Sir you have explained far better then my so called BIg GATE institute , You bring me to the easiest way to find out Gain Margin, Thank you very much, Have a nice day
thank you... you're doing what my tenured professors at the university of southern california, USA cannot: TEACH.. truly helpful and amazing. i will graduate because of your videos
I watched this UA-cam video about phase margin and gain margin, but I must admit that I was a bit confused and couldn't fully understand the concepts being discussed. It's possible that the video was intended for a more advanced audience, or the presenter didn't explain the ideas in a way that's accessible to beginners like me. I also noticed that some people in the comments were applauding the presenter's explanation, which made me wonder if I'm missing something. However, I understand that everyone has different levels of understanding and familiarity with the topic, so it's possible that they had a better grasp of the concepts. If anyone has any resources or recommendations for learning about phase margin and gain margin, I would greatly appreciate it! I'm eager to learn and understand these concepts better.
@ibrahimabdi -- this is 8 year old video, not likely to get an answer from the TA who has no doubt, found a paying job! These are concepts from a Control Theory class, (call it CT), which Electrical Engineering students must study as a junior or senior in their undergraduate training. The idea of CT is to move a complex system described by differential equations, out of the time domain, into an imaginary domain -- the frequency domain -- via a Laplace Transform. Or, if you wish to work with a discrete domain, the Z Transform. My point in supplying these details is to demonstrate that it requires advanced math training to get the big picture of CT. I wish you the best of luck with your education.
YAY!! THANKS A LOT, have been looking for the step by step procedure for this and now I know it. Thanks again MAN... Keep posting :) Would like to know this step by step process for PHASE MARGIN too :)
Yes but the result is the same. Multiply both numerator and denominator by the complex conjugate of the denominator and then setting the imaginary part of the resultant numerator to zero you get the same formula.
shouldn't the imaginary part be obtained by multiplying the denominator and numerator by the conjugate of the denominator? because we can't separate fraction in two fractions, one the imaginary and the other the real part, till the denominator isn't expressed in factorised form and the numerator is an algebraic sum of real and imaginary part
hey sir, i really like your way of explanation, i'm just confused about one thing, is the crossover phase frequency the same as the phase margin? if not, pls tell me how to get the latter and thnx
Your videos are amaaaaaazing! Very helpful. Thanks! I am a student of Murray State University, KY and I have an exam on 30th of May. Can you please upload a video on lead compensators and lag compensators via root locus? It'll be great!
Just one query: For Phase crossover frequency, you said to equate the Im[G(jw)]=0. But actually you equated the imaginary part of the denominator of G(jw) to 0, i.e, without rationalizing G(jw). So, please clarify you mean to equate the denominator only or the whole rationalized transfer function.
It's unreal explaination. I am very much impressed with your provided solutions. Could you please help me resolving following transfer function : 1/s(s+1000)2 . Find GM. where gain coefficient K : 630 x 10 power 6.
Sir you have explained far better then my so called BIg GATE institute , You bring me to the easiest way to find out Gain Margin, Thank you very much, Have a nice day
All the best... Thank you for the kind words..
thank you... you're doing what my tenured professors at the university of southern california, USA cannot: TEACH.. truly helpful and amazing. i will graduate because of your videos
Chase Schidfar I am very glad it was helpful :) All the very best for your exams. Good luck.
YES! FINALLY! I was pulling out my hair trying to figure it out from my notes and you clarified it. Thanks a lot, you rule!
Thankyou :) Glad it helped :D
Oh men, you are such a Savior. Bless🙏🙏
Thank you. I am glad it was helpful.
I have an exam on 17th may n I watch all of ur video's for preparation sir...u r awsm sir...
so, that's tomorrow... All the best :)
actually i'm Nigerian i like this lecture i have exam next week 10/09/2019
I am glad it was helpful :) All the best !
Also Indian University exm 😚
I watched this UA-cam video about phase margin and gain margin, but I must admit that I was a bit confused and couldn't fully understand the concepts being discussed. It's possible that the video was intended for a more advanced audience, or the presenter didn't explain the ideas in a way that's accessible to beginners like me.
