My teacher took entire 2 hour class on this topic and I could understand nothing but you made it just to simple under 5 mins I could understand everything!
Hello! HCF contains the COMMON terms of both f and g, which have the lower exponent. So both, f and q, must contain (x-3)(x+3) factors. So, one of the roots of (3x^2-7x-a) must be 3 (because we factor the polynomial to (x-x1)(x-x2), so to have x-3 there, one root of this polynomial should be 3), and one of the roots of (2x^2+3x+b) must be -3 (to have there one factor (x+3)). Compute delta for both equations and then find a and b for which you get one of the roots 3, on first equation, and one of the roots -3 on second equation. Hope this helps.
8 years later ur still helping me with clutching my sat thanks a lot sir!
I have done my quiz easily because of this fabulous video explanation.
Thank you sir
I appreciate it sir. Day after tomorrow is my exam and it helped me a lot
Your explanation in English is so exact...👍👍👍 Thanks sir
Dhanyawad....🙏
Write some big alphabets sir
My teacher took entire 2 hour class on this topic and I could understand nothing but you made it just to simple under 5 mins I could understand everything!
Thankyou sir ❤🎉
I understood really well sir
After 6 yrs..The best explanation available on youtube..thank you
Sir I have a doubt..
What if they give two polynomials,their HCF and ask us to find A,B in polynomial
Ram Slam08 pal its one year old he will not reply
Time flies though..
@@leotronicscales3597 now its 5th year
@@omprakashreddi961 maybe 6th year
@@gughanraju5681 😂
I can't understand , sir your Hcf and LCM of polynomial's
Dude why can't you write 7x 5x+2x ! Why 6x+x ? Y only one x :D
What about the cubic polynomials
Thanks for this... Very nice
Good..
Super sir , sir plz explain tamil language
Sir can you do of only two term
Thank you
awsome explaination!!!i am seeing this video before 15mins of exams and hope so this video will save my 4-5marks
Thanks
What if there are two 4th degree polynomials???
You mean biquadratic polynomial?
Thanks 🙏🙇sir perfectly explained!
Super
I have a doubt that is
If the HCF of the polynomial f(x)=(x+3)(3x^2 -7x-a) and g(x)= (x-3)(2x^2 +3x+b) is (x+3)(x-3) then a+b=
Hello! HCF contains the COMMON terms of both f and g, which have the lower exponent. So both, f and q, must contain (x-3)(x+3) factors. So, one of the roots of (3x^2-7x-a) must be 3 (because we factor the polynomial to (x-x1)(x-x2), so to have x-3 there, one root of this polynomial should be 3), and one of the roots of (2x^2+3x+b) must be -3 (to have there one factor (x+3)). Compute delta for both equations and then find a and b for which you get one of the roots 3, on first equation, and one of the roots -3 on second equation. Hope this helps.
What kind of stupid ass
Very nice
Thank you so much Sir 😊
Thank you sir
Thanks sir
Nice
After I ask for help in the comment session than I found out that it is of 2015 dude!!! Now 2021
Thanks sir . Now I understood perfectly
What to do if there is no common factor
Then the answer will be 1
Hello sir how to factorise pls show
Thank you bro for explaining this
Got it. 👍
Selute
I got it
sir explain some more
2x^2+xy+y^2 & x^2+xy+2y^2
How can find the hcf of these
Polynomial
very good explanation
Abe yrrr toda samjha bhi do basss solve karte chale jaa rahe
so
not
Thank you Sir
Thanks
Thanks sir
Thanks
Thanks sir
Thanks sir
Thankyou
thanks