Mesh Topology (i) No of cables needed = n*(n-1)/2 = 6*(6-1)/2 = 15 (ii) No of ports required for each device = n-1 = 6-1 = 5 (iii) No of ports required for the entire network = n * (n-1) = 6 * (6-1) = 30
Mesh topology :- 1) how many cables are needed ? A) The numbers of cables neded in mesh topology is 15
2) How many ports are needed for each device ? A) 5 ports are needed for each device. 3) How many ports are Needed in entire network? N = number of nodes =6 , number of cable = 15 number of port per node = 5 number of ports in entire network= Number of Nodes x number of port per node = 6x5 = 30 A) 30
In a mesh network topology with 6 devices, the following can be calculated: 1. Number of ports needed for each device: Each device in a mesh topology needs to be connected to every other device, so the number of ports required per device is n-1, where n is the total number of devices. With 6 devices, each device requires 6-1 = 5 ports.[1][2] 2. Total number of cables needed: In a mesh topology, the total number of cables needed is n(n-1)/2, where n is the total number of devices. With 6 devices, the total number of cables needed is 6(6-1)/2 = 15 cables.[1][2] 3. Total number of ports in the network: The total number of ports in the network is n*( n-1), where n is the total number of devices. With 6 devices, the total number of ports in the network is 6*5 = 30 ports.[1][2] In summary, for a mesh network topology with 6 devices: - Each device requires 5 ports - A total of 15 cables are needed - The total number of ports in the network is 30
In a mesh network with n devices: 1. Each device connects to n-1 other devices. 2. So, there are n(n-1) total connections if each device is counted separately. 3. But each connection is counted twice, so divide by 2 to avoid double counting. 4. Therefore, the formula for the total number of connections is n(n-1)/2.
1. Each device to be connected to every other device so if there are n devices we need (n-1) cables thus (n-1) ports. 2. For the whole mesh of n devices the total number of ports= n*(n-1) ports.(here ports are unique to a device ) 3. But each cable is shared between 2 devices the total number of cables in the mesh will be (n*(n-1))/2.
no of cables = nCp (n = no of nodes or computers , p = a cable can connect two nodes/computers at a time) so n=6 , p =2 6C2 = 6!/2!4! = 15 2. PORTS = 5 per nodes 3.. total = 30 ports
Mesh topology is simple a complete graph on paper, so that: - There are n(n-1)/2 cables, equivalent to the number of edges - Since each device will connect to every other except for itself, it has n-1 ports - Each cable has 2 ends so with e cable, we have a total 2*e port for the whole system
Number of cable: the summe of the umbers from (N-1) till 1 and the number of ports needed for each device is (N-1) followed by the number of ports needed in the whole network which we can calculate through multiplying the number of nodes in the number of the the number of ports needed for each device
We have 6 Nodes, _N=6_, so the number of ports that each device (node) needs, in order to connect to all devices separately, is N-1 (one less than the number of nodes, because device is not going to connect with itself) . _P/N = 5_ Number of total ports in this network is: Number of nodes multiplied by the number of Ports/Nodes, _TP = N * P/N = 6*5 = 30_ Finally number of cables is number of total ports divided by 2. _C = TP/2 = 15_ In the reply I will explain how we got the formula for total number of cables, _C_
This is one way, there could be other, maybe less difficult ways to determine formula for the total number of cables in mesh network. First, we know that the number of ports that one node has is: _P/N=N-1=5_ and that is also the number of cables that are connected to one node. Now let's define "inner" and "outer" cables for one node. Number of Outer cables is always equal to 2, in order to have mesh network. _OC=2_ Number of Inner Cables is: _IC= P/N - OC = P/N - 2 = 5-2 = 3_ Total number of Outer cables is equal to the number of Nodes _TOC = N = 6_ Total number of Inner cables is: _TIC = IC*N / 2 = 3*6 / 2 = 9_ (dividing by 2, because if one node is connected to other node, then there is no need for another cable to make connection again between these two nodes, it's a bidirectional network). Sum of _TOC_ and _TIC_ is the number of total number of cables, _TC_ _TC = TOC + TIC = 9+6 = 15_ If we divide _TP_ (num. of total ports) we'll get exactly the same result 30/2 = 15, and it makes sense, because it's a bidirectional network, to connect two nodes we need only one cable.
