Special theory of relativity | Special relativity questions and answers | Special relativity lecture
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- Опубліковано 17 гру 2024
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About this video
In this video, I have explained the questions on the special theory of relativity. I have solved a few questions on special theory, including MCQ(s) and bsc 1st year questions and answers. The objective of this video is to give solutions to the problems of special relativity and help the students in the examination. I have solved MCQ(s) and descriptive questions to help the students.
Topics covered:
(i) Length contraction
(ii) Time dilation
(iii) How to solve problems on muon decay and
(iv) Twin paradox.
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HAVE COMPLETE UNDERSTANDING SPECIAL RELATIVITY THROUGH SOLVED PROBLEMZ.. THANK YOU SIR
Welcome
An amazing video for beginners who have read the theory but dont understand how to approach questions, sir.
Thank you very much 👍
Really good
"In May and November, the Earth is moving at "right angles" to the line to Algol. During this time we see minima happening regularly at their 2.867321 day intervals. However, during August, the Earth is rapidly moving towards Algol at about 107,229 km/hr as explained on my How Fast Are We Moving? page. (The Earth moves approximately 202 times its own size in one day.) So in 2.867321 days the Earth moves about 7,379,039 km closer to Algol. _But the varying light from Algol doesn't know this - its light waves left Algol 93 years ago and are travelling at a constant speed._ The result - we "catch a bunch of minima early" during August as shown on Chart 2. Exactly the opposite happens during February - the Earth is moving away from Algol that fast and it takes longer for the group of minima to reach us so we see them taking longer between events. How long? 7,379,039 km divided by the speed of light 299,792.458 km/sec is 24.61382 seconds. So in May and November when we are not moving towards or away from Algol - the period seems constant. It is our rapid movement towards or away from the events in August and February that causes the timing differences."
I assume that light is passing the earth at c when the earth isn't moving towards or away from Algol.
In February the earth is moving away from Algol and the time between the eclipses is 2.8675875347 days and the light is passing the earth at 186,265 mi/sec.
In May and November the earth is not moving towards or away from Algol and the time between eclipses is 2.867321 days and the light is passing the earth at 186,282 mi/sec.
In August the earth is moving towards Algol and the time between eclipses is 2.8670608912 days and the light is passing the earth at 186,299 mi/sec.
Thank you so much!
You are welcome
thanks
Sir, the 2nd question of muon in descriptive questions ,,,,the cause behind the question that "at what altitude does muon decay" can't understand.....if you describe this in comment box or your video description.....its become too helpful 🙏....so sir plz kindly give that
Ok, fine. Let me look into it. One question? Do you think if I make more videos on the question, answer of Special Relativity, will it be useful?
The elapsed time for a process depends on which observer is measuring it. Foe example, the time measured by the astronaut is smaller than the time measured by the earthbound observer . The time elapsed for the same process is different for the observers, because the distance the light pulse travels in the astronaut’s frame is smaller than in the earthbound frame.
Cosmic ray particles that continuously rain down on Earth from deep space. Some collisions of these particles with nuclei in the upper atmosphere result in short-lived particles called muons. The half-life (amount of time for half of a material to decay) of a muon is 1.52 μs when it is at rest relative to the observer who measures the half-life. This is the proper time interval Δτ.
This short time allows very few muons to reach Earth’s surface and be detected if Newtonian assumptions about time and space were correct. However, muons produced by cosmic ray particles have a range of velocities, with some moving near the speed of light. It has been found that the muon’s half-life as measured by an earthbound observer ( Δt ) varies with velocity exactly as predicted by the equation Δt=γΔτ.
The faster the muon moves, the longer it lives. We on Earth see the muon last much longer than its half-life predicts within its own rest frame. As viewed from our frame, the muon decays more slowly than it does when at rest relative to us. A far larger fraction of muons reach the ground as a result.
Thank you so much
Welcome. You can also look into this video of Special Relativity
ua-cam.com/video/14Q7pyVfD0E/v-deo.html
@4:00 you say 1/1 = 0 ... that hasn't been true since grade school!
Yes, very true. That's a mistake. Sorry for that. How is the overall video ?
@@physicsforstudents yes sir the video is very informative.
But I confused due to this mistake.
@@mainakkoley8691 Welcome. I hope now you it is fine.
@@physicsforstudentshow can u do this mistake sir. It's so basic. 1/1=1. Unbelievable. That a highly intellect person did this mistake
11:02 sir , it should be 10^(-31).
A mistake sir.
Yes. Sorry for that. Thank you for pointing out.