[@Monica-in6mk]

thank you! this was really helpful for my exam

[@ceriselewis1350]

Thanks, my son was struggling with matrices and your video has cleared up all of the ambiguity!!! Thank you.

[@Tofumoode-jy6ro]

Thanks, my textbook and some or other videos didn't help much except yours. Thanks again.

[@twa_le]

Nice one! I didn't know how to do this until now :)

[@ktri9291]

Nice video. Tip: if you are doing an intense cramming session like I am try watching at 1.5 speed.

[@thejomarifernandez7554]

Thank you. I love you

[@karanichols4587]

God bless you, sir. You've explained this so well.

[@hugoolsson7372]

Thank you! Great explanation!

[@danielvanbibber991]

Thank you so much! This makes perfect sense now!

[@joinedthenavy]

thank you

[@xBXVx97]

listen to this man
great video

[@marshallzingkhai889]

Thank you....hope this type of questions will be asked for my exams tomorrow.

[@stacydrake2341]

Hi David,
Firstly, Thank you - the way you describe the transcription of the row operations to elementary matrices is perfect.
Unfortunately, I'm confused about the final answer achieved here. My text indicates that E1*E2*E3*...*Ek*A=I. To get A on the left by itself we need to use multiply both sides of the equation by the inverses (E1^-1, E2^-1, etc). When I used the method prescribed in the video to do my own homework, I end up having to make A= the inverses of E1*E2*E3 etc. to get the answers to match the text. Can you clarify? Did I miss something in the video?

[@mathslearningUofA]

I think so Kellas -- A has been written as a product of matrices, each of which is an elementary matrix.

[@robbiebrooks8245]

god bless your soul and your family for generations

[@kellaslowery8426]

Are you sure that final answer is perfectly on point?

[@wowitsfeffy]

Kellas Lowery it is correct, multiply them together and you get back A