Arclength Formula | Derivation & Ex: Circumference of a Circle
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- Опубліковано 24 сер 2024
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Description: We can use calculus to compute the arclength of differentiable curves. In this video we develop the formula from basic ideas of integral calculus. Then, knowing the formula, we apply it in a special case, computing the circumfrence of a circle. Of course we have long since memorized that formula, but isn't it nice to see it actually derived?
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This video was created by Dr. Trefor Bazett, an Assistant Professor, Educator at the University of Cincinnati.
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Excellent. A visual approach like this makes it much easier.
Dear Dr. Trefor, Because of a logical and step-by-step way you have explained/derived the Arclength Formula, even someone with less mathematical knowledge can understand this, so to speak. Very well done Dr. Trefor and thank you!
Dear Dr. Trefor, Thank you very much for your quick reply. I often wonder how someone like you for instance with so much knowledge looks at everyday life; is it still possible to observe life events with a neutral view? Maybe an impertinent question of me, in that case I apologize sincerely! Well-balanced, educational and enjoyable math videos, Dr. Trefor. greetings from the other side of the atlantic sea...
Thank you very much professor for teaching these lessons so clearly. Now I can understand the entire arclength lesson easily than before
Your contents are like paid course but you're giving it free. Lots of love from Bangladesh.
I was sick and could not attend calculus2 for for two weeks and your videos helped me a lot. Thank you sir
Really appreciate your videos. It's great to watch a video like this before reading the text or attempting problems.
a quick way to understand the formula also comes from the idea that, if you move along a curve, distance comes from integrating speed, i.e. magnitude of velocity. Understanding that this implies length comes from integrating the magnitude of changes in x and y can allow you to extrapolate to the formula pretty quickly.
sir how f'(x) replaced f'(xi*) ???
Reimann sum. You can pick any x as long as x is in the interval delta_x. The result is the same.
With graph and examples , concept is easy to grasp.
I'm grateful for this amazing way of explanation.
You and professor Leonard are currently saving my calc 3 grade
This is really the best I have seen that explained how to calculate arc length so awesome.
I just want to say thank you for your time and great work
love ❤️ from Iran
Thumb up to your video, I think you are indeed a good math educator
Thank you! 😃
That division by zero almost pokes the eye 😂
Excellent
Amazing, well Presented and explained. Thanks.
Love you Trefor youre the best 😊
it was awesome sir ,please keep making such wonderfull videos ,we are always with you 😤🤩🤩👍🏻👍🏻♥️♥️❤️
I'm so grateful to u!
Respect++ Earned😍😍😍
❤️ from Pakistan🇵🇰
Great video, very succinct
Thanks for this!!
Nicely done.
deriving this is difficult
modeling with differential calculus is still hard, eg trying to derive the differential equation for a one-dimensional wave/string is hard
5:29 MVT also requires continuity right
Hello Dr. Bazett, I was going to ask why this formula was different than the one for 3D curves with parametric equations, and I think it just clicked why they are different. Here you are converting the change in 'Y' into terms of x because you integrating the curve between some bounds with a change in 'x', but when we are doing parametric curves we need the terms in the form t because we are integrating over some bounds with a change in 't'.
Great video.
Make a video about fourier series
Great.
8:09 HOW CAN WE TAKE FROM -1 TO 1 IF THE DERIVATIVE IS NOT DEFINDED IN THE BOUNDARIES, I MEAN IF F IS DEFINED OVER -1:1 INCLUDING BOUNDARIES THEN THE DERIVATIVE IS DEFINED OVER THE OPEN INTERVAL, SO HOW CAN WE INCLUDE THE BOUNDARIES WHEN INTEGRATING
Nice explanation 👌👍..
Great content!
Thnks for this helpful vedio
How do you make such a wonderful videos? Any tips.
what about arc length of a implicit function?
Sir, can you please help me, when we have taken the limits for a full Circle, then arclength should be 2π. But that isn't the case here?
@@DrTrefor Thanks, I missed that
oh I should train my forearms today
U r awesome .
hi! can you please help me ? why does he replace the sigma with the integral sign in minute 7:01?
He took the limit as delta x goes to zero, and n goes to infinity. Just like Riemann sums become integration by doing the same thing when we are first introduced to integration, this sum becomes integration as well. Taking the limit as our segments get small, and our number of segments gets large.