In MESH TOPOLOGY, the general formula to determine nodes cables and ports, Number of nodes = n Number of cables= n*n-1/2 Number of port per each device (NOPD)= n-1 The total num of ports (TNOP) = n*(n-1) If we have 6 devices, n=6 Number of cables= n*(n-1)/2 = 6*(6-1)/2 = 15 cables. Number of port per each device (NOPD)= n-1 = 6-1 = 5 ports of each device. The total num of ports (TNOP) = n*(n-1) = 6*(6-1) = 30 ports in entire network.
1) total numbers of cables required in mesh topology with n nodes : n(n-1)/2 Dividing by 2 bcz each wire would have been counted twice so dividing by 2 So for n=6 No. Of cables=6*5/2=15 cables ii) ports/device = (n-1) Bcz each device is connected with n-1 devices so for n=6 Ports/device= 5 p/d iii) total ports in network =n(n-1) since there are n devices with n-1 ports for n=6 There will be total 30 ports
number of computer = n = 5; (i) number of cables = n*(n-1)/2 = 15 or (n-1)+(n-2)+(n-3)+(n-4) = 5+4+3+2+1 = 15; (ii) port each device = n-1 = 4; (iii) total port = port each device * n or n(n-1) = 6*5 = 30
Given :- N=6 nodes, mesh topology Cables=(N-1) +(N-2)+(N-3)+(N-4)+.........+ Till(N-N) Cables= (6-1)+(6-2)+(6-3)+(6-4)+(6-5)+(6-6) =5+4+3+2+1+0 =15 cables #Port for one node Port =N-1 Port=5 #All ports in topology All ports=N*(N-1) All ports=6*(6-1) All ports =30 ##Formula Applicable for all mesh topology
In a mesh topology, each node is connected to every other node, creating a fully interconnected network. The number of ports and cables required can be calculated using the formula: Number of ports per node = n - 1 where "n" is the total number of nodes in the network. So, if you have 6 nodes in a mesh topology: Number of ports per node = 6 - 1 = 5 Each node will have 5 ports for connecting to the other nodes. Now, to find the total number of cables needed, you can use the following formula: Total number of cables = (n * (n - 1)) / 2 For 6 nodes: Total number of cables = (6 * (6 - 1)) / 2 = 15 So, in a mesh topology with 6 nodes, each node would have 5 ports, and a total of 15 cables would be required to fully connect the network.
For Mesh topology Suppose n nodes are there 1st node connects to n-1 nodes 2nd node connects to n-2 nodes .... nth node connects to 1 node No. cables required are (n-1)+(n-2)+(n-3)+(n-4)+......+1 = 1+2+3+......+n-1 =(n-1)*(n-1+1)/2 =(n-1)*n/2 = n*(n-1)/2
Really very useful information.. And teaching way is superb. Thank you very much sir... Really superb. I have been watching all classes.. Very useful for my upcoming exams
15 Cables/30 ports (first node use 5 cable second node use 4 cable as 1 is already counted on first, third node use 3 cable forth node use 2 cable and 4th node use 1 cable)
number of nodes =5 number of cables= 5-1+5-2+5-3+5-4+5-5=10 number of ports=5nodesx4ports for each node to connect all 4 cables of 4other nodes = 20 ports
Homework answers For 6 devices arranged in a mesh topology: ->No of cables will be= 6*(6-1)/2=15 i.e, n*(n-1)/2 ->No of ports needed for each device= 6-1=5 i.e, n-1 ->Total no of ports in the network= 5*6=30 i.e, n*(n-1)
Ring topology have unidirectional cable..if it is possible for using bidirectional link, it will easly transfer a data to nearest one.. it does not transfer data to some nodes and then it reached to receiver node. processing speed also increase by this... I have this query while listening
Nodes=N No. Of ports per device(NOP)=N-1 Total Number of Ports(TNOP)=N×NOP No. Of Cables=(N×NOP)/2 SO if N=6 NOP=6-1=5 i) Number of cables=(N×NOP)/2 =>6×5/2=15 ii)NOP=5 iii)TNOP=N×NOP=6×5=30
Each Node has 5 port and 6 nodes = 30 Port , Cable 15 ( 2nodes have one cable , it means we need to consider only three nodes so , 3 nodes X 5 port = 15 cable ) Each device need 5 port .
