4:54 , it doesn't mean you've gone wrong, it just shows that there isn't a bn , so the equation would be an^2+c. I have come across a question where the answer is a quadratic but is in the form of n^2+c instead of n^2+bn+c
@Davey: We have found the first part of the formula is 8n^2, so we can subtract that to leave the rest which will be linear. Looking at a simpler example: 3, 8, 15, 24,...The differences go up in 2's, so we know that the formula starts with n^2, so we subtract 1, 4, 9, 16 respectively to leave 2, 4, 6, 8 and can see that the linear formula for these numbers is 2n. So now we can put the two formulas together to get n^2 + 2n
Thank you do much i didnt learned anything at all but dont worry im subscribe and i like you because all your other vedios helped me and you helped makr my teacher proud by me
You could try it yourself: what happens with the simplest example: 1, 4, 9, 16, 25,...What are the second differences? Then try multiplying up by an integer, say 10, so you get 10, 40, 90, 160, 250,...What are the second differences? Can you answer your question?
Got a sequence that involves n^3 and took me 4 difference of sum to get same ones... how would I convert the amount of times it takes to get a common difference to the power that I am looking for?
Maybe you will be able to work out the pattern....just try the simplest sequence of powers of 4: 1, 16, 81, 256, 625, 1296, and what is the 4th difference? Then the pattern should emerge...
If you had to find the differences 4 times before they converge, would that mean the answer should be in the form an^4 + bn^3 + cn^2 + dn + e or should it just be an^2 + bn + c? The sequence is 1, 3 ,12, 39, 120, 316, ... which makes the differences 2, 9, 27, 81, 196 and then 7, 18, 54, 115 then 11, 36, 61 then 25, 25 If it should be the first option, do I just repeat the steps again and again or is there another way to do this?
That's harder than this one....it will involve cubing, not just squaring. If you haven't looked at cubic nth term yet, try writing each number in your pattern as a product of two numbers and look at 2 patterns...
@David: Think about the sequence of square numbers: 1, 4, 9, 16, 25,... The differences are 3, 5, 7, 9,... And the differences between the differences are 2...so we divide by 2 to get the number to multiply n^2
I've been struggling with this for a full year! Thanks so much this finally makes sense!
You are so welcome!
Thaaaankkk youuu I was definitely going to fail this test thx for this explanation
@Krishna Pol: Thank you! Hope your test went well!
this helped me impress my maths teacher ty so much
@navin navin: That's great! Thank you!
Thanks I need this for my GCSE
@Blue Buddy: Thank you!
@@MathsWithJay Thanks. I needed this.... not really I'm in Year 8...
Not anymore
@@pawelpow same but your not
Same here..
The explanation was terrific!
Wonderful Job Frau Jay!
My pleasure 😊
This was so confusing to me, you made it so easy to understand, thanks for making this
You're welcome!
Thank you for sharing your knowledge! Are there similar methods to find higher degree series as well?
Yes, there are.
I must be unteachable when you put 8n² in the table and got -32 I was like how
8x2x2
watching this one night before igcse maths exam cuz none of my teachers helped... thank you for saving my life 🙏
Good luck!
helped a lot im doing IGCSE extended maths and this really did help, thank you :)
You're very welcome!
@@MathsWithJay Hello, i wanted to ask, why went finding the an, we needed to divide the 16 by 2. pls and thank you.
Edit: an^2
@@poplil3934 we apparently need to divide by 2 every time
Best explanation and step by step working of topic Thanks
You are welcome
4:54 , it doesn't mean you've gone wrong, it just shows that there isn't a bn , so the equation would be an^2+c. I have come across a question where the answer is a quadratic but is in the form of n^2+c instead of n^2+bn+c
Yes, you're right - that is another possibility
awesome your the best math like rananjum
@Anirudh: Thank you!
Great vid. Thx for the help.
@MatZio Addo: Thank you!
Why is it -8 I am so confused it was positive 8 before
@Davey: We have found the first part of the formula is 8n^2, so we can subtract that to leave the rest which will be linear. Looking at a simpler example: 3, 8, 15, 24,...The differences go up in 2's, so we know that the formula starts with n^2, so we subtract 1, 4, 9, 16 respectively to leave 2, 4, 6, 8 and can see that the linear formula for these numbers is 2n. So now we can put the two formulas together to get n^2 + 2n
@@MathsWithJay i still dont get how this makes it a minus
This helped me a lot thanks!!!
Glad it helped!
This is the second time I am watching this vid and it is still helpful
You may like to look at this: ua-cam.com/video/5iLAGcz4Vfk/v-deo.html
Best video on the topic!
Wow! Thank you!
u slayed fr fr
yw
Hello I love 💓 you’re explanation Tysm
@Afsana Rahman: You’re welcome 😊
Great vid my brudda
@Joe: Thank you!
my brudda
Thank you do much i didnt learned anything at all but dont worry im subscribe and i like you because all your other vedios helped me and you helped makr my teacher proud by me
Do you have a question about this video?
aa tysm! greatly appreciated :)
Glad it helped!
Thank you so much I need this to finish my homework
Glad I could help!
Thank you very much Jay
You are very welcome
Thank you so much ♥️
You’re welcome 😊
tomorrow i have maths exam and this topic was left out ....thanks
Most welcome 😊
Good Job thanks for you kind help and tutorial Keep it Up !😉
Thank you!
you deserve a LIKE :D
Thanks, Yasser! 😁
Thank you, helped me do my homework correctly 🎉
That's great!
