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Gud mrng mam/sir In tcs profile I have entered Rakshitha only instead of Rakshitha N will they allow me to write an exam because in Aadhar card my name as Rakshitha N.
Prepinsta tell me how to get my paid material u deducted my money but not send me any material.what the hell is going to happen from ur side.u give me ur no.i want my paid material
I agree that 217 can be the right Child of X so that x range is [94 to 136] [=43 different values] but 217 can also be the left child of X so that x permissible range becomes [218 to 235] [=18 different values] so in total x can have 61 different/unique values
I agree that 217 can be the right Child of X so that x range is [94 to 136] [=43 different values] but 217 can also be the left child of X so that x permissible range becomes [218 to 235] [=18 different values] so in total x can have 61 different/unique values
@@bestquotes2765 because the next node traversed from X is 217 and while searching we follow a single path till the searched node . Just try to go for a BST and search any value in it you will get it
in ques 3 there should be specified that the tree is also binary search tree, then only we can perform your procedure other wise information is not enough...... and if this is specified that the tree is binary search tree then we can find post order just after finding inorder as inorder of a BST is just all keys with ascending order arrangement... so at the end we can find post order with the help of pre and in order
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In question 10, i think correct answer would be 43 instead of 42. as x can take values from 94 till 136. to understand this suppose x can be 5,6,7 if we do 7-5 this will give us 2 but here x is actually taking 3 values.
Sir, I have already cleared TCS digital 2020 held at our campus but didn't get selected. So can I directly appear for TNQT interview or should I take TNQT 2020 again? Our placement cell said that we can appear directly for an interview. so please sir reply asap! Thank you
@@nikitasarda7389If you appear for the interview without writing NQT you will be considered for Ninja profile only. If you are determined to get Digital profile write NQT. This is what our college said to us.
I really appreciate your hard work to give easy explanation for students who really need this . I follow Prep Insta 's all video regarding TCS NQT. All the materials are really helpful and I also go through all your website course..Good quality content. 5 stars 🌟🌟🌟🌟🌟
answer to ques 10 should be 43 as number of elements between 136 -94 is 43 not 42, Eg: elements between 94-98 is (94,95,96,97,98) =5 (98-94+1=5) therefore 136-94+1 is required
Thank You very much sir it was a great videos, every question is explained in detail so the concept also clear and if question of this type comes can also be solved ...once again thank you very much
My answer for question 10 You chose position of x right But after that there will be 2 possibilities 217 will be the right child or the left one If right then 93
In Qns.10 : As per the sequence of order the X had appeared in-between the number 93 and 217. So, the ans would be 124(217 - 93). In Qns.7 : When we look at the key point "the packets arriving in right order" we can use queue data structure right? as it's increase size based on input.
in ques 3 there should be specified that the tree is also binary search tree, then only we can perform your procedure other wise information is not enough...... and if this is specified that the tree is binary search tree then we can find post order just after finding inorder as inorder of a BST is just all keys with ascending order arrangement... so at the end we can find post order with the help of pre and in order
The first explanation of the question was wrong. it's not about 6 zeros there. The actual reason is when we store 0.1 in variable "f" it stored in binary form in memory. we can not convert 0.1 into binary accurately there will be some transaction error. The same question if you do with 0.5 you will get output "yes" without typecasting. Happy coding
@@arnavsingh381 but where she wants recent changes to undo .In telephony audio message you can't undo anything. so,I think queue might be the better answer .
Thank you Atulya Sir...your explanation is always the easiest..whether it is your online class or study material. Keep explaining like this only no complains
This video helped a lot, I thought all the important matter would only be in your paid content which I couldn't buy. I hope it all helps in clearing the test.
My answer for question 10 You chose position of x right But after that there will be 2 possibilities 217 will be the right child or the left one If right then 93
How to approach pointer based question in Tcs. And ur team is so active. And we are preparing in ur platform and we are sharing your videos to my frds.. Thanks a lot.
In last question! What if x value is lesser than 93.. Then it will go to left hand side. So the method will be same for both right and left hand side.!!
x value can't be lesser than 93 else we will never get to traverse 217 while searching 137, although x can be greater than 217 which isn't mentioned. Reply if I am wrong @Prep Insta
The viedo was very helpful ...can u please give a clear idea about pre and post increments and decrements by explaning more examples ..bcz its a confusing topic when to solve from right or left
Diffrent compiler read this statemenr differently.... Some reads it from left to r8 and some r8 to left!! Always go from right to left (as per c or c++)
Doesn't matter, what comes next to x node. What matters here is, x may be lesser or greatter than 93.... Firstly, here we have to decide that where we want to put the x node after 93 You can place x either left side or right side.
when you run code for question 2 you get answer 22 as "a" will first pre incremented and will become 11 so a+a = 22 will be assigned to x. Please correct me if i am wrong.