Can you please explain answer for question you made on this session. Question is assuming six device are connect in mesh topology And this my answer No.of cable: 15 required No.of Ports per device is:5 ports Total No.of port in the entire network is : 30 ports Hope my answer correct.
Traffic problem can be solved using ring topology. you said that each node can send information only when it receives TOKEN. so at a time only one node is sending information through the link so no traffic problem. Please change confirm my doubt.
No. of cables = n!/(x!(n-2)!) where x is no. of ports in 1 cable only..final formula for total no. of cable for a mesh topology is n!/(2!*(n-2)!). No. of ports per device (p) is n-5. Total no. of ports is n*p. Answer: a = 15, b = 5, c = 30
Sir makaut university(west bengal) semester is going to start from 1st week of december, could you please upload the whole videos as soon as possible......please we need your help #nesoacademy #nesoacademy
In the star topology.. Why dint u consider router as a node.. Since it is also a node.. If it is considered.. Then the whole explanation changes..? Correct me if im wrong
answer for last question A) 15 if we have 5 nodes the cables will be 4 + 3 + 2 +1 = 10 general formula to find the sum of n consecutive digits is (n*(n+1))/2 so = (4*(4+1))/2=10 if we have 6 nodes the cables will be 5 + 4 + 3 + 2 + 1 = 15 if we have n nodes the cables will be (n*(n-1))/2 explanation : here n is number of nodes - 1, lets take it n-1 general formula to find the sum of n consecutive digits is (n*(n+1))/2 substituting n with n-1 we get ((n-1)*(n-1+1))/2 = ((n-1)*n)/2 =(n*(n-1))/2 B) 5 the number of ports in each device is 5 since there are 6 nodes including itself then the ports in each device will be = total nodes - 1 = 6-1=5 C) 30 number of ports are = number of ports in one node * number of nodes since there are 6 nodes then there will be 5 ports in each node so the answer will be 5*6=30 ports
No. of cables = N*(N-1)/2 No. of ports per device = N - 1 No. of ports = N*(N-1) N= 6 No. of cables = (6*5)/2 = 15 cables No. of port per device = 6-1 = 5 No of ports = 6*5 = 30 port
It depends on your objective, if you can spend a lot of money and want high speed and an anti-slip system, as well as high security, the best option is mesh, but if dont care about he security and dont have soo much money the ring is the best in my vision
No of cables =n*(n-1)/2
Ports for each device=n-1
No of ports in entire network=n*(n-1)
mention which topology it is
@@damareswaramaddepalli9714 mesh
They are practically proven.
Thank you
Kindly explain your answer Reddy
Mesh Topology
(i) No of cables needed = n*(n-1)/2
= 6*(6-1)/2
= 15
(ii) No of ports required for each device = n-1
= 6-1
= 5
(iii) No of ports required for the entire network = n * (n-1)
= 6 * (6-1)
= 30
Jio sher
8/136. A long road ahead. Good luck fellow internet traveler.
Good luck for you too, my noble one.
@@РодригоТаварес have you completed it buddy
Mesh topology :-
1) how many cables are needed ?
A) The numbers of cables neded in mesh topology is 15
2) How many ports are needed for each device ?
A) 5 ports are needed for each device.
3) How many ports are Needed in entire network?
N = number of nodes =6 , number of cable = 15 number of port per node = 5
number of ports in entire network= Number of Nodes x number of port per node = 6x5 = 30
A) 30
Can you please show how you got the formula for Part 1?
1)15 cables
2)5 ports for each device
3)30 ports in the entire network
Thanks for good explanation.
Best computer networking tutorials....Thanks for such fantastic vedios.
Suppose,number of node= n
Then,
1)no of cables = n*(n-1)/2
2)ports per device= (n-1)
3)total ports = n * (n-1)
u r genious
all of the faculties of Neso are best..love u all & ur way of teaching
In a mesh network topology with 6 devices, the following can be calculated:
1. Number of ports needed for each device:
Each device in a mesh topology needs to be connected to every other device, so the number of ports required per device is n-1, where n is the total number of devices.
With 6 devices, each device requires 6-1 = 5 ports.[1][2]
2. Total number of cables needed:
In a mesh topology, the total number of cables needed is n(n-1)/2, where n is the total number of devices.
