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Sir aap jo padhate ho achese smjh ata hai sb pr kahi kahi jb aap hindi terms ka use krte ho to confusion ho jata hai, to sir hindi ke sath sath English terms ka bhi use kiya kru. Thank you sooo much Your obediently
Circumference of front wheel × no. of its revolutions = circumference of rear wheel × no. of its revolutions 2Πx×n=2Πy×m (let 'm' is the revolution of rear wheel) m=nx/y
Thanks so much sir aj mera exam third shift mai tha 4 clcok sirf sir mai apke sb lecture dowanload karke dekhta tha sir exam mai 26 question aaye the maine ek bhi question galat nae kiya sir Maine total accurate 72 kiye ek bhi rong ni hai thanku so much sir
Area =1/2 (sum of parallelsides)×height 1/2 ( 7x+4x) 22x =176 , to solve X=4 Therefore, AB side = 7×4=28 CD= 4×4=16 CM =2×4=8 AM =AN+NM 6+16=22 (AN=BM= 12/2=6) NOW USE PYTHAGORUS TRIANGLE ACM AC2=CM2+AM2 8SQ+22SQ ANS = 2 ROOT 137 SAI HAI NA ANSWER PLEASE REPLY ?? 32 10
sir agar hum last question(rhombus) mein dekhe toh waha pe agar hum right angled triangle consider kare toh hypotenuse 6.5cm hein and side 10cm...How? Aur hum jante hein ki ek point se ek line tak shortest distance perpendicular hota hai lekin yaha pe sab ulat hai
Sir plz if it is possible then plzz sir start mix veg as u start in during alp it really helps a lot sir... plz sir make such kind of vidoes till je exam is not completed its a humble request sir... Thanks in adwance sir...
Sir plzz jaise aapne yahan pr geometry krwayi hai.waise hi ek baar height and distance or algebra bhi krwa de bss main main jahan se aa skta h.plz plzz sir its a request
Q ki last question mein value thik nhi tha...sare value anuman(hypothesis)se liya gaya... Example : altitude 10 cm jahape side 6.5 cm... altitude side se jada kaise ho sakta hai???toh actually 10 cm value possible nhi hai... isliye pehlebale formula se kabhi sahi answer nhi aayega..
In the last question: how can the altitude of a rhombus be 10 when its side is 6.5 . I mean if we make a rt triangle with altitude 10 inside the rhombus... Its hypotenuse will be 6.5 . How is that even possible?
52:57 rhombus possible nhi h n sir ?? ...I think Ye parallelogram hoga kuki rhombus hota to diagonal must be less than 2×6.5=13 jbki question me 26 diya h... Is bat ko ese b smjha ja skta h k triangle ki do side ka sum teesri se zda hota h... Jo k yha ques me rhombus man ne pr fulfil nhi ho rha
Sam Chaturbhuj ki Bhuja 6. 5 centimetre Hai To sirslamb 10 kaise hoga samajh mein nahi aaya aur Vikarn 26 kaise ho sakta hai Agar sirslamb nahi diya hota to buja se Vikran Kaise nikalte 🤔🤔🤔🤔🤔🤔🤔🤔🤔
👉🏻 Get *RRB JE* Test Series: bit.ly/2Z2ERsX
😲 Use Referral Code *“wifistudy”* & Get *10% Discount* on Unacademy Plus Subscription
🤙🏻 *Call/WhatsApp:* 70233-33675
Sir mean median mode Bata do exam m Puch t hai
Bhad nhi bad gayi sir
Ek dum mast
Good study
Teaching to bhut karate h. But apka tarika lajawab h sahil sir🍉🍒🍓🍍🍋🍊
Sir aap jo padhate ho achese smjh ata hai sb pr kahi kahi jb aap hindi terms ka use krte ho to confusion ho jata hai, to sir hindi ke sath sath English terms ka bhi use kiya kru.
Thank you sooo much
Your obediently
I love Sahil sir....... great job
Ans
1- 2 root 137
2- 32
3- 10
Thank you sir 😊
Sir आपने सही कहा जैसा आप पढ़ाते हो ऐसा पढ़ने के लिये 5000र लगते ओर ओर आप फ्री में पढ़ाते हो
धन्यवाद sir g
Superb....... superb....... superb...... superb....... superb....... Excellent......Sir
U r the best teacher sir
Itna kbi b kahi b nhi seekha.
