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This video is very helpful, thank you
Great Concept. Thaks for the Video.
Thanks Bro... This is what I am looking for...
Thank you bro.
how can i just delete al the records with one button. Im doing this for a shopping cart and when i say "order" it needs to delete the files from the cart table.
Can we have query sql string with one connection only? Update table1 set col=2 where id=1; update table1 set col=10 where id=2; update....
How to create the dropdown field for position and Office ?
can you please add code for having select option instead of input?
punya sya kok error undefined array disini ya mas$name = $_POST['name_'.$updateid]; $position = $_POST['position_'.$updateid]; $office = $_POST['office_'.$updateid]; $age = $_POST['age_'.$updateid]; $salary = $_POST['salary_'.$updateid];ada solusi mas?
I am updating 30,000 record. Too many connection error.
hi can u give me paing for this
You are looping mysqli possible of too many connection error.
This video is very helpful, thank you
Great Concept. Thaks for the Video.
Thanks Bro... This is what I am looking for...
Thank you bro.
how can i just delete al the records with one button. Im doing this for a shopping cart and when i say "order" it needs to delete the files from the cart table.
Can we have query sql string with one connection only? Update table1 set col=2 where id=1; update table1 set col=10 where id=2; update....
How to create the dropdown field for position and Office ?
can you please add code for having select option instead of input?
punya sya kok error undefined array disini ya mas
$name = $_POST['name_'.$updateid];
$position = $_POST['position_'.$updateid];
$office = $_POST['office_'.$updateid];
$age = $_POST['age_'.$updateid];
$salary = $_POST['salary_'.$updateid];
ada solusi mas?
I am updating 30,000 record. Too many connection error.
hi can u give me paing for this
You are looping mysqli possible of too many connection error.
Thank you bro.