With 6 devices, the total number of cables needed is 6(6-1)/2 = 15 cables.[1][2]
3. Total number of ports in the network:
The total number of ports in the network is n*( n-1), where n is the total number of devices.
With 6 devices, the total number of ports in the network is 6*5 = 30 ports.[1][2]
In summary, for a mesh network topology with 6 devices:
- Each device requires 5 ports
- A total of 15 cables are needed
- The total number of ports in the network is 30
In a mesh network with n devices:
1. Each device connects to n-1 other devices.
2. So, there are n(n-1) total connections if each device is counted separately.
3. But each connection is counted twice, so divide by 2 to avoid double counting.
4. Therefore, the formula for the total number of connections is n(n-1)/2.
No of cables : 15
No of ports per devices : 5
Total no of ports in a network: 30
heyy cutie
Really we learn computer network from you sir . every content is very helpful. thanks for giving us these quality of education.
Which college bro ?
1. Each device to be connected to every other device so if there are n devices we need (n-1) cables thus (n-1) ports.
2. For the whole mesh of n devices the total number of ports= n*(n-1) ports.(here ports are unique to a device )
3. But each cable is shared between 2 devices the total number of cables in the mesh will be (n*(n-1))/2.
I am thankful to neso academy for providing such a systematic course .
no of cables = nCp (n = no of nodes or computers , p = a cable can connect two nodes/computers at a time)
so n=6 , p =2
6C2 = 6!/2!4! = 15
2. PORTS = 5 per nodes
3.. total = 30 ports
Good 👍
Mesh topology is simple a complete graph on paper, so that:
- There are n(n-1)/2 cables, equivalent to the number of edges
- Since each device will connect to every other except for itself, it has n-1 ports
- Each cable has 2 ends so with e cable, we have a total 2*e port for the whole system
So beautiful explanation... it is very helpful to students studying comp app
Number of cable: the summe of the umbers from (N-1) till 1 and the number of ports needed for each device is (N-1) followed by the number of ports needed in the whole network which we can calculate through multiplying the number of nodes in the number of the the number of ports needed for each device
By using diagonal formula n*(n-3)/2
No of cables (9+6)=15
Each node has (6-1)=5 ports
Total no of ports (6*5 ) or (15*2)=30
We have 6 Nodes, _N=6_, so the number of ports that each device (node) needs, in order to connect to all devices separately, is N-1 (one less than the number of nodes, because device is not going to connect with itself) .
_P/N = 5_
Number of total ports in this network is: Number of nodes multiplied by the number of Ports/Nodes,
_TP = N * P/N = 6*5 = 30_
Finally number of cables is number of total ports divided by 2.
_C = TP/2 = 15_
In the reply I will explain how we got the formula for total number of cables, _C_
This is one way, there could be other, maybe less difficult ways to determine formula for the total number of cables in mesh network.
First, we know that the number of ports that one node has is:
_P/N=N-1=5_
and that is also the number of cables that are connected to one node.
Now let's define "inner" and "outer" cables for one node.
Number of Outer cables is always equal to 2, in order to have mesh network.
_OC=2_
Number of Inner Cables is:
_IC= P/N - OC = P/N - 2 = 5-2 = 3_
Total number of Outer cables is equal to the number of Nodes
_TOC = N = 6_
Total number of Inner cables is:
_TIC = IC*N / 2 = 3*6 / 2 = 9_
(dividing by 2, because if one node is connected to other node, then there is no need for another cable to make connection again between these two nodes, it's a bidirectional network).
Sum of _TOC_ and _TIC_ is the number of total number of cables, _TC_
_TC = TOC + TIC = 9+6 = 15_
If we divide _TP_ (num. of total ports) we'll get exactly the same result 30/2 = 15, and it makes sense, because it's a bidirectional network, to connect two nodes we need only one cable.
@@opst1704 Thank you so much for amazing explanation 🙏🙏
In MESH TOPOLOGY, the general formula to determine nodes cables and ports,
Number of nodes = n
Number of cables= n*n-1/2
Number of port per each device (NOPD)= n-1
The total num of ports (TNOP) = n*(n-1)
If we have 6 devices, n=6
Number of cables= n*(n-1)/2
= 6*(6-1)/2 = 15 cables.
