Timestamps 00:02 - Understanding the concept of straight lines in NCERT Class 11 Maths 02:29 - Understanding the signs and coordinates in a Cartesian plane 07:28 - Derivation of the area of a triangle and introduction to slope of a line 10:18 - Finding slope of a line using two points 15:16 - Understanding slope of lines and their relationship 17:47 - Explaining the formula for finding the angle between two lines. 22:06 - Calculation of area of quadrilateral and equilateral triangle 24:40 - Finding the vertices and using Pythagoras Theorem in triangles. 29:18 - Finding a point on x axis using slope and equidistant concept 31:28 - Finding the slope of a line and understanding equidistant points 36:26 - Finding slopes of lines without using Pythagoras Theorem. 38:42 - Finding the slope of a line at a 30° angle with the y-axis 43:09 - Calculation of slopes and angles between two lines 45:41 - Finding the slope of two lines using the formula tan3 50:18 - Understanding the slope point form of a line equation 52:40 - Explanation of slope-intercept form in straight lines 57:14 - Discussion on collinear points and finding equations of lines. 59:20 - Explaining the formula for finding the equation of a line. 1:03:58 - Find the equation of median through vertex RRM. 1:06:37 - Solving for the equation of a line passing through two points 1:11:09 - Find the equation of a line and its slope 1:13:21 - Finding the equation of a line with the intercept form 1:17:50 - Solving linear equations with two variables 1:20:22 - Finding the equation of a line perpendicular to another line. 1:24:58 - Understanding mid point formula and section formula 1:26:52 - Understanding various forms of line equations 1:31:29 - Understanding distance and perpendicularity between a point and a line 1:33:50 - Understanding the distance formula for finding the points on the X-axis 1:39:16 - Lines will be equal or proportional based on the given equations 1:41:25 - Finding the equation of a line parallel to a given line 1:46:09 - Calculating the slope and value of theta 1:48:30 - Finding equation of the second line with given angle 1:53:21 - Intersection point by solving two equations 1:55:35 - L1 is perpendicular to L2, find the value of m1 * m2 2:00:34 - Solving equations using straight lines in one shot 2:02:36 - Finding intersection points and solving equations for line intercepts 2:06:49 - Solving equations and finding common points 2:09:05 - Finding equations with given slopes and angles. 2:13:44 - Solving equations and finding values of A and B. 2:16:27 - Solving for the value of B in a given equation 2:21:23 - Finding the slope of a line using two points. 2:23:53 - Understanding the equations of straight lines and their intersections.
00:02 Understanding the concept of straight lines in NCERT Class 11 Maths 02:29 Understanding the signs and coordinates in a Cartesian plane 07:28 Derivation of the area of a triangle and introduction to slope of a line 10:18 Finding slope of a line using two points 15:16 Understanding slope of lines and their relationship 17:47 Explaining the formula for finding the angle between two lines. 22:06 Calculation of area of quadrilateral and equilateral triangle 24:40 Finding the vertices and using Pythagoras Theorem in triangles. 29:18 Finding a point on x axis using slope and equidistant concept 31:28 Finding the slope of a line and understanding equidistant points 36:26 Finding slopes of lines without using Pythagoras Theorem. 38:42 Finding the slope of a line at a 30° angle with the y-axis 43:09 Calculation of slopes and angles between two lines 45:41 Finding the slope of two lines using the formula tan3 50:18 Understanding the slope point form of a line equation 52:40 Explanation of slope-intercept form in straight lines 57:14 Discussion on collinear points and finding equations of lines. 59:20 Explaining the formula for finding the equation of a line. 1:03:58 Find the equation of median through vertex RRM. 1:06:37 Solving for the equation of a line passing through two points 1:11:09 Find the equation of a line and its slope 1:13:21 Finding the equation of a line with the intercept form 1:17:50 Solving linear equations with two variables 1:20:22 Finding the equation of a line perpendicular to another line. 1:24:58 Understanding mid point formula and section formula 1:26:52 Understanding various forms of line equations 1:31:29 Understanding distance and perpendicularity between a point and a line 1:33:50 Understanding the distance formula for finding the points on the X-axis 1:39:16 Lines will be equal or proportional based on the given equations 1:41:25 Finding the equation of a line parallel to a given line 1:46:09 Calculating the slope and value of theta 1:48:30 Finding equation of the second line with given angle 1:53:21 Intersection point by solving two equations 1:55:35 L1 is perpendicular to L2, find the value of m1 * m2 2:00:34 Solving equations using straight lines in one shot 2:02:36 Finding intersection points and solving equations for line intercepts 2:06:49 Solving equations and finding common points 2:09:05 Finding equations with given slopes and angles. 2:13:44 Solving equations and finding values of A and B. 2:16:27 Solving for the value of B in a given equation 2:21:23 Finding the slope of a line using two points. 2:23:53 Understanding the equations of straight lines and their intersections.
