A tricky question for math lovers

[@ZoonCrypticon]

Where was the tricky part? Did I miss something ?

[@thilakhari]

I solved it too. It wasn't tricky at all.

[@plkrishh]

Quoting Sherlock Holmes "Elementary Watson".
10 min explanation not needed tor this

[@tellusorbit]

He talks too damn much.

[@RikiFaridoke]

Please using complex analysis method sir.

[@Ecknaton]

This gives rise to a quadratic equation, therefore x=a+root b, y=a-root b. From the first equation follows a=3. Then from the second it follows b=3.

[@خالد-ح9ف-د2ل]

First it is simple,but it is become complicated,

[@KaivalyaChess]

very nice sir

[@ic2Yee]

bro 7th grades could do this

[@chiffxyz]

I thought this was the most basic of product of roots and sum of roots problem.

[@iuliusv]

awesome

[@benjiebogarts]

The key step is y=6/x or x=6/y

[@bundlesofun9568]

This guy is the king of generating hate in his comment section 😂

[@OH2az2]

can't you just start this thing "x + y = xy" and skip a bunch of steps?

[@Segalmed]

x=6-y put in equation 2 => y²-6y+6=0 => y1,2 = 3 +/- Sqrt(3). Since y and y are interchangable x1,2 =3 -/+ SQRT(3).
Where's the tricky part?

[@RealQinnMalloryu4]

(3)+(3) =6 (y ➖ 3x+3). (xy ➖ 3xy+2) .

[@ksenchy]

Do you think you can do some collage level stuff? This is NOT higher math 😱

[@AyushKalmodiya-j3g]

😮😮

[@hakanerci4372]

X= 3+ root3, Y= 3- root3

[@joss5515]

Ingerchangeable so there are 2 sets of solutioms

[@hakanerci4372]

@@joss5515 yes

[@TheSourJam]

No, the other solution is extraneous

[@marais75012]

That is not higher math.

[@prollysine]

x+y=6 , x*y=6 , x=6/y , 6/y+y=6 , y^2-6y+6=0 , y= 3+V3 , 3-V3 , x=6-y , x=6-(3+V3) , x=3-V3 ,
x=6-(3-V3) , x=3+V3 , solu (x , y ) , (3-V3 , 3+V3) , (3+V3 , 3+V3) ,
test , x*y=6 , (3-V3) * (3+V3) = 9-3*V3+3*V3-3 , --> 6 , (3-V3) * (3+V3) = 9+3*V3-3*V3-3 , --> 6 , OK ,

[@AsadbekRoʻziboyev-u2f]

Bot bad Mr

[@WashingtonAgboka]

Speak slowly