Number of port per each device (NOPD)= n-1
= 6-1 = 5 ports of each device.
The total num of ports (TNOP) = n*(n-1)
= 6*(6-1) = 30 ports in entire network.
1) total numbers of cables required in mesh topology with n nodes :
n(n-1)/2
Dividing by 2 bcz each wire would have been counted twice so dividing by 2
So for n=6
No. Of cables=6*5/2=15 cables
ii) ports/device = (n-1)
Bcz each device is connected with n-1 devices so
for n=6
Ports/device= 5 p/d
iii) total ports in network
=n(n-1)
since there are n devices with n-1 ports
for n=6
There will be total 30 ports
number of computer = n = 5;
(i) number of cables = n*(n-1)/2 = 15 or (n-1)+(n-2)+(n-3)+(n-4) = 5+4+3+2+1 = 15;
(ii) port each device = n-1 = 4;
(iii) total port = port each device * n or n(n-1) = 6*5 = 30
I noticed how the number of views decrease as we progress with the course
Unfortunately most don't go the distance. This happens with in-person classes as well how their attendance drops overtime.
@@codingoftheuniverse8355 yup
@@codingoftheuniverse8355 Yeah
Given :- N=6 nodes, mesh topology
Cables=(N-1) +(N-2)+(N-3)+(N-4)+.........+ Till(N-N)
Cables= (6-1)+(6-2)+(6-3)+(6-4)+(6-5)+(6-6)
=5+4+3+2+1+0
=15 cables
#Port for one node
Port =N-1
Port=5
#All ports in topology
All ports=N*(N-1)
All ports=6*(6-1)
All ports =30
##Formula Applicable for all mesh topology
Formula : n(n-1)/2
NO OF CABLES : N
NO OF CABLES : 15
NO OF PORTS : N
NO OF PORTS { NOPD } : 5
NO OF PEN : 30
1. nC2 : n = no. of devices
2. n - 1 ports per device
3. n * n-1 ports in the network
No. of cables needed = n*(n-1)/2
No. of ports required for each device = (n-1)
No. of ports in entire network = n*(n-1)
No of nodes = 6
No of cables = 15
No of port per device = 5
Total No of port in Mesh topology = 30
In a mesh topology, each node is connected to every other node, creating a fully interconnected network. The number of ports and cables required can be calculated using the formula:
Number of ports per node = n - 1
where "n" is the total number of nodes in the network.
So, if you have 6 nodes in a mesh topology:
Number of ports per node = 6 - 1 = 5
Each node will have 5 ports for connecting to the other nodes. Now, to find the total number of cables needed, you can use the following formula:
Total number of cables = (n * (n - 1)) / 2
For 6 nodes:
Total number of cables = (6 * (6 - 1)) / 2 = 15
So, in a mesh topology with 6 nodes, each node would have 5 ports, and a total of 15 cables would be required to fully connect the network.
fruitful videos ! thanks sir, i hope you will discuss all the layers at the end of December.
For Mesh topology
Suppose n nodes are there
1st node connects to n-1 nodes
2nd node connects to n-2 nodes
....
nth node connects to 1 node
No. cables required are (n-1)+(n-2)+(n-3)+(n-4)+......+1
= 1+2+3+......+n-1
=(n-1)*(n-1+1)/2
=(n-1)*n/2
= n*(n-1)/2
Excellent teaching. Love the way you explained the topologies... Thanks a lot Neso Academy for this networking course...
Total no of cables = Σ (n-i) from i = 1 to n, where n is no. of nodes
ports for each device = n-1
total no of ports = n(n-1).
