Angular momentum addition

The process of adding angular momentum in quantum mechanics is a rich topic, one that we can only briefly touch on, but it is an important topic that you should be aware of. Here there be Clebsch-Gordan coefficients. (This lecture is part of a series for a course based on Griffiths' Introduction to Quantum Mechanics. The Full playlist is at www.youtube.com...)

[@Mew__]

Two weeks short of being 7 years old, this video is still among the best on UA-cam to explain the horrific "Addition of Angular Momenta" paragraph in Griffiths. Brilliant.

[@ifrazali3052]

It's 11 years old now

[@QuantumOverlord]

Adding angular momentum is one of the most difficult things I have come across in physics so far. I hate how hard it is.

[@QuantumOverlord]

@eh6794 I think I got a 2:1 in it which would be in the 60-70% range. In the UK that's considered good. Good luck with your finals!

[@dalmudi3539]

Thank you for explaining this in a way that finally makes sense. One of the best videos ever.

[@Valeria-ib6gj]

Finally!, as a mathematician that is trying it's way into physics I can finally use my knowledge on freaking representation theory from my tesis hahah sorry it is just that it was really hard for me to understand those topics when I was developing my tesis but now I can use it, actually I stopped the video several times bc I was connecting the dots already and when he said exactly what I was thinking I was so happy. Haha well have fun in life and wish me luck on my master in physics bc I am going to need it :3

[@the-fantabulous-g]

Brant Carlson you da MVP, I wouldn't understand any of this without watching and rewatching your videos. Thanks for sticking through with completing this lecture set!

[@MrJespur]

Brant, thank you for saving my semester!

[@SR-pi8qt]

Thanks to you, I've spared 2 hours trying to study it from the books, alone. Your explanation is very clear ! Merci !

[@guitar0wnz]

This is the greatest video on this topic I have ever seen

[@ferox7878]

you're a good guy, Brant, I appreciate it a lot.

[@charmendro]

Bro how did u explain this so well, still unsure about some things but i think i understand a lot more than before the video

[@ivanvargas1522]

Class has started to go over this, This helps so much! Thank you !

[@aeglos07]

What is the reason to use the lowering operator here? As far as I can tell, it does not provide any further information, since we already know the S_z Momenta. We also know the possible spin combinations. I'm confused....

[@rubindasgupta9462]

What if the two particle interact with each other and the coupling constant is a non zero quantity (J). How will the J be incorporated in the addition of angular momentum?

[@159abdellah]

thank you very much you just helped me a lot !

[@amedeodeamicis1957]

with CG coefficients i don't understand because my teachers writes when s1=1 and s2=1/2 ...... |3/2 -1/2> = sqrt (2/3) |1 0> |1/2 -1/2> + sqrt(1/3) |1 -1> |1/2 1/2>

[@lorenzofiordaliso8839]

Thank you this really helped!

[@joaobernardo5593]

Perfekt. Danke !

[@gabrielgonzalezdominguez6746]

Thank you very much indeed.

[@redowanahmedniloy6978]

... and they are bloody complicated, I got scared after hearing this, and when I understood, I got that complicated is an understatement :(

[@spacedoggo352]

briliant

[@zoomalkchannel]

Can you explain me how you got the state at 7:30 ?

[@HankGussman]

ua-cam.com/video/xeYysQWLXqE/v-deo.html - Check this video to understand how the fourth state is derived from orthogonality argument.

[@md65000]

At 4:35 where is the factor of h-bar?

[@JayAyyWhy1231]

Very often angular momenta are given in units of h-bar -- otherwise h's would be abound.

[@maxinatorborderls]

Better than Griffiths

[@aracelial9188]

Thank you! now i think i understand it!

[@rafsanjani9207]

You are the best :)

[@krishnadhakal5246]

Thank you

[@reehji]

omg, very helpful :3
Thanks