Drawing free body diagrams in a bunch of orientations and highlighting exactly what section we are analyzing in each view is immensely helpful. This video is SHEAR excellence. Thank you so much! I subscribed!
Just one word. Excellent. If prior scientist or expert were alive they will be forsure proud of you. I am from civil engineering and read this concept all over where but like this manner i was not able to clear. Just so pin point. A big big thanks to you sir.
Literally sir, 1st time I watched your video and i am now very very very impressed and satisfied with your method of teaching and explanation. Thank you so much...
I have never ever seen such a wonderful explanation of very tough concept. You are great and you have very high quality teaching skill.👌👌 Hope we will work together in future.
Amazed by the kind of explanation, I was trying to understand this topic for so long but couldn't as other videos were confusing and not fully explanator, A big thumbs up to you 👍
I know I have already commented, but your style of teaching is excellent. Revising each concept after the introduction of a new one is a very, very critical way to imbibe full understanding of the concept. I never thought I was good at SoM, but you've cleared concepts like no one has ever been able to, thank you
Hats off to your dedication. You can even make a backbencher understand this concept. Keep it up! And keep making videos on difficult topics. I have a request if you can make some videos on aerospace concepts too involving strength of materials, FEM
Excellent boss👍👍 plzz make our concepts more clear by uploading on free platform who can't afford the lectures from websites. It's a humble request to u sit
An excellent video, thank you. I just have one query. When you show the 15N example as the shearing force running length ways, you say that the complimentary shear is also 15N. I do not think this is the case. The shear flow is given by q = SAY/I. So the value of the shear flow at a distance "x" from the free edge would be q = S(xt)Y/I. But if you integrate underneath that it would be the area of a triangle, (1/2)(q)(x). So I think in this case the complimentary shear would be 7.5N. Also, consider that it is not truly complimentary in that there is a free edge along the length. What do you think? Thank you
if we did analysis for a simply supported beam then direction of shear flow in the web would not match the direction of shear stress in any stress element on the vertical plane
Nicely explained about the sear flow, sir. But what is the shear centre?? I clicked the video based on the title 'Concept of shear centre'. Please be precise on the title at the least.
GATE 2020 Answer for this question is 0 but in the solution of coaching centers is 5..... Plz Solve this by making a video on this ... Thanks ......... A steel part with surface area of 125 cm2 is to be chrome coated through an electroplating process using chromium acid sulphate as an electrolyte. An increasing current is applied to the part according to the following current time relation:
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Drawing free body diagrams in a bunch of orientations and highlighting exactly what section we are analyzing in each view is immensely helpful. This video is SHEAR excellence. Thank you so much! I subscribed!
Proud to be a subscriber of exergic channel ...even I am from civil engineering background...I am always eager to watch ur lectures 🙏🙏
Just one word. Excellent. If prior scientist or expert were alive they will be forsure proud of you.
I am from civil engineering and read this concept all over where but like this manner i was not able to clear. Just so pin point.
A big big thanks to you sir.
At a young age what kind of explanation this gentleman is providing excellent and amazing .Keep it up.
Impressed by this lecture..Much thanks to you Chandresh Sir.
A sheer flow of concept right into the mind. Simply amazing!
As Usual One more Well explained Concept. Kudos
I can watch this guy explaining things all day long! Greetings from morocco
you too preparing fr gATE
@@skp7230 nope im studying engineering in my country
@@HussamJihaz best of luck for your upcoming exam buddy, lets make our life worth living ...support from India
@@skp7230 for you too buddy thank you!!!
Literally sir, 1st time I watched your video and i am now very very very impressed and satisfied with your method of teaching and explanation.
Thank you so much...
As usual your explanation and clearance of concepts is unique.
Sir Plz bring the lectures everyday everyone is eager for watching . Thank you sir ❤
39:38 Doubt cleared ✌️thanks
Completely understood the concept Thanks what a explanation ! Mind Blowing
I have never ever seen such a wonderful explanation of very tough concept.
You are great and you have very high quality teaching skill.👌👌
Hope we will work together in future.
Sir you are excellent teacher. You have very deep understanding of the subject. I have no words to say thanks to you 🙏🙏🙏❤️❤️❤️❤️
This is definitely the best video on this topic!!!
Thank you so much!!🙏
even medical students will understand this concept. What an explanation. Huge appreciation for giving us such quality education
I thought this video was very slow and lengthy, but after i watched it completely its totally worth it💯.
you have been a game changer for engineering students!
he he boi
@@prathammaskara4106
Was wondering about this concept, from where those shear flow lines came, i could not find the explaination anywhere, finally its clear now.
Sir, your explanation is superb.... This is the best lecture on Shear flow that I ever seen..
Amazed by the kind of explanation, I was trying to understand this topic for so long but couldn't as other videos were confusing and not fully explanator, A big thumbs up to you 👍
I know I have already commented, but your style of teaching is excellent. Revising each concept after the introduction of a new one is a very, very critical way to imbibe full understanding of the concept. I never thought I was good at SoM, but you've cleared concepts like no one has ever been able to, thank you
Glad to know that!
already completed in course. great explanation of complete topic
This video helped me greatly to clear my concept, such an excellent video!