Really very useful information.. And teaching way is superb. Thank you very much sir... Really superb. I have been watching all classes.. Very useful for my upcoming exams
no of nodes,n=6;
No of cables=nc2=6c2=15
Ports for each device=n-1=6-1=5
No of ports in entire network=n*5=6*5=30
Nodes n,
Cables 2n,
Each device has ports n-1,
Total number of ports n(n-1)
15 Cables/30 ports (first node use 5 cable second node use 4 cable as 1 is already counted on first, third node use 3 cable forth node use 2 cable and 4th node use 1 cable)
You are very talented
next level of teaching
number of nodes =5
number of cables= 5-1+5-2+5-3+5-4+5-5=10
number of ports=5nodesx4ports for each node to connect all 4 cables of 4other nodes = 20 ports
No of nodes = n = 6
No of cables : nC2 = 15
No of ports : 5x6 = 30
Homework answers
For 6 devices arranged in a mesh topology:
->No of cables will be= 6*(6-1)/2=15 i.e, n*(n-1)/2
->No of ports needed for each device= 6-1=5 i.e, n-1
->Total no of ports in the network= 5*6=30 i.e, n*(n-1)
No. Of cable n(n-1)/2
No of port/device N
No .of port in network N²
Answer:
Cables = 15
Ports for each device = 5
Ports in entire network = 30
i) No. of cables: (n*(n-1))/2 = (6*(6-1))/2 = 15
ii) Total no. of ports: 6*5 = 30
iii) No. of ports per device = 5
i extreamly love the way,u teach!!!!!!
Thankyou for so much useful video sir
numbers of cables for each node = n-1
number of cables for entire system= 2n+2
number of nodes for the entire = 5n
Very good explaination sir
Ring topology have unidirectional cable..if it is possible for using bidirectional link, it will easly transfer a data to nearest one.. it does not transfer data to some nodes and then it reached to receiver node. processing speed also increase by this... I have this query while listening
Nodes=N
No. Of ports per device(NOP)=N-1
Total Number of Ports(TNOP)=N×NOP
No. Of Cables=(N×NOP)/2
SO if N=6
NOP=6-1=5
i) Number of cables=(N×NOP)/2 =>6×5/2=15
ii)NOP=5
iii)TNOP=N×NOP=6×5=30
Number of cables=n*(n-1)/2
Ports for each device=n-1
Number of ports in entire topology=n*(n-1)
Thank you sir 😁
According to me,
Cables - 15
Port for each device - 5
Total ports - 30
No. Of ports required per device will be (N-1) = 6-1= 5
Total no. Of ports = N(N-1) = 6*5=30
Toral no. Of cables required = N(N-1)/2= 6*5/2= 15
No.of nodes 6
No of cables 15
No of ports in single device 4
Total no. Of ports in the whole network is 4×6=24
Each Node has 5 port and 6 nodes = 30 Port ,
Cable 15 ( 2nodes have one cable , it means we need to consider only three nodes so , 3 nodes X 5 port = 15 cable )
Each device need 5 port .
a) No of cables =n*(n-1)/2
=15
b) Ports for each device=n-1
= 5
c) Number of ports in entire network=n*(n-1) = 30
Cool
Such a huge fan of your after watching video even i don't see u
Sir plzzzz make the playlist as early as possible
.....thank you
Number of Cables is = 15 cables
Number of Ports per device = 5 ports
Total Number of Ports = Number of ports per device x 6 = 5 x 6 = 30 Ports.
let no of nodes=n
total no of cables required= nC2
no of ports/node= n-1
total no of ports= n(n-1)
please keep making it, I check the channel everyday for new videos
k=1,2,3,4,5,......N
no. of cables =(n-k)+(n-(k+1))+.......until (n-(k+N) equal to 0
ports for each device is n-1
total ports is n*(n-1)
No of cables = n(n-1)/2
No of ports/each node = n-1
Total no of ports = n(n-1)
MESH TOPOLOGY
1. NOC: nC2/2
2. NOP/device: n-1
3. TNOP: n*(n-1)
Can you please explain answer for question you made on this session.
Question is assuming six device are connect in mesh topology
And this my answer
No.of cable: 15 required
No.of Ports per device is:5 ports
Total No.of port in the entire network is : 30 ports
Hope my answer correct.
Mesh Topology :
n=6 ; r=2;
Combinations Formula:
no. of cables = 6!/4!*2! = 6*5/2 = 15 cables in mesh topology network.
no. of ports = 5 ports per device * 6 devices = 30 ports in network.
.
.
.
.
n*(n-1)/2 cables
n-1 ports for each node
n*(n-1) total ports
Traffic problem can be solved using ring topology. you said that each node can send information only when it receives TOKEN. so at a time only one node is sending information through the link so no traffic problem. Please change confirm my doubt.
When a network is in traffic, that means, a system in a node must wait for sending/receiving signal. This normally occurs in Ring topology.