Thank u so much.
You're most welcome
does it have to be divide by 2 each time? or is that only for this specific quadratic equation?
You could try it yourself: what happens with the simplest example: 1, 4, 9, 16, 25,...What are the second differences? Then try multiplying up by an integer, say 10, so you get 10, 40, 90, 160, 250,...What are the second differences? Can you answer your question?
@@MathsWithJay Thanks! This video really helped me with my school homework.
Got a sequence that involves n^3 and took me 4 difference of sum to get same ones... how would I convert the amount of times it takes to get a common difference to the power that I am looking for?
It should be 3 rows of differences to get n^3
Maths with Jay why do u divide it by 6 when it's 3, and divide by 2 when it's 2? what about n^4 ._.
Maybe you will be able to work out the pattern....just try the simplest sequence of powers of 4: 1, 16, 81, 256, 625, 1296, and what is the 4th difference? Then the pattern should emerge...
Interesting
Thank you!
im subbing.
Thank you
what if when you find the an^2 it becomes negative automatically, like -8n^2, Then is it 8n^2?
@Hari: Why would you change the sign from negative to positive?
i mean if that happened then you would have --8n^2 so it would become positive. but im not 100% sure
It doesn’t become minus, the sign was there just to signify that it is being subtracted from the other sequence
Thank you so mutch
You are welcome
What if the difference you get (when finding bn+c),is different ?
@Nadir Sajid: What is your sequence?
thank you !
You're welcome!
Do we always have divide by 2 or does it change?🤔
Always 2
Hi, how do i determine which term has the value given to me using the formula?
Solve it as an equation
Thanks
@The Real Bleach: Thank you!
Right I’ve done this for like 2 hours on the same question pretty sure I’m doing something stupid what’s the nth term for to 1, 3, 6, 10, 15, 21
This method will work....have you worked out the first stage yet?
I got -2 and +3 would that also be right?
@Annika: -2 and 3 for what?
Why do you do minus 8 instead of positive 8 for 8n^2???
At what time in the video?
ty bro
welcome!
If you had to find the differences 4 times before they converge, would that mean the answer should be in the form an^4 + bn^3 + cn^2 + dn + e or should it just be an^2 + bn + c?
The sequence is 1, 3 ,12, 39, 120, 316, ...
which makes the differences 2, 9, 27, 81, 196
and then 7, 18, 54, 115
then 11, 36, 61
then 25, 25
If it should be the first option, do I just repeat the steps again and again or is there another way to do this?
Kieran, it's the first option. You could find the coefficient of n^4 first and so on.
Thanks a lot!!!
It is really really helping me! God bless you!! 😇😇
@Alhamdulillah: Thank you!
I don’t get where you got + 2 from
At what time in the video?
What if you don't have the first 4 but instead the 2nd 3rd and 5th term only
@Ross: Have you been told what kind of sequence it is? (Linear, quadratic, ...)
@@MathsWithJayit's quadratic but don't worry i managed to solve it but thanks!
@2:32, why do we divide it by 2??
Look at the simplest quadratic sequence, the square numbers: 1, 4, 9, 16, 25,... and work out the second differences....what do you get?
I can't understand at the end that is( +2) concept .plss mam reply me
At what time in the video?
@@MathsWithJay at 5:36, i mean c=2 is come from where
-1+3=2 See ua-cam.com/video/vvayGlslby0/v-deo.html
tysm
You're welcome
Why do we make it 3n from 8n and how?
At what time in the video?
what if the diffrence of the diffrence is 0
@Hari 0: Which difference? The first or second?
What if 8n squared is negative
@Henry: Squaring would always give a positive number.
@@MathsWithJay thanks really helpful
What do you do when the differences are not the same? Plz help
Can you give an example?
@@MathsWithJay I think it's known as a cubic sequence
Do the third set of differences come out to be the same as each other?
@@MathsWithJay yes they do
Then start by dividing the common difference by 6, that will give you the coefficient of the cubed term
what if the difference is 2
@Geronima: We always divide the difference by 2. So 2/2 = 1.
How did it became -3? 5:03
We need to subtract 3 from -1 to get -4. See ua-cam.com/video/vvayGlslby0/v-deo.html
Is there a way to find the nth term of a quadratic sequence without using that formula?
A method that doesn't use a formula?
Like, a way that you can just calculate it without that formula, i learned it that way in high school but i forgot it
❤
😍
Pls can you help me out with 2,12,36,80.
That's harder than this one....it will involve cubing, not just squaring. If you haven't looked at cubic nth term yet, try writing each number in your pattern as a product of two numbers and look at 2 patterns...
Why do you divide 16 by 2
@David: At what time in the video?
2:36
@David: Think about the sequence of square numbers: 1, 4, 9, 16, 25,... The differences are 3, 5, 7, 9,... And the differences between the differences are 2...so we divide by 2 to get the number to multiply n^2
@@MathsWithJay Oh thanks
why n=4?
At what time in the video?
@@MathsWithJay 5:50, i mean, why do we choose 4 of all numbers?
Why is it plus 2
At what time in the video?
5:30
That part is looking at a linear sequence like: ua-cam.com/video/vvayGlslby0/v-deo.html
My exam is tomorrow 😭
Hope it went well
@@MathsWithJay it did thankfully 😅
same :' )
im vegan btw, very cool!
Does that help you to find the nth term?
Loooll
lol