Proving a Sequence Converges Advanced Calculus Example with {(1/n^4)}

Поділитися
Вставка
  • Опубліковано 24 гру 2024

КОМЕНТАРІ • 18

  • @RobinsonGames
    @RobinsonGames 6 років тому +13

    That really helped me to understand that topic a lot better. I did understand the definition but couldn't really do a proof myself. Thanks for the video.

  • @dangerousangel777
    @dangerousangel777 4 роки тому +1

    Wow. This was the best explaination I have seen thus far. NOWWWWWW I get it. And I get why you should do it forwards and backwards. It just shows it more clarity. Thank you 😭❤️ I've been trying to understand this for weeks.....months....lol

  • @juarjuna4130
    @juarjuna4130 6 років тому +5

    What a great explanation! Thank you!

  • @jshook
    @jshook 2 роки тому

    3:40 would it also be correct to use the ceiling function to find a natural number lager than 4th-root(1/epsilon)?

  • @brilliazz
    @brilliazz 4 роки тому +5

    Sir you're a legend (and surprisingly funny ;))

  • @uwuslayer0211
    @uwuslayer0211 5 років тому +2

    Can we use ratio test here, so then that becomes limit n tends to infinity, (1/n^5)*(n^4) = limit n tends to infinity (1/n) = 0?

    • @TheMathSorcerer
      @TheMathSorcerer  5 років тому

      No that will not be helpful because that is for series:)

    • @uwuslayer0211
      @uwuslayer0211 5 років тому

      @@TheMathSorcerer mathonline.wikidot.com/the-ratio-test-for-sequence-convergence pls check this link. I want to confirm if this is a valid method

  • @thesangg2816
    @thesangg2816 4 роки тому

    🙏sir .If any sequence have range then that is bounded sequence. Is it right sir?

  • @aneeshsrinivas9088
    @aneeshsrinivas9088 2 роки тому

    Just use the same N choice for 1/n.

  • @ambrosesabbat9385
    @ambrosesabbat9385 2 роки тому

    Why don't we just say that N belongs to N (natural numbers set) ?

  • @thesangg2816
    @thesangg2816 4 роки тому

    🙏sir .If any sequence have range then that is bounded sequence. Is it right sir?

    • @TheMathSorcerer
      @TheMathSorcerer  4 роки тому +1

      if it's stuck within a range then yes it's bounded, so like a_n = sin(n) is bounded