Thanks alot.
Superrrrbbbbbb dil khus ho gya or Apka pyar yuhi bn rha sahil brother
Area of path really reminds me about my high-school maths classes..thank u ...🤗
Homework questions 32, 10 thank you sir
HW Ans.
I) D = 2 root 137 cm
Solution : 11x^2 = 176 ; x =4 ;
Sides = 7x = 28; 4x = 16 ;
Perpendicular h = 2x = 8 ;
Diagonal = sqroot ( 484 + 64 ) = sqroot ( 548)
= 2 root 137 ans.
II) D = 32 cm
III) h = 10 cm
Home work 1 - (2√137
2-(32cm
3-(10cm
Thank u very much sir for your such an effort for us 🙏🙏🙏🙏🙏
Sir bohut hi acha........ Thank you so much.....
Dhanyawad sir ji...😍👏👏
1. Diagonal length= 2√137
2. Diagonal = 32 cm
3. Height = 10 cm
Sir apki mehnat Or imaandar ko salam
Bhut achha lgta h sir hm s bina kuch liye ....aap itna mehnat s pdhte ho 🙏🙏
Nice session sir
Hw answes
(1)d1=16,d2=32cm
(2)h=10cm
U r doing great job u work is incredible always inspiring keep it up sir
Thank you Sahil sir.. Nice class
H/W....larger diagonal=32cm & height of trapezium=10cm
You are best sir
1》2 root 137 cm
2》32 cm
3》10 cm
Homework questions answer- 32 and 10
Thank you sir🙏🙏🙏🙏
Circumference of front wheel × no. of its revolutions
= circumference of rear wheel × no. of its revolutions
2Πx×n=2Πy×m (let 'm' is the revolution of rear wheel)
m=nx/y
Solution of HW
Q1- 2√137
Q2- 32cm
Q3- 10cm
Marvellous sir jee !
Thanks so much sir aj mera exam third shift mai tha 4 clcok sirf sir mai apke sb lecture dowanload karke dekhta tha sir exam mai 26 question aaye the maine ek bhi question galat nae kiya sir Maine total accurate 72 kiye ek bhi rong ni hai thanku so much sir
Thanks sir for ur efforts🙏🙏🙏🙏🙏
52:10 sir ji, hum khiladi hai, toh aap khiladiyo ke khiladi hai........
Nice class
Good job
.🙏🙏💖🙏🙏💖🙏🙏💖🙏🙏
Sahil sir best math teacher in WiFi
You are Awesome... Sir... Thank You to wifistudy for such helpful classes👍👍
My ideal sahil sir
Thanks Sir Ji
You are grate
hw answers are : 2 root 137, 32 and 10..thanks
Area =1/2 (sum of parallelsides)×height
1/2 ( 7x+4x) 22x =176
, to solve
X=4
Therefore,
AB side = 7×4=28
CD= 4×4=16
CM =2×4=8
AM =AN+NM
6+16=22
(AN=BM= 12/2=6)
NOW USE PYTHAGORUS
TRIANGLE ACM
AC2=CM2+AM2
8SQ+22SQ
ANS = 2 ROOT 137
SAI HAI NA ANSWER PLEASE REPLY ??
32
10
Hina jii GA..
Thank u sir.....maharaj abb to karlo ....yea bat roj bstana sir plzz mujhe bahot a6i lagte hey.....😂
Thanku sir maza aa gaya...
Sir aap mahan he.🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼
Very nice session sir u are really great u teaches so well...
Thank you sir love you sir ap hum loge ke liye itne mehnat karte hai to Ek like to banti hai ap logo 👍👍👍👍👍👍👍👍👍👍
Thanks sir ji for this class 👌👍
Q1.:- (2√137)
Q2.:- (32)
Q3 :- 10
गुरु जी नमसते कृपया हिन्दी में बताने की कोशिश करे हम हिन्दी माध्यम से है
sir agar hum last question(rhombus) mein dekhe toh waha pe agar hum right angled triangle consider kare toh hypotenuse 6.5cm hein and side 10cm...How? Aur hum jante hein ki ek point se ek line tak shortest distance perpendicular hota hai lekin yaha pe sab ulat hai
Sir plz if it is possible then plzz sir start mix veg as u start in during alp it really helps a lot sir... plz sir make such kind of vidoes till je exam is not completed its a humble request sir...
