Group of order 56 is not simple

[@Md.AbuBakr]

NICELY EXPLAINED MA'AM

[@anshumanpal8078]

Very nice explanation mam 😊

[@ghulamhabibhabibi9118]

thank you!

[@DhaanvisCreations]

1lk
Beautifully explained

[@05anjamantabssum53]

Thank you❤🌹 so much mam

[@music_lyrics-ni7ks]

Beautifully explained, Ma'am, thank you so much

[@NAZMULHASAN-nl9ev]

Mam,why are you take such as n1,n7 .which method ,please explain

[@rudrakishore2840]

Nyc Explanation🎉🎉

[@princehudda3992]

Mam isme jo 7 or 8 order ka group h Usme common elements bi to ho sakte h

[@enoceliasperezmatias7089]

Muchas gracias. Saludos desde México.

[@aadityakant7329]

Ma'am if last condition was hold then will what??

[@ALLISON-4417]

Good presentation my friend

[@akd26438]

Mam Kya sirf identity common ha or koi elements common nahi Ho sakta.

[@recipe_routine]

Thank you mam for this presentation, it is so helpful.

[@dr.upasanapahujataneja1707]

Many Thanks....please refer to other Videos of modern Algebra and real analysis...

[@deepakgautam7062]

Thanks mam 🙏🙏🙏

[@dr.upasanapahujataneja1707]

Thank you

[@latestfactsfile3900]

Very nice explanation mam❤

[@anikumari4423]

Thanks di

[@04arunjeet22]

Mam pls make a video on group of order 30 .
What will be the cases?

[@sambhusharma1436]

Ma'am why there is only identity element common between two p-ssg?

[@dr.upasanapahujataneja1707]

Thanks for asking the question😊
Ans- As every group has Only one identity element and these are Subgroups of this group so the identity element is common.

[@BlacksheepY-l8q]

@@dr.upasanapahujataneja1707 the question here is not why identity is a common element between two p-ssg, but the “only common”.

[@BlacksheepY-l8q]

Because she made a mistake on assuming all “p-SSG” has prime order, forgetting the p here indicates the group has order of a power of p, not that group has prime order.

[@rohitprasad5333]

Thank You so much ma'am!!😭

[@dr.upasanapahujataneja1707]

You are so welcome!
Keep watching

[@radharanibhakta8735]

Thank you so much ma'am

[@dr.upasanapahujataneja1707]

Thank you 😊

[@radharanibhakta8735]

@@dr.upasanapahujataneja1707 Ma'am is it possible to personally contact with you ??

[@dr.upasanapahujataneja1707]

Mail me at [e-mail]

[@radharanibhakta8735]

@@dr.upasanapahujataneja1707 okk thank you ma'am

[@lapotela3108]

thanks mam

[@dr.upasanapahujataneja1707]

Most welcome 😊

[@kartiklifestyle]

Thank you mam

[@RideR-SAM65]

Mam there can b more elements common in two Sylow p subgroups...why are we taking only identity element in intersection?

[@dr.upasanapahujataneja1707]

They Will not have any element common other than identity as they are groups of prime order...

[@BlacksheepY-l8q]

@@dr.upasanapahujataneja1707 by this you are claiming 8 is a prime number, again, “2-SSG” is a group with order being powers of 2, in this video every 2-SSG has order 8, by no ways you can restrict it to just a cyclic subgroup or order 8.

[@arpitamishra656]

Please make a video on "group of order 120 is not simple"

[@kidsgames3352]

Hii..have u ans for tiz question?? Explain it..

[@amansparsh7229]

Mam, here in 2-SSG order is 2
1 is identity common in all H1,.....H7 and rest contains one more element in total 1+7 = 8 (you took 48 here)
And 7 SSG is 48
In total giving 56 which divides 56
Am I right ????

[@saumyagupta7192]

The order of 2-ssg is not 2. It is 2^3 = 8

[@abijith8829]

Very usefull

[@dr.upasanapahujataneja1707]

Thank you...😊

[@pushpaboora8813]

Mam ssg ki full form btana

[@dr.upasanapahujataneja1707]

Sylow subgroup

[@karma_returns463]

Mam in case of group of order 30,
n2 = 1,3,5,15
n3 = 1,10
n5= 1,6
Now how to proceed further?
What will be the different cases?

[@anjaneyasharma322]

Is (1, 2) a simple group ?

[@dr.upasanapahujataneja1707]

Write me on [e-mail]

[@BlacksheepY-l8q]

This prove fails at 7:49 here the number of “2-SSG” is 7 and number of elements in every “2-SSG” is 8, we know nothing about these subgroups of order 8 and you just assumes they are all isomorphic to cyclic group of order 8 and trivially intersects. THIS IS SIMPLY FALSE. The same problem arises multiple times in your videos, and you have refused to address this issue.

[@dr.upasanapahujataneja1707]

Will definitely look into this and will revert asap

[@a-_-handIe]

English please? Can't understand Indian

[@indranilsaha7753]

Please stop giving such wrong solutions...