A good teacher shows how smart he is, but the best makes his students feel that they are smart. Thank you, Professor Razavi. You are the best of the best.
I a doubt here at 11:33 , if here input terminal is source and output terminal is drain, that means that drain is at higher potential than source and the amount by which its higher is voltage across the resister, now if the source terminal is increasing its value, that means drop between drain and source is decreasing, so inorder to stop the drain terminal to increase its value, we should ACTUALLY DECREASE the resistance between them,instead of increasing it. Pleaseee clear my doubt!!!!
@@RaviNagar16the location of the drain terminal and source terminal do not depend on the symbol, but on the voltage difference or the driving current passing through the mosfet (which in this case an NMOS). Apparently current flows from left to right then across resistors to complete the feedback mechanism. Therefore, in this case, no matter how Professor Behzad razavi draws the NMOS, the drain terminal is on the left and source is on the right.
I a doubt here at 11:33 , if here input terminal is source and output terminal is drain, that means that drain is at higher potential than source and the amount by which its higher is voltage across the resister, now if the source terminal is increasing its value, that means drop between drain and source is decreasing, so inorder to stop the drain terminal to increase its value, we should ACTUALLY DECREASE the resistance between them,instead of increasing it. Pleaseee clear my doubt!!!!
something toomuch interesting: @47:20 after all the analysis he did and made us understand....the way he simply said that the inverter doesn't work.... in lab .......... it was nerve cutting also very thought provoking...and curiosity building.
I a doubt here at 11:33 , if here input terminal is source and output terminal is drain, that means that drain is at higher potential than source and the amount by which its higher is voltage across the resister, now if the source terminal is increasing its value, that means drop between drain and source is decreasing, so inorder to stop the drain terminal to increase its value, we should ACTUALLY DECREASE the resistance between them,instead of increasing it. Pleaseee clear my doubt!!!!
Since the op amp in the circuit has a voltage (Vref) -> Vout - open loop gain = Ao(Vref) -> gate voltage increases making the mosfet work in saturation region..
I a doubt here at 11:33 , if here input terminal is source and output terminal is drain, that means that drain is at higher potential than source and the amount by which its higher is voltage across the resister, now if the source terminal is increasing its value, that means drop between drain and source is decreasing, so inorder to stop the drain terminal to increase its value, we should ACTUALLY DECREASE the resistance between them,instead of increasing it. Pleaseee clear my doubt!!!!
When the drain voltage increases beyond Vref, gate voltage decreases. Since the resistance is inversely proportional to Vgs-Vt so it will increase. And since Vds is inversely proportional to R so Vds will decrease with increase in resistance. This will keep MOSFET in triode region ig. When resistance of the MOSFET in linear region increases current reduces hence keeping the value of drain close to that of source.
I a doubt here at 11:33 , if here input terminal is source and output terminal is drain, that means that drain is at higher potential than source and the amount by which its higher is voltage across the resister, now if the source terminal is increasing its value, that means drop between drain and source is decreasing, so inorder to stop the drain terminal to increase its value, we should ACTUALLY DECREASE the resistance between them,instead of increasing it. Pleaseee clear my doubt!!!!
Is their any reason that the inverting and non-inverting amplifier should look like the same as with that two resistances Why can't we just remove both resistances and just apply the input on either of the two terminals and call it as inverting and non-inverting amplifiers
I a doubt here at 11:33 , if here input terminal is source and output terminal is drain, that means that drain is at higher potential than source and the amount by which its higher is voltage across the resister, now if the source terminal is increasing its value, that means drop between drain and source is decreasing, so inorder to stop the drain terminal to increase its value, we should ACTUALLY DECREASE the resistance between them,instead of increasing it. Pleaseee clear my doubt!!!!
A good teacher shows how smart he is, but the best makes his students feel that they are smart. Thank you, Professor Razavi. You are the best of the best.
I a doubt here at 11:33 , if here input terminal is source and output terminal is drain, that means that drain is at higher potential than source and the amount by which its higher is voltage across the resister, now if the source terminal is increasing its value, that means drop between drain and source is decreasing, so inorder to stop the drain terminal to increase its value, we should ACTUALLY DECREASE the resistance between them,instead of increasing it. Pleaseee clear my doubt!!!!
@@RaviNagar16the location of the drain terminal and source terminal do not depend on the symbol, but on the voltage difference or the driving current passing through the mosfet (which in this case an NMOS). Apparently current flows from left to right then across resistors to complete the feedback mechanism. Therefore, in this case, no matter how Professor Behzad razavi draws the NMOS, the drain terminal is on the left and source is on the right.