I think you have missed something in Q3 it should be binary search tree not just tree. If its a normal tree or even binary tree then there is no compulsion on left child should have to be lesser
In Question 7 how can Linked List be the answer when we know in Computer Networking Flow Control Methods like Stop & Wait/Go Back N etc use Queue as the Receiver Buffer to receive data packets from Sender?
Question 3rd sol. is wrong The order will be 9,11,15,13,19,23,21,17. Because 11 should come before 9 while traversing the tree in post order...the post order format of traversing is left,right ,root and root of left can be 13 and 11 both
hello sir, my doubt isnt related to these questions. Like suppose we declare an enum function and in enum function if we initialize the value to some number, then will the initialized value be considered or the value which enum assigns?
Sir in first question there's no bracket for "if and else" statement soo no answer ll be printed, the complier ll indicate error...I am saying no answer ll be printed(it ll indicate error)
In ques 9 when n becomes 0 you are saying it'll terminate then how can you decrement the n th value?? ...the answer of that ques ans should be '7 5 3 1'
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In 2nd qn u haven't checked the priority
Right to left
Gud mrng mam/sir
In tcs profile I have entered Rakshitha only instead of Rakshitha N will they allow me to write an exam because in Aadhar card my name as Rakshitha N.
Prepinsta tell me how to get my paid material u deducted my money but not send me any material.what the hell is going to happen from ur side.u give me ur no.i want my paid material
I agree that 217 can be the right Child of X so that x range is [94 to 136] [=43 different values]
but 217 can also be the left child of X so that x permissible range becomes [218 to 235] [=18 different values]
so in total x can have 61 different/unique values
Sir in ques 10 the value of X is greater thn 93 and less than 217 how come it is less than 137 ? I didnt get it
I agree that 217 can be the right Child of X so that x range is [94 to 136] [=43 different values]
but 217 can also be the left child of X so that x permissible range becomes [218 to 235] [=18 different values]
so in total x can have 61 different/unique values
Yes....I too rising this doubt .....
Great Buddy
Why we shouldn't assume that x value smaller than 93 so that x become left of 93?
@@bestquotes2765 because the next node traversed from X is 217 and while searching we follow a single path till the searched node . Just try to go for a BST and search any value in it you will get it
@@anandmusicverse6235 where would you put 69 or 92 on that tree?
in ques 3 there should be specified that the tree is also binary search tree, then only we can perform your procedure other wise information is not enough......
and if this is specified that the tree is binary search tree then we can find post order just after finding inorder as inorder of a BST is just all keys with ascending order arrangement...
so at the end we can find post order with the help of pre and in order
ur right
U know what, you're best at explaining things. U became my helping hand for all time. ❤️❤️❤️
I didn't have much idea about tcs paper pattern. Such video needed to prepare placement .Thank you so much for this video. It helped a lot.
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hi
I have great experience with prepinsta from August 2018..i gi through the this videos and i easily cracked tcs ninja .. programming explanation part will very excellent..i should request to same explaination about advance apptitude.. thank you prepinsta😀
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Is this a re-uploaded video....
I have already watched this videos last night..
I didn't get Q4 because in tree right child value is always greater than the root value
24:28 "Eesha is doing all kinds of things" :p Boss lady!
In the last question answer will be 43 (94 to 136, that's 43 values in total).
you are Right 94 and 136 also include
In question 10, i think correct answer would be 43 instead of 42. as x can take values from 94 till 136. to understand this suppose x can be 5,6,7 if we do 7-5 this will give us 2 but here x is actually taking 3 values.
In the last question, the answer will be 61 and not 42 . As -
1) for 93
Close to answer, we could consider number between 94 to 235 including both and excluding 137 and 217 which turns out to be 235-94+1=142
@6:52 right to left... Pre increment will have highest priority so 11 + 11 is 22
Who liked the comment
I suggest you, write the entire code in c compiler and execute and check the output.
who else feel that voice is mismatch with pen.
Hello guys,
Hope that you like the video. If have any doubts :) You can ask me in the comment section below...
Atulya Sir !!! ^_^
Sir, I have already cleared TCS digital 2020 held at our campus but didn't get selected. So can I directly appear for TNQT interview or should I take TNQT 2020 again? Our placement cell said that we can appear directly for an interview. so please sir reply asap! Thank you
@@nikitasarda7389If you appear for the interview without writing NQT you will be considered for Ninja profile only. If you are determined to get Digital profile write NQT. This is what our college said to us.
@@nikitasarda7389 You will appear for TCS direct campus selection.