Thanks in adwance sir...
jafar hussain firstly I will complete syllabus then will start
@@sahilkhandelwal8631 thnks sir as soon u finish the syllabus dont forget to start mix veg it build up our confidence level sir for xam🙏🙏🙏🙏
Great sir
u r great😃😆
Q 1
Ans (a) 32 CM
Q 2
Ans (B) 10 cm
Great sir🙏🙏🙏🙏🙏🙏
very nice method
Q1. 2√137
Q2. 32
Q3. 10
Good morning sir
Ssc or lekhpal k form kb aare.... pleas btao Bhai ji
Nice class sir thank you very much sir 👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍
🙆 Yupp!
Best teacher
Very well class
🙌🙌🙌🙌
H w
Q(1) 32 cm
Q(2) 10 cm
Good topic sir thanks
home work
1) 2 undaroot 137
2)32
3)10
Nice video sir
U r Great sir
Sir ab to ghr bethe pad ke selection le sakte han.....
mja aa gya sir
Sir bahut mehnati h☺☺
1. 2 * sqrt 132
2. 32
3. 10
Sir plzz jaise aapne yahan pr geometry krwayi hai.waise hi ek baar height and distance or algebra bhi krwa de bss main main jahan se aa skta h.plz plzz sir its a request
Thank you sir
1st h.w ans- 2 root 137
2nd - 32cm.
3rd - 10cm.
Best sir 😇😇
Mja aagya sir
In last practice question of rhombus of side 6.5 cm.
a^2= sum of squares of half of diagonal
Is not working here what is the reason
Haan yaar. But why
Pele a² wala formula galat likh diya tha sir ne.
Q ki last question mein value thik nhi tha...sare value anuman(hypothesis)se liya gaya...
Example : altitude 10 cm jahape side 6.5 cm... altitude side se jada kaise ho sakta hai???toh actually 10 cm value possible nhi hai... isliye pehlebale formula se kabhi sahi answer nhi aayega..
In the last question: how can the altitude of a rhombus be 10 when its side is 6.5 . I mean if we make a rt triangle with altitude 10 inside the rhombus... Its hypotenuse will be 6.5 . How is that even possible?
Sir hw ans} (1) 32 cm&
(2) 10 cm nise session .👍👍👍👍👍🙅🙅🙅🙅👏👏👏
Doubt in last question. In rhombus how
Altitude (10) is greater than side ie. Hypotenuse
Nice vidio sir thanks sir
Thanx 🤗
1) 32
2) 10
1:32cm,2:10cm
Good
52:57 rhombus possible nhi h n sir ?? ...I think Ye parallelogram hoga kuki rhombus hota to diagonal must be less than 2×6.5=13 jbki question me 26 diya h... Is bat ko ese b smjha ja skta h k triangle ki do side ka sum teesri se zda hota h... Jo k yha ques me rhombus man ne pr fulfil nhi ho rha
Also agr rhombus hota to 4a^2=d1^2+d2^2 krne pr d2 ki imaginary value aati...
1.2√137
2.32
3.10
Aap bahot jaldi main lag Raha ho sir.....ab pehla vali baat nii lag rahi hai
Jo natural ha usko formula ratwati hoo...
ans
1.32cm
2.10cm
Koi btaega ye 3d ki pdf kha se download kru
Love u sir...
Q1. 32
Q2. 10
Anyone in lockdown....
37:55 sir hame lga tha ki hum hi atakte hai....... hahahhhhhah
Hw questions ans 2√137, 10,32
What is difference between centroid and incenter?
Sir trapaziam ka perimeter ka concept ek bar batado sir please
Sam Chaturbhuj ki Bhuja 6. 5 centimetre Hai To sirslamb 10 kaise hoga samajh mein nahi aaya aur Vikarn 26 kaise ho sakta hai
Agar sirslamb nahi diya hota to buja se Vikran Kaise nikalte 🤔🤔🤔🤔🤔🤔🤔🤔🤔
Plz explain
Sir question with side of rhombus 6.5 cm
Altitude(10 cm) cant be more than side and also diagonal cant be more than sum of two adjacent sides.
Raj Kumar yes u r right but kya kre Question to Question h btw well done
Sir mts ke liye sallbulls bataiye
220×200-200×180=44000-36000
=8000
Sir ntpc ka koi practice set bataiye