@@ylmak3998 drain and source can interchange mos is symmetric bilateral device.
Explanations are given in a very simple way so that the viewer can understand and the concepts given are very good.
Enjoying the way he simplifies the concept. Thank you Professor!!
I a doubt here at 11:33 , if here input terminal is source and output terminal is drain, that means that drain is at higher potential than source and the amount by which its higher is voltage across the resister, now if the source terminal is increasing its value, that means drop between drain and source is decreasing, so inorder to stop the drain terminal to increase its value, we should ACTUALLY DECREASE the resistance between them,instead of increasing it. Pleaseee clear my doubt!!!!
The best teacher ever .
For a difficult subject like Analog you made things so easy and clear.
Thanks a lot Sir.
something toomuch interesting:
@47:20
after all the analysis he did and made us understand....the way he simply said that the inverter doesn't work.... in lab ..........
it was nerve cutting also very thought provoking...and curiosity building.
great lecture from a very very great prof
This is what we can calls as learning subject.....
Great lecture once again, thank you sir
You Cleared many doubts sir
I a doubt here at 11:33 , if here input terminal is source and output terminal is drain, that means that drain is at higher potential than source and the amount by which its higher is voltage across the resister, now if the source terminal is increasing its value, that means drop between drain and source is decreasing, so inorder to stop the drain terminal to increase its value, we should ACTUALLY DECREASE the resistance between them,instead of increasing it. Pleaseee clear my doubt!!!!
I think he is god of microelectronics
ammaizing lecture. solute you SIR
Grea series of lectures
Why is your intro so good?!
Razavi ROCKS!!
behzad abi kralsın sen...
what a legend
Why is thevenin voltage is found at input and thevenine resistance at output? As far as i know both should be found at same place.
Thevenin voltage is found at output for unity gain buffer output voltage is equal to input voltage he said it listen again you will get it
29:18 very cool indeed :D
It was funny to hear him casually say "cool" like that all of a sudden. 8-)
11:45 how can we ensure the MOSFET operates at triode region?
same doubt :(
Since the op amp in the circuit has a voltage (Vref) -> Vout - open loop gain = Ao(Vref) -> gate voltage increases making the mosfet work in saturation region..
I a doubt here at 11:33 , if here input terminal is source and output terminal is drain, that means that drain is at higher potential than source and the amount by which its higher is voltage across the resister, now if the source terminal is increasing its value, that means drop between drain and source is decreasing, so inorder to stop the drain terminal to increase its value, we should ACTUALLY DECREASE the resistance between them,instead of increasing it. Pleaseee clear my doubt!!!!
When the drain voltage increases beyond Vref, gate voltage decreases. Since the resistance is inversely proportional to Vgs-Vt so it will increase. And since Vds is inversely proportional to R so Vds will decrease with increase in resistance. This will keep MOSFET in triode region ig.
When resistance of the MOSFET in linear region increases current reduces hence keeping the value of drain close to that of source.
Does anyone know the name of that catchy music in the beginning of these videos?
I a doubt here at 11:33 , if here input terminal is source and output terminal is drain, that means that drain is at higher potential than source and the amount by which its higher is voltage across the resister, now if the source terminal is increasing its value, that means drop between drain and source is decreasing, so inorder to stop the drain terminal to increase its value, we should ACTUALLY DECREASE the resistance between them,instead of increasing it. Pleaseee clear my doubt!!!!
Is their any reason that the inverting and non-inverting amplifier should look like the same as with that two resistances
Why can't we just remove both resistances and just apply the input on either of the two terminals and call it as inverting and non-inverting amplifiers
I a doubt here at 11:33 , if here input terminal is source and output terminal is drain, that means that drain is at higher potential than source and the amount by which its higher is voltage across the resister, now if the source terminal is increasing its value, that means drop between drain and source is decreasing, so inorder to stop the drain terminal to increase its value, we should ACTUALLY DECREASE the resistance between them,instead of increasing it. Pleaseee clear my doubt!!!!
I thought that for a differentiator, we will use a resistor and inductor!!
You are Sir
هو مفيش زرار هنا ادوس عليه اخليه يتكلم عربى ؟؟؟
لا ما فيش 😄
Ultimatum videos
oops😄
49:45 😊
@@aasousajr 😂