I know if the question is a binomial question
The number of trials would be fixed. Also, you only have two possible outcomes like wins and losses or yes and no. The trials are independent. The probability of success is the same throughout.
Thank you
x is not the number of successes. x is the number of occurrences. You want to find out the probability of 3 heads occurring, or the probability of, at most, 2 heads occurring. Occurrence =/= success.
'p+q = 1 in this case how you get your q= 0.5 ?
they are complemnet of each other i.e p=1-q =(.5=1-.5)