Was eagerly waiting for such a video, Really helps!!!
I really appreciate your hard work to give easy explanation for students who really need this . I follow Prep Insta 's all video regarding TCS NQT. All the materials are really helpful and I also go through all your website course..Good quality content. 5 stars 🌟🌟🌟🌟🌟
Woaaaah thanks !!
que 10 : we cannot travel this side😂😂 Nice explaination
Lolz😂
I started my prep at 10 pm, have the exam in first slot tomorrow. These are the only videos I can relate to :)
Wow, this video helped me in clearing my doubts.. thank you sir for ur easy explanation.......!!!!!!
answer for Q10 is 43 i.e numbers btw 93 and 137 ( Tn=a+(n-1)*d ) so 137=93+(n-1)1 is 45 then subtract 2(for 93 and 137) from 45=43,like if am right
Thank you so much prepinsta. So many questions were there in exam. It will really help a lot. You guys are really doing a lot for all the students :)
Thank you komal
answer to ques 10 should be 43
as number of elements between 136 -94 is 43 not 42, Eg: elements between 94-98 is (94,95,96,97,98) =5 (98-94+1=5) therefore 136-94+1 is required
Thank You very much sir it was a great videos, every question is explained in detail so the concept also clear and if question of this type comes can also be solved ...once again thank you very much
honestly Q10 is going over my head :P
He did not explain it very well
same here
my que is also the same
nothing different no difference
Same here
Same here neji, maybe ask sasuke!
My answer for question 10
You chose position of x right
But after that there will be 2 possibilities
217 will be the right child or the left one
If right then 93
You are too good at data structures thanks alot sir
217 can also become left child of X if X is [218,235] by this X can have 61 possible values
Great explanation.This is the best video for understanding Programming logic
Thanks ankita
Q)10 ans will be 61... check it properly by considering both the cases of x>93 and ×
A heart full thanks for this video. It was a much needed video
We are glad that we could help
Thankyou so much for this video today. Much needed video. Tomorrow is the exam. Don't know what type of questions will come
This video is very important a few questions may also come in the exam !!!
In Qns.10 : As per the sequence of order the X had appeared in-between the number 93 and 217. So, the ans would be 124(217 - 93).
In Qns.7 : When we look at the key point "the packets arriving in right order" we can use queue data structure right? as it's increase size based on input.
esha cn packet question answer should be "queue" as we can implement queue using LL and packets are arriving in an order
exactly
In Q.no 3 do mention that it's a bst not just tree
exactly
in ques 3 there should be specified that the tree is also binary search tree, then only we can perform your procedure other wise information is not enough......
and if this is specified that the tree is binary search tree then we can find post order just after finding inorder as inorder of a BST is just all keys with ascending order arrangement...
so at the end we can find post order with the help of pre and in order
The first explanation of the question was wrong. it's not about 6 zeros there. The actual reason is when we store 0.1 in variable "f" it stored in binary form in memory. we can not convert 0.1 into binary accurately there will be some transaction error. The same question if you do with 0.5 you will get output "yes" without typecasting. Happy coding
nice
Yes 1st question explanation is wrong
in last question you need to take 94 &136 so answer is 42+1=43.
What if the value of X is 80??
Q2. I thought this type of questions solved from right hand side.
Thank u for this video, it really helped me in understanding coding difficulty
Thanks vaibhav
Thank you so much for this video sir..this will really help me in preparation for tcs nqt 👍
In question 7 answer can be queue because FIFO and queue can also be implemented using Linked list.
agree, but she wants the recent changes to undo. stack will be good. pop the top
@@arnavsingh381 but where she wants recent changes to undo .In telephony audio message you can't undo anything.
so,I think queue might be the better answer .
Thank you sir for the explanation. It helped a lot in understanding the concept..
we are really happy that you liedk it
Thank you Atulya Sir...your explanation is always the easiest..whether it is your online class or study material. Keep explaining like this only no complains
Thanks ashish means a lot
Nice video ,day after tomorrow is my tcs xm ,tnx for uploading this video we want more videos like this 😊
Sir in Question 7 queue can be the answer because queue is open from both sides just like a pipe for transmission of packets isn't so??
in queue size is fixed
A very good explanation sir. Good 👍😍😍
in Q10 .... 236>x>217 or 137>x>93
Great work guys..
Learning is never been this much easy thanks for the greater good prepinsta
Thanks rishabh
very nice and useful video.Thank u so much
Very helpful for programming
last question (10 q) ans should be 61 not 42....because 93
Yes, my answer is also same .I don't understand why they are not considering 217
great explanation really loved it
We are really glad that you liked it !!!!
This video helped a lot, I thought all the important matter would only be in your paid content which I couldn't buy. I hope it all helps in clearing the test.
