Could you help explain with questions as such: A chemist must prepare 1000.mL of 711μM aqueous copper(II) fluoride (CuF2) working solution. He'll do this by pouring out some 1.83mM aqueous copper(II) fluoride stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the copper(II) fluoride stock solution that the chemist should pour out. Be sure your answer has the correct number of significant digits.
Hi Stephanie! For the problem you referenced, the procedure will be exactly the same, however, you have the added wrinkle of micro mols and mili mols that you must deal with. My recommendation would be to first convert your 711 and 1.83 values into simply 'mols' (you can honestly just use google to do this at this point), then do the problem following the procedure in the video. Hope that helps!
This is still so helpful in 2022! Thank you, I appreciate the time you put into each video
Thank you so much !!!!!!!
chem is the reason i want to drop out. not sure why i need to know this shit for my mechincal engineering...
passed the class with a B somehow lool
Same. I'm doing Civil Engineering and this mess has nothing to do with my career, I would tolerate having issues with Physics, but not Chemistry smh
Could you show for mmol, umol and ml. in another example?
Could you show for mmol, umol and ml.
Can you do the Aleks topic “solving applied dilution problems” under “gases, liquids and solids”
A very good explanation thank you so much
Wow I can’t believe I was having trouble with this .....
Could you help explain with questions as such:
A chemist must prepare 1000.mL of 711μM aqueous copper(II) fluoride (CuF2) working solution. He'll do this by pouring out some 1.83mM aqueous copper(II) fluoride stock solution into a graduated cylinder and diluting it with distilled water.
Calculate the volume in mL of the copper(II) fluoride stock solution that the chemist should pour out. Be sure your answer has the correct number of significant digits.
Hi Stephanie! For the problem you referenced, the procedure will be exactly the same, however, you have the added wrinkle of micro mols and mili mols that you must deal with. My recommendation would be to first convert your 711 and 1.83 values into simply 'mols' (you can honestly just use google to do this at this point), then do the problem following the procedure in the video. Hope that helps!
Can use m1 v1 = m2 v2 without converting to liters?
U help me so much thank you!!!