I also noticed that some people in the comments were applauding the presenter's explanation, which made me wonder if I'm missing something. However, I understand that everyone has different levels of understanding and familiarity with the topic, so it's possible that they had a better grasp of the concepts.
If anyone has any resources or recommendations for learning about phase margin and gain margin, I would greatly appreciate it! I'm eager to learn and understand these concepts better.
@ibrahimabdi -- this is 8 year old video, not likely to get an answer from the TA who has no doubt, found a paying job! These are concepts from a Control Theory class, (call it CT), which Electrical Engineering students must study as a junior or senior in their undergraduate training.
The idea of CT is to move a complex system described by differential equations, out of the time domain, into an imaginary domain -- the frequency domain -- via a Laplace Transform. Or, if you wish to work with a discrete domain, the Z Transform.
My point in supplying these details is to demonstrate that it requires advanced math training to get the big picture of CT.
I wish you the best of luck with your education.
YAY!! THANKS A LOT, have been looking for the step by step procedure for this and now I know it. Thanks again MAN... Keep posting :) Would like to know this step by step process for PHASE MARGIN too :)
Welcome :) Will do on phase margin soon :)
Chinmaya A.S.V when will u give for phase ?
You make very easy topic now thanks 👍
Most welcome :)... It is very kind of you to say so..
A legend among men. thank you
Thank you sir
You cleared my all doubts about this topic.
Glad it was helpful :) Thanks!
explanation is good
but you should keep the camera stable as it is creating disturbance in understanding
Brilliant, but let the audience know that k = 1 so it is K/1/Kg then -20log(answer) in Db ..many thanks!
Very simple explanation sir thank you very much sirr 😊
Thank you. All the best !
Thanks Man , Very good Explination
You're welcome!
Excellent Work. But, do you have video to show how to find phase margin without plotting?
Will upload one soon..
Very helpful, thank you! How will I use this to find the phase margin?
simply superb sir
What would you do if the number on the top wasn't 1 though? This is where I am stuck
why not re express it as a fraction in the denominator? Say it was a 2, just put 2/4 in the denominator and multiply through
No he means if in numerator (s+1) exists
multiply with complex conjugate both num. and denum. . Then equate imaginary part of numerator to zero.
how about any other transfer function with numerator ? E.G. k(s + 1)
thank you so much :)) greetings from turkey :)
I am glad it was helpful :) Greetings to you too ! All the best !
For separating the real and imaginary part, don't we have to rationalize the fraction?
Yes but the result is the same. Multiply both numerator and denominator by the complex conjugate of the denominator and then setting the imaginary part of the resultant numerator to zero you get the same formula.
lol when he used the calculator to determine 1/sqrt(2) and its output was sqrt(2)/2. All the same, good presentation! :)
you are awesome..it just cleared my every doubt
Thanks. I am glad it was helpful !
@@ChinmayaASV phone number ... Help me
i love your video! but how to find phase margin for this question?
Thanks very much bro..... what if the numerator is not one?
Do it for phase margin and gain crossover frequency please.
hello did you find one for the phase margin?
@@omarsinno2774 yes i did, do you need link?
@@UnknownDistraction yes please
@@UnknownDistraction could you please post the link? Would be of great help!
You are doing a great job sir how do we find bandwidth and DC gain of a simpler transfer function..thanks in advance
shouldn't the imaginary part be obtained by multiplying the denominator and numerator by the conjugate of the denominator? because we can't separate fraction in two fractions, one the imaginary and the other the real part, till the denominator isn't expressed in factorised form and the numerator is an algebraic sum of real and imaginary part
Sanhita Guin it's also correct to do that, try different examples you will see it
Yes, but it wouldn't matter mathematically after rationalization. Same answer both ways.
it is very helpfull thank you chinmaya
for gain margin there will be a negation before 20log(kg) formula.
that is up to how do you define kg. here is kg = 1/|L(jw)|. if kg = |L(jw)| then you need minus.
Sir could u please find for same problem phase margin and Gian cross over frequency
Can i draw bode plot on normal graph if log graph is not given in exam?? But how??
hey sir, i really like your way of explanation, i'm just confused about one thing, is the crossover phase frequency the same as the phase margin? if not, pls tell me how to get the latter and thnx
Your videos are amaaaaaazing! Very helpful. Thanks! I am a student of Murray State University, KY and I have an exam on 30th of May. Can you please upload a video on lead compensators and lag compensators via root locus? It'll be great!