My answer for question 10
You chose position of x right
But after that there will be 2 possibilities
217 will be the right child or the left one
If right then 93
For the ques 5
Circular doubly linked list the accurate answer
How to approach pointer based question in Tcs. And ur team is so active. And we are preparing in ur platform and we are sharing your videos to my frds.. Thanks a lot.
Thanks do not forget to subscribe and ask them subscribe as well !! :)
Good video really loved it
Thanks ^_^ Do not forget to show love and sub
In last question!
What if x value is lesser than 93.. Then it will go to left hand side.
So the method will be same for both right and left hand side.!!
x value can't be lesser than 93 else we will never get to traverse 217 while searching 137, although x can be greater than 217 which isn't mentioned. Reply if I am wrong @Prep Insta
Question 4 was there in my TCS NQT exam for 2018 batch off campus
Yes, its previous year question paper for TCS
The viedo was very helpful ...can u please give a clear idea about pre and post increments and decrements by explaning more examples ..bcz its a confusing topic when to solve from right or left
Diffrent compiler read this statemenr differently.... Some reads it from left to r8 and some r8 to left!!
Always go from right to left (as per c or c++)
Question at 14:18 was there in my TCS exam
Yes, it could also be repeated this time
Thank you sir
👌👌👌👈👌very nice video sirji
...
OSOM SIR
Thanks man.
Informative video😍
sir ques no :2 is giving the ans 22 on turbo compiler which value we take in examination
22 is correct
Those sort of questions are actually compiler dependent . You can never know what is right answer
Thank you...
really iam excited with this content, it was pretty good 👍
Question number 4 and 9 were repeated in July TCS exam
Yes it was asked in the previous NQT exam for 2019 and 2018 batches
Sir in 10 question .
X217
Doesn't matter, what comes next to x node. What matters here is, x may be lesser or greatter than 93....
Firstly, here we have to decide that where we want to put the x node after 93
You can place x either left side or right side.
when you run code for question 2 you get answer 22 as "a" will first pre incremented and will become 11 so a+a = 22 will be assigned to x. Please correct me if i am wrong.
yes bro u r wrong
@@AllDimension to bhai correct to bta
@@nilborban8315 the one he explained was correct
Voice is like ayushman khurana
Answer will be of second question
x=22
This is right.
How?
Please upload more videos on youtube
There is more possible value of X in question no. 10.
In 10th question answer is wrong
217>x
I think you have missed something in Q3 it should be binary search tree not just tree. If its a normal tree or even binary tree then there is no compulsion on left child should have to be lesser
In Question 7 how can Linked List be the answer when we know in Computer Networking Flow Control Methods like Stop & Wait/Go Back N etc use Queue as the Receiver Buffer to receive data packets from Sender?
Question 3rd sol. is wrong
The order will be 9,11,15,13,19,23,21,17.
Because 11 should come before 9 while traversing the tree in post order...the post order format of traversing is left,right ,root and root of left can be 13 and 11 both
please explain pointer based questions sir...thank you
We will post thiat soon as well
Thank u so much prepinsta for uploading the video
You're welcome.... We hope that this video will be helpful for you. If you any questions feel free to ask us in the comment section.
hello sir, my doubt isnt related to these questions.
Like suppose we declare an enum function and in enum function if we initialize the value to some number, then will the initialized value be considered or the value which enum assigns?
43 will be the answer of question number 10
sir ji aapto khel gye last question me
Tqq sir
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In which compiler you gives output??
Sir the second qst that u have solved is wrong. Pls check once the correct ans is 22
NO its correct
And is 22
Q. 2 ans is 22
Is TCS NQT taking Programming logic questions on C programming only? Or from some other languages?
Sir in first question there's no bracket for "if and else" statement soo no answer ll be printed, the complier ll indicate error...I am saying no answer ll be printed(it ll indicate error)
There is no need of brackets for if and else...it still gibes the output
@kgame , okay 😊
In question 9, ch is int variable but ch = getchar() is present won't that result a compilation error?
In ques 9 when n becomes 0 you are saying it'll terminate then how can you decrement the n th value?? ...the answer of that ques ans should be '7 5 3 1'
bro the whatsapp group is full..pls upload it in youtube or create group in telegram..please
In last question, if X is printed on the right of 137 then how it will be less than 137?
Programing me career bnane ke liya kya hume compilr design,network ,os,rdms,padhna padega reply. kar
In Q no 10. The value of x can also be less than 68...than why we r not considering that??
if we start our search from 68, how come x would be less than 68
if only these videos were posted a week ago
1st question, if i put 0.1 it gives "no" but while am putting 0.5 it gives "yes" in actual comliper nut why???