Задание 24 из демоверсии ЕГЭ Информатика 2025. Самый сложный тип с арифметическим выражением

[@analitiqtutor]

Решение: github.com/blacksmithalex/ege_computer_science/blob/main/КЕГЭ/24/17878.py
def solution_linear(a):
flag_operator = False
flag_leading_zero = False
flag_prev_zero = False
count, countm = 0, 0
for x in a:
if x == '0':
if flag_operator or count == 0:
flag_leading_zero = True
if not flag_leading_zero or flag_operator:
count += 1
countm = max(count, countm)
else:
count = 1
flag_prev_zero = True
flag_operator = False
elif x in '6789':
if flag_leading_zero:
count = 1
else:
count += 1
countm = max(count, countm)
flag_leading_zero = False
flag_operator = False
flag_prev_zero = False
else:
if not flag_operator and count != 0:
count += 1
flag_operator = True
else:
count = 0
flag_leading_zero = False
flag_prev_zero = False
return countm
file = open('24_17878.txt')
a = file.readline()
file.close()
print(solution_linear(a))