Please help me....now I am 3 rd year student...I guess u got passed out from b.tech
@@dhonipspk2423
Did u find any helpful videos
My exam is in 24h
Absolutely impressive 💓💓
Thank you :) I am glad it was helpful !!!
is the phase crossover frequency the same thing as the gain crossover frequency?
how do you do it when you have a zero in the function?
Just one query: For Phase crossover frequency, you said to equate the Im[G(jw)]=0. But actually you equated the imaginary part of the denominator of G(jw) to 0, i.e, without rationalizing G(jw). So, please clarify you mean to equate the denominator only or the whole rationalized transfer function.
the intersection with real axis needs to be found out,so whole imaginay part needs to be equated to zero
please upload video on phase margin also
thnk u sir....helped a lot.... :)
Is it phase cross over frequency or gain margin. That he is finding out
I don't know man 🤔🤔🤔🤔
Thankyou so much :) it really helped ,can u please upload how to find phase margin as well
how to find out phase margin and gain cross over frequency without plotting bode plot??
It's unreal explaination. I am very much impressed with your provided solutions. Could you please help me resolving following transfer function :
1/s(s+1000)2 . Find GM. where gain coefficient K : 630 x 10 power 6.
sirr plss upload video on niquist plot
How can i get the phase margin? Thank you
Thanks a lot for this video......
how about estimating phase margin with given transfer function??
can u pls post a video on that too.
i like your video
Thank you...Hope it was helpful :)
Sir what to do when there is not 1 in numerator???
For the phase cross over frequency, why is it required to have imaginary part of the transfer function equal to 0?
hi, i want to know how to find the gain margin for time delay? do we have to apply euler rule
How Phase margin calculate
@6.45 while calculating gain margin you have not considered the imaginary part by saying it is zero.. Can you please explain it..
can you give me idea about to find phase margin from TF?
Can you do phase margin please
Excelent!! Thank you
You are welcome!
please add Nyquist plot ...
Nice video, nice english
Thank you for the kind words
WOW! THANK YOU SIR
THANK YOU KKINGGGG💕🛰
All the best !
Can Wpc be zero??
sir upload phase margin video nd one thing more when cross over frequency is 0,then gain margin will be?
Hellll...i am not getting why in finding phase cross over frequency we need to take imaginary part as zero...some1 plz ans
Bcz for finding the value of GM we need help"wpc" w=wpc(phase crossover freq).
Here we take imaginary part of G(s) H(s)=0
Explain slow sir and tell clarity its very understand sir
Thank you for the kind words..
Can't we take w^3=1?
Cool but u didnt calculate phase margin
THANKS A LOT SIR....
Wat happens if imaginary term comes in numerator also..
God bless you
Thank you and all the best..
thank you sir
TF must be L(s) = G(s)*H(s) loop TF where H(s) =1.
awesoooome man thanx alot but i also need the phase Margin if you dont mind
.....^-^
thank you!! very much!!!
grt vedio sir
Help full to me bro
free-courses.org share please with your friend it contain courses for free on the domain of control system
thanks for clearance....
Thankyou sir..
Thanks dude!
Thanks Sir !
Wpc. Y u took IMG part 0
Why was the function not rationalized before making calculations?🙄
Thanks!
Glad it was helpful :) Thanks!
Wg ?
thanks .
Welcome :)
It was a good video :)!!!
very good
sir where is phase margin
can someone tell me how do we find phase crossover frequency from this: -3.14= inv tan (-0.5w)-0.1w
im suffering from this aswelllllllllllllllll
What if the gain margin is zero ?
That means nyquist plot crosses negative real axis of L(s) at (-1,j0). Then the system is unstable after 1.
Thankyou Sir
You didn't find the phase margin and the gain cross over freq.
conjugate multiplication!
4:07 Kanye in the house :P
Thanks buddy
Thanks. I am glad it was helpful !
you can't take imaginary part like that that's not right i think
you can't separate fraction by separating the denominator
Grt ! onee Thank you !! :)
superbbbbb...
tanks more....