#1 and #2 are separate cases. For #1 you look at f(4), which is f evaluated at x=4. So for #1 that is the case for when x=4. For #2, you look at the limit as x approaches 4. So x is never equal to 4, it approaches 4. Cases #1 and #2 don't happen at the same time, so x is never simultaneously equal and not equal to 4. For Case #3, if the answers to #1 and #2 are the same, then the function is continuous.
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Very good. Thanks
Thankyou maam🙏
There’s a hole at 4, so not continuous.
how can x=4 while simultaneously not being equal to 4?
#1 and #2 are separate cases.
For #1 you look at f(4), which is f evaluated at x=4. So for #1 that is the case for when x=4.
For #2, you look at the limit as x approaches 4. So x is never equal to 4, it approaches 4.
Cases #1 and #2 don't happen at the same time, so x is never simultaneously equal and not equal to 4.
For Case #3, if the answers to #1 and #2 are the same, then the function is continuous.
why cant you just put 4 into x^2 - 16?
if ur talking about the first step, f(x)=8 when x=4
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