I just realized that we could connect a line from a point on the circumference of the shaft touching one side of the key to the other point also on the circumference of the shaft but touching the other side of the key, and this line connected by these two points is parallel to "b". the Arc length on the key that lies on the circumference of the shaft if the circumference were continuous does not make sense...
@@NoobCube248 statement po sa problem that the system is prevented from rotating. The force F is the force preventing the system to rotate and should be opposite of the direction of the given torque kaya sya assumed clokwise
I just realized that we could connect a line from a point on the circumference of the shaft touching one side of the key to the other point also on the circumference of the shaft but touching the other side of the key, and this line connected by these two points is parallel to "b". the Arc length on the key that lies on the circumference of the shaft if the circumference were continuous does not make sense...
But that area is larger than that of using "b" so the mode of failure is higher on the thinner part of the key.
Thanks for your efforts, Mr.But I have a problem, how did you get 30?What is the radius of this?
Given in the problem is 60 mm diameter. The 30 mm is the radius taken as half of the value of the diameter.
Hello po, Pano nagka F doon and not counter clockwise torque?
@@NoobCube248 statement po sa problem that the system is prevented from rotating. The force F is the force preventing the system to rotate and should be opposite of the direction of the given torque kaya sya assumed clokwise
why po na hindi na e multiply sa pi yung 70(b)(pi)?
You don't need pi for solving area of rectangle po, length times width lang i.e. 70b
bakit po T=fd?
To compute the Torque its force time distance po. Formula po yan.