No. of cables = n!/(x!(n-2)!) where x is no. of ports in 1 cable only..final formula for total no. of cable for a mesh topology is n!/(2!*(n-2)!). No. of ports per device (p) is n-5. Total no. of ports is n*p.
Answer: a = 15, b = 5, c = 30
Homework :
1. cables needed = 15
=N = N(N-1)/2
=N = 6(6-1)/2
=N = 15
2. ports needed per device = 5
NOP = N-1
NOP = 6-1
NOP = 5
3. total ports of the network = 30
TNOP = NxNOP
TNOP = 6x5
TNOP = 30
Very well explained.. Thank you sir.
MESH TOPOLOGY
N is the no. of nodes
No. Of cables = (N-1) + (N-2) + ... + 2 + 1
NOP/D = N-1
No of ports in entire network =
NOP/ D * N
no.of . cables = 6
no.of . ports required for each device is = 3
no . of . ports required for entire network is = 18
Sir makaut university(west bengal) semester is going to start from 1st week of december, could you please upload the whole videos as soon as possible......please we need your help #nesoacademy #nesoacademy
no of cables=n*(n-1)/2=15;
no of ports for each =n-1=5;
total ports =(n*(n-1))=5*6=30;
no. of nodes = n
no. of ports per node = n-1
Total no. of ports in the network = n*(n-1)
No of cables = n*(n-1)/2
(Thank me later........)
(i) Ncables = Σ i from i=1 to N-1 (for N devices) = N(N-1)/2 N=6 ⇒ Ncables = 15
(ii) Nports = N-1 (for N devices) N=6 ⇒ Nports = 5
(iii) Nports_all = Nports × N = N(N-1) (for N devices) N=6 ⇒ Nports_all = 30
PS: (i) can also be Ncables = (N choose 2)
Awesome explanation
Sir when you going to add remaining tutorial
Thanks its very excellent explanation
THANK YOU
Thank you Mr
In the star topology.. Why dint u consider router as a node.. Since it is also a node.. If it is considered.. Then the whole explanation changes..? Correct me if im wrong
1) 15 cables
2) 5 ports/device
3) 30 ports in entire network
Amazing
1.15cables
2.5 ports needed for each devices
3.30 ports entire networks
Is it correct 🤔🤔🤔
1)-15
2)-5
3)-30
Number of cables is 15
Number of ports for each device is 5
Total number of ports for entire network is 30
Thanks
General formula:
No of cables- n*(n-1) /2
Ports per cable- n-1
Total ports in n/w- n*(n-1)
Respective answer for 6 node mesh:
15
5
30
No.of cables=15
No.of ports/device=5
No.of total ports=30
answer for last question
A) 15
if we have 5 nodes the cables will be 4 + 3 + 2 +1 = 10
general formula to find the sum of n consecutive digits is (n*(n+1))/2
so = (4*(4+1))/2=10
if we have 6 nodes the cables will be 5 + 4 + 3 + 2 + 1 = 15
if we have n nodes the cables will be (n*(n-1))/2
explanation : here n is number of nodes - 1, lets take it n-1
general formula to find the sum of n consecutive digits is (n*(n+1))/2
substituting n with n-1 we get ((n-1)*(n-1+1))/2 = ((n-1)*n)/2
=(n*(n-1))/2
B) 5
the number of ports in each device is 5 since there are 6 nodes including itself
then the ports in each device will be = total nodes - 1 = 6-1=5
C) 30
number of ports are = number of ports in one node * number of nodes
since there are 6 nodes then there will be 5 ports in each node so the answer will be
5*6=30 ports
No.of devices=6
No.of cables=15
Ports needed for each device=5
Ports in entire network......5×6=30
No. of cables = N*(N-1)/2
No. of ports per device = N - 1
No. of ports = N*(N-1)
N= 6
No. of cables = (6*5)/2 = 15 cables
No. of port per device = 6-1 = 5
No of ports = 6*5 = 30 port
Ans1) 15 cables
Ans2) 5 ports for each device
Ans3) 30 ports in the entire network
Which topology is best amongst the all in a connection of more than thousand concurrent users
It depends on your objective, if you can spend a lot of money and want high speed and an anti-slip system, as well as high security, the best option is mesh, but if dont care about he security and dont have soo much money the ring is the best in my vision
Star topology is best commonly use this topology
No of cables 15
No of ports 30
Tq sir