Hi teacher, thank you for solution. I have a request. Can you share where did you find from questions at your classic mechanics list? I could not find those kind of questions.
You need to do a course that includes Lagrangian Mechanics (first year uni). Any average uiversity Classical Mechanics textbook should have a chapter on Lagrangian Mechanics. There are plenty of these questions over there.
I have an exercise which asks the constraint force, the answer is F = -[mg/[1-(m+M/m)*tan^2(theta)]]. Using the constraint that you used I found a similar answer but isn't the same, do you know how I can get to that answer?
But a thing that caught my eye is the fact that you choose as your generalized coordinate diferents coordinates that if you were solving the same problem without considering any constraint.
and that answer one question that I had: "If I try to solve it using the multipliers and then don't using them, do I have to choose the same generalized coordinates in both cases?"
@@physhell9926 Also, great channel dude, I'm having Classical Mechanics in my graduation and I loved Lagrangian Mechanics and you channel helped me so much. Thank you.
Yes you can. But this is the complete method. Without this lamba, you can calculate the accelerations but you won't have a clue about the forces of constraints.
Hi teacher, thank you for solution. I have a request. Can you share where did you find from questions at your classic mechanics list? I could not find those kind of questions.
Same
You need to do a course that includes Lagrangian Mechanics (first year uni). Any average uiversity Classical Mechanics textbook should have a chapter on Lagrangian Mechanics. There are plenty of these questions over there.
I have an exercise which asks the constraint force, the answer is F = -[mg/[1-(m+M/m)*tan^2(theta)]]. Using the constraint that you used I found a similar answer but isn't the same, do you know how I can get to that answer?
Hi. Yes it is very similar to the result here. But are you sure the coordinates (x-y axes) are defined same as here in this video?
@@physhell9926 No, i'm not sure because the exercise doesn't show any figure.
But a thing that caught my eye is the fact that you choose as your generalized coordinate diferents coordinates that if you were solving the same problem without considering any constraint.
and that answer one question that I had: "If I try to solve it using the multipliers and then don't using them, do I have to choose the same generalized coordinates in both cases?"
@@physhell9926 Also, great channel dude, I'm having Classical Mechanics in my graduation and I loved Lagrangian Mechanics and you channel helped me so much. Thank you.
You could have done it without the lambda, no?
Yes you can. But this is the complete method. Without this lamba, you can calculate the accelerations but you won't have a clue about the forces of constraints.
Music!!!