e^(-1/z^2) Essential Singularity

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  • Опубліковано 21 жов 2024

КОМЕНТАРІ • 10

  • @shubh.ruhela
    @shubh.ruhela 7 місяців тому

    Maine pada tha tha ki function exp(-1/z^m) nowhere analytic hota hai. Nowhere analytic hai to no singularities nahi hogi yaha ??? Plz clear my confusion!

    • @shubh.ruhela
      @shubh.ruhela 7 місяців тому

      @@prachi_ but this opposes the definition of singularity! Csir Feb 2022 QID 527 mein ek aisa question aaya tha.

    • @prachi_
      @prachi_  7 місяців тому

      @@shubh.ruhela ok i got your point. According to the definition of singularity, a point is said to be a singularity of a function if its neighbourhood contains at least 1 point at which it is analytic .

    • @shubh.ruhela
      @shubh.ruhela 7 місяців тому

      @@prachi_ now can we can the given function is nowhere analytic but satisfies the CR equation over C ?
      Also, what if the function is not given in the price wise form ( i.e. f(z) = 0 at z =0 not given) only f(z) = exp(-1/z²) is given then what can be about its singularities? I found two answers of this question 1) z=0 is an essential singularity (coaching institute assignment sheet)
      2) no singularities (in official answer key and in dips academy handwritten notes)
      Plz clear my doubt! Which one is right ?

    • @prachi_
      @prachi_  7 місяців тому

      If the function is not analytic it will not satisfy CR equation

    • @prachi_
      @prachi_  7 місяців тому

      And at z=0 the f(z) = e^ (-1/z^2) will give 0 . Whether it is mention or not mention in question

  • @Mjafar2000
    @Mjafar2000 Рік тому

    What is zero of this function??

  • @Amitkumar-vk3ln
    @Amitkumar-vk3ln 2 роки тому

    nice explanation