agar origin se upar throw kare :- eg. (0, Y) then, eq. of trajectory main change hoga - (y-Y) = x(tan∅) [1-x/R] where, R->range and ∅ ->angle. agar origin se niche throw kare :- eg. (0, -Y) then, eq. of trajectory main change hoga - (y +Y) = x(tan∅) [1-x/R] where, R->range and ∅ ->angle. at last solve the equation with y^2=4ax with anyone of the chosen Case. 😊
Easy question only to satisfy the equation of trajectory with the parabola eqn
Thank u saurav bhaiya...ye me solve kr ia (after u write Eq , of tragectory😅). ❤❤ love this series..plz continue🙏🙏
Sir what if waha lowest point ke bajaye kuch upper ya niche point hota then how we will do that question
agar origin se upar throw kare :- eg. (0, Y) then, eq. of trajectory main change hoga -
(y-Y) = x(tan∅) [1-x/R] where, R->range and ∅ ->angle.
agar origin se niche throw kare :- eg. (0, -Y) then, eq. of trajectory main change hoga -
(y +Y) = x(tan∅) [1-x/R] where, R->range and ∅ ->angle.
at last solve the equation with y^2=4ax with anyone of the chosen Case. 😊
@@Aman-ru6jl okk thanks aman thinking the same as you just need the suggestion to check if i am thinking wrong or right
@@mr.xedits5979 most welcome
Bhaiya aese hi questions Lao taki hum adv. Uda de