Great Explantion From Very Basics 👌🏻💙
tum madeeasy wale sudhar jao nhi toh dukan band ho jayegi .....
@@digendrasingh8518 😂😂😂
Hats off to your dedication. You can even make a backbencher understand this concept. Keep it up! And keep making videos on difficult topics. I have a request if you can make some videos on aerospace concepts too involving strength of materials, FEM
Excellent boss👍👍 plzz make our concepts more clear by uploading on free platform who can't afford the lectures from websites. It's a humble request to u sit
Very good explanation man thank you !
When you care about the concept and understanding, not about the syllabus 🤘🤘
I have the same issue.
An excellent video, thank you. I just have one query. When you show the 15N example as the shearing force running length ways, you say that the complimentary shear is also 15N. I do not think this is the case. The shear flow is given by q = SAY/I. So the value of the shear flow at a distance "x" from the free edge would be q = S(xt)Y/I. But if you integrate underneath that it would be the area of a triangle, (1/2)(q)(x). So I think in this case the complimentary shear would be 7.5N. Also, consider that it is not truly complimentary in that there is a free edge along the length. What do you think? Thank you
Very nicely explain
Your efforts are visible
best way of teaching. thank u sir
Maaza aa gya .... isse bolte hai concept smjhana 😊 bro banate rahana videos
I am form Pakistan but actually sir your teaching method wow fantastic your explanation can understand easily by everyone.
Very good approach
Sir aap ne bahut awesome padhaya hai 🙏🙏👌
Neatly cleared concept of shear flow.thanks❤️
Beautifully explained....
I appreciate your explanation.Thank you
Fantastic explanation. Hats off
Ecstatic teacher...❤️😘😘...Superb Exploration it was..
Ultra hd lecture 😎,every detail covered
Thank you
Very useful content
RECOMMENDED
Thank you very much sir. Great work.
Berry good explanation sirji🙏🏼🙏🏼🙏🏼
Superb👍
Beautiful ♥️
very well explained ,thank you sir
if we did analysis for a simply supported beam then direction of shear flow in the web would not match the direction of shear stress in any stress element on the vertical plane
21:01 the force should act parallel and opposite to keep the body in equilibrium? But why it should be perpendicular?
You are my hero!!!
YOU ARE A LEGEND
Excellent
Visualization makes content crystal clear.....no need animation, just awesome....very conceptual explaination
Love from civil❤️
Very nice explained
Nicely explained about the sear flow, sir. But what is the shear centre?? I clicked the video based on the title 'Concept of shear centre'. Please be precise on the title at the least.
Best lecture ever
Sir why is the shear distribution in flange also in vertical direction
Sir video solutions available in Exergic Question Bank?? Please reply.
No words to express my appreciation and gratitude for this excellent video. I hope your channel reaches great heights soon.
thanks too much
Thank you so much sir ❤️🙌🏻
From where this man came ??? Even IIT's GATE paper setters may not know the real sense of concepts......
Is shear center full concept is finished or some is left?
Sir when will the additive manufacturing lectures be uploaded in the new syllabus additions video course?
Sir did you provide class for mathmatics only ?that is subject wise class
Sir, how F will act towards larger value F1... For equilibrium it should act towards F2 which is smaller🤔!!
Why always blue shirt 💗💗💗💗
@@uppalapativenkatsatyasrava8766 ammababoiii...
Please provide video on Compressible fluid flow.... Thanks in advance
Hey bro you are from iit
@@swapnilsurushe6465 No bro
...
Please upload the FLTs as soon as possible
Nailed it
umm, but where is shear centre? Wasn't that going to be explained here? :\
Sir, what is shaer centre then?
GATE 2020 Answer for this question is 0 but in the solution of coaching centers is 5..... Plz Solve this by making a video on this ... Thanks .........
A steel part with surface area of 125 cm2
is to
be chrome coated through an electroplating
process using chromium acid sulphate as an
electrolyte. An increasing current is applied to
the part according to the following current time
relation:
Thanks sir
Can you provide the questions ffor newly added syllabus?
Kindly upload other imp newly added topics
thank you
thank you sir
I am not getting all the videos
I'm studying M E Engineering Design 2nd year. but now only i understood why the shear flow is like this...
No horizontal shear stresses in I section but what about other section. Like I am not getting vertical shear stresses for rectangle section.
Pls refer further videos in the course. It has been explained there how to draw these instantly for any cross section.
@@ExergicGATE I am not a paid user of course.😅
Video course of only Newly added syllabus is available on Exergic website for Rs. 499 only. Best wishes for GATE 2021 😊
Maza agya
Who teaches mathematics in exergic?
Gaurav Kumar sir
AIR-143
GATE 2018 Mechanical
yara manam di Bala bacaheya
somewhat lengthy
Sir ye koi ni samjhata jo aapne samjhaya, sab skip krdete h
Excellent explanation !!