Hi im watching your vid in KOREA This vid and other MATH vids are sooooooo useful to me !!!! I really want to tell u that i always think really thanks to ur upload. Thanks !!!!!!!!! FOREVER!!!!! YOU'RE THE BEST TEACHER
hey, dude, I didn't have the test but I have a question. I was wondering when you do "a squared+ b squared = C squared", does c always equal the hypotenuse?
Mario suggested I put my problem here. So, my son & I are having difficulty graphing a tan function that goes like this: y= tan (1/3 - pi/4)+2. We have the period - 3pi, the phase shift 3pi/4 (to the right) and the vertical shift is 2up. We just can't seem to figure out where to start the graph. If we take 3pi/4 and add the 3pi to it, it's 3&3/4pi, right? That's the end (on the right), but what do we start with on the left end? We really struggle figuring out the asymptotes. Any help would be appreciated.
Hi there! I tried graphing this too but could not figure it out, from my understanding, this graph would not have the classic, curved "s" shape of a tan graph, instead it would be a single point. This is cause in the equation: y= tan (1/3 - pi/4)+2, we do not have a "x" variable, instead we only have constants, so we can put this entire equation into a calculator and get an answer, (which is roughly 1.514...) For example if we did have an "x" variable, take the equation y= tan (x/3 - pi/4)+2, then we would have the classic "s" shaped graph. Why is this? because when we have a tan graph with a variable, we are typically dealing with a function that maps each x value to a corresponding y value, resulting in a curve that exhibits the characteristic "s" shape of the tangent function. You can put ur equation into a graphing calculator such as desmos, and then try including an "x" variable and note the difference yourself! so to summarize a tan function with a variable "x" will have the classic (curved- "s" looking shape) of a tan graph whereas, when there are no variables, but only constants, we have a single answer, graphically this means no curved shape, but a single point on the graph representing that single answer. Hope this helped!
actually, (just to clarify a bit more) this graph would be a straight line - horizontally, from the point (0, 1.514...) again i do recommend graphing this in a graphical calculator, such as desmos yourself it really helps visualize what is going on, Have a great day!
Are you still getting notifications on your videos? I'm stuck on a problem graphing a tan function and I just can't figure out where to start my graph. Can you help?
I’d recommend posting your question here and hopefully someone in our awesome community here can comment and help…it’s often hard to explain via a short comment but I’d recommend checking into some of my other videos on graphing tangent as well as the other trig functions …I have quite a few of them up on the channel.
Hi im watching your vid in KOREA
This vid and other MATH vids are sooooooo useful to me !!!!
I really want to tell u that i always think really thanks to ur upload.
Thanks !!!!!!!!! FOREVER!!!!! YOU'RE THE BEST TEACHER
Glad you like my videos and that they are helping you Heilee!
Great video! Your methods make sense! Thanks!
Glad you liked my video George!
Hey, what do you do if the question gives u a domain?
Why did you go left one and up two on 3:45? Thanks.
This more recent video I did may help you more:
How to Graph Tan and Cot (2 Methods)
ua-cam.com/video/JsQ5-cLHXj0/v-deo.html
Thank you, really helpful :)
Really nice video, thanks
Your welcome! Glad you liked the video!
hey, dude, I didn't have the test but I have a question. I was wondering when you do "a squared+ b squared = C squared", does c always equal the hypotenuse?
When you have a right triangle with a right angle. Yes c is always the hypotenuse.
okay thx
Thank you 🙏
You’re welcome 😊
Mario suggested I put my problem here. So, my son & I are having difficulty graphing a tan function that goes like this: y= tan (1/3 - pi/4)+2. We have the period - 3pi, the phase shift 3pi/4 (to the right) and the vertical shift is 2up. We just can't seem to figure out where to start the graph. If we take 3pi/4 and add the 3pi to it, it's 3&3/4pi, right? That's the end (on the right), but what do we start with on the left end? We really struggle figuring out the asymptotes. Any help would be appreciated.
Hi there!
I tried graphing this too but could not figure it out,
from my understanding,
this graph would not have the classic, curved "s" shape of a tan graph, instead it would be a single point.
This is cause in the equation: y= tan (1/3 - pi/4)+2, we do not have a "x" variable, instead we only have constants, so we can put this entire equation into a calculator and get an answer, (which is roughly 1.514...)
For example if we did have an "x" variable, take the equation y= tan (x/3 - pi/4)+2, then we would have the classic "s" shaped graph.
Why is this?
because when we have a tan graph with a variable, we are typically dealing with a function that maps each x value to a corresponding y value, resulting in a curve that exhibits the characteristic "s" shape of the tangent function. You can put ur equation into a graphing calculator such as desmos, and then try including an "x" variable and note the difference yourself!
so to summarize a tan function with a variable "x" will have the classic (curved- "s" looking shape) of a tan graph whereas, when there are no variables, but only constants, we have a single answer, graphically this means no curved shape, but a single point on the graph representing that single answer.
Hope this helped!
actually, (just to clarify a bit more) this graph would be a straight line - horizontally, from the point (0, 1.514...)
again i do recommend graphing this in a graphical calculator, such as desmos yourself it really helps visualize what is going on,
Have a great day!
Are you still getting notifications on your videos? I'm stuck on a problem graphing a tan function and I just can't figure out where to start my graph. Can you help?
I’d recommend posting your question here and hopefully someone in our awesome community here can comment and help…it’s often hard to explain via a short comment but I’d recommend checking into some of my other videos on graphing tangent as well as the other trig functions …I have quite a few of them up on the channel.
Thanks! I'll try. It's difficult without posting a photo. @@MariosMathTutoring
确实讲的好