For question 5 there is no need for any trick like that. Just say A,B,C = a, ar, ar^2. Hence the arithmetic series is: a, 2ar, ar^2. 2ar-a must equal ar^2-2ar. Then divide by a (a != 0) and solve the quadratic for r.
Great idea. Both your approach and Drew's approach beat my approach, where I ended up having to simplify root(7-4root(3)) which whilst not impossible, was very annoying. Great question.
i know the question may just not be worded well but how do you know the terms in the arithmetic progression are equal. it only says they're in a progression so it could be the 3rd 4th and 8th term no?
Thought I’d mention that a better way of attempting question 3 would be to multiply the series G by 3 to get that 3a/1-r =384, and then solve a/1-3r = 3a/1-r by cross multiplying and then getting r = 1/4 subbing that back into any formula
I was confused on q5 since it didnt say where the numbers are in the arithmetic sequence, i assumed that they were in random positions as the question doesnt state it
could a trial and error method for question 9 be a good starting point for limiting options and working on from there, for example when n=1, all of the options cancelled out in question 9 except b.
Does anyone know if we’re going to get a whiteboard or pen and paper in the test? Having to rub out your working so you can’t check each q seems pretty harsh but that’s what i get from reading on the website
Ok I will make it simple, search up Pearson Vue board online on UA-cam and it shows what it is, basically it is a board u can write with a whiteboard pen with multiple pages and u can't rub out ur workings.
You can't rub out your workings yourself from the videos I watched all it means is you have to use like a whiteboard pen style marker, my concern is I am reading we only get 5 pages in this notebook which is not enough for me but I could be wrong about this
As you are splitting the series into 2 parts, there will be n terms of the first sum and n terms of the second sum to make 2n terms, hence each sum is ^n
He cross-multiplied. So when you have 2 things that are equal to each other, you can make them both fractions and multiply the top of the fraction of one side of the equation to the bottom of the other side of the equation and vice versa.
For question 5 there is no need for any trick like that. Just say A,B,C = a, ar, ar^2. Hence the arithmetic series is: a, 2ar, ar^2. 2ar-a must equal ar^2-2ar. Then divide by a (a != 0) and solve the quadratic for r.
i got this and let u = ar to form my quadratic, can we divide through by a as its non-zero ?
@@kobequach3262 yes
Great idea. Both your approach and Drew's approach beat my approach, where I ended up having to simplify root(7-4root(3)) which whilst not impossible, was very annoying. Great question.
i know the question may just not be worded well but how do you know the terms in the arithmetic progression are equal. it only says they're in a progression so it could be the 3rd 4th and 8th term no?
@@gray2262 you make a great point.
Thought I’d mention that a better way of attempting question 3 would be to multiply the series G by 3 to get that 3a/1-r =384, and then solve a/1-3r = 3a/1-r by cross multiplying and then getting r = 1/4 subbing that back into any formula
love these videos
I was confused on q5 since it didnt say where the numbers are in the arithmetic sequence, i assumed that they were in random positions as the question doesnt state it
could a trial and error method for question 9 be a good starting point for limiting options and working on from there, for example when n=1, all of the options cancelled out in question 9 except b.
Can you bring one on integration and graphs aswell
Does anyone know if we’re going to get a whiteboard or pen and paper in the test? Having to rub out your working so you can’t check each q seems pretty harsh but that’s what i get from reading on the website
Ok I will make it simple, search up Pearson Vue board online on UA-cam and it shows what it is, basically it is a board u can write with a whiteboard pen with multiple pages and u can't rub out ur workings.
i'm also interested
You can't rub out your workings yourself from the videos I watched all it means is you have to use like a whiteboard pen style marker, my concern is I am reading we only get 5 pages in this notebook which is not enough for me but I could be wrong about this
@@flippergail9946 thanks, where did you find info on this? 5 pages is rough too though
@@mattwrld2588 I just searched it up on google
Drew for question 9 isn't the answer ^2n instead of n since it's asking for the sum of the first 2n terms?
As you are splitting the series into 2 parts, there will be n terms of the first sum and n terms of the second sum to make 2n terms, hence each sum is ^n
can u do integration qs related to TMUA please?
for question 2 how do you know a is equal to 1 to 3-3r=1
He cross-multiplied. So when you have 2 things that are equal to each other, you can make them both fractions and multiply the top of the fraction of one side of the equation to the bottom of the other side of the equation and vice versa.
@@is4ak yes i get that part but i dont know how do you know that a=1 like the first term in the series is 1
@@urviverlekar4163 a isnt one. When he divided everything by a, the a turned into 1. Because a/a = 1
who is jacqueline?
Are these questions from actual papers or are they made by Jacqueline?
They're made up by Jacqueline but they're good realistic questions that resemble TMUA-style questions.
@@pawelpow thank you, I wanted to make sure I wasn't repeating questions too many times
Much appreciated!