Understanding the concept of straight lines in NCERT Class 11 Maths 02:29 Understanding the signs and coordinates in a Cartesian plane 07:28 Derivation of the area of a triangle and introduction to slope of a line 10:18 Finding slope of a line using two points 15:16 Understanding slope of lines and their relationship 17:47 Explaining the formula for finding the angle between two lines. 22:06 Calculation of area of quadrilateral and equilateral triangle 24:40 Finding the vertices and using Pythagoras Theorem in triangles. 29:18 Finding a point on x axis using slope and equidistant concept 31:28 Finding the slope of a line and understanding equidistant points 36:26 Finding slopes of lines without using Pythagoras Theorem. 38:42 Finding the slope of a line at a 30° angle with the y-axis 43:09 Calculation of slopes and angles between two lines 45:41 Finding the slope of two lines using the formula tan3 50:18 Understanding the slope point form of a line equation 52:40 Explanation of slope-intercept form in straight lines 57:14 Discussion on collinear points and finding equations of lines. 59:20 Explaining the formula for finding the equation of a line. 1:03:58 Find the equation of median through vertex RRM. 1:06:37 Solving for the equation of a line passing through two points 1:11:09 Find the equation of a line and its slope 1:13:21 Finding the equation of a line with the intercept form 1:17:50 Solving linear equations with two variables 1:20:22 Finding the equation of a line perpendicular to another line. 1:24:58 Understanding mid point formula and section formula 1:26:52 Understanding various forms of line equations 1:31:29 Understanding distance and perpendicularity between a point and a line 1:33:50 Understanding the distance formula for finding the points on the X-axis 1:39:16 Lines will be equal or proportional based on the given equations 1:41:25 Finding the equation of a line parallel to a given line 1:46:09 Calculating the slope and value of theta 1:48:30 Finding equation of the second line with given angle 1:53:21 Intersection point by solving two equations 1:55:35 L1 is perpendicular to L2, find the value of m1 * m2 2:00:34 Solving equations using straight lines in one shot 2:02:36 Finding intersection points and solving equations for line intercepts 2:06:49 Solving equations and finding common points 2:09:05 Finding equations with given slopes and angles. 2:13:44 Solving equations and finding values of A and B. 2:16:27 Solving for the value of B in a given equation 2:21:23 Finding the slope of a line using two points. 2:23:53 Understanding the equations of straight lines and their intersections.
@@SathwikRP-t6e 1)Slope of a Line 2)Different Forms of the Equation of a Line 3)General Equation of a Line 4)Angle Between Two Lines 5) Distance of a Point from a Line 6)Distance Between Two Parallel Lines [ HOPE THIS HELPS] :) All the best for your test!
sir tomorrow Is my mathematics examination and I've studied through a tons of ur videos during my preparation leave 😊😊❤❤ , I have no words to describe my gratitude towards u , and pls give me ur blessings for my tomorrow's Mathematica examination 😌🙇🏻🙏
1:54:47 sirji ❤DOUBT❤ pls mera ek doubt Clear kardo sir Ji is question mai humlog equation nikalne ke baad Kya Y-axis Ki equation se solve karke y intercept nikalsakte hai because y axis and yeh, like y intercept Par he toh yeah Line aur y axis meet karrahe hai so that point must be its intercept/intersection and my answer is coming out to be (y=+3) and slope is 1/2. Pls reply
30:15 in this question if the point can be took away from the other two points then why can't we simply let it be the mid point between those two points that is ,(7,6) and (3,4) and then use the class 10th formula to find it's coordinates.
1:16:59 this question has 2 answers actually, one is x+y = 5 and other is y=3x/2 which is a case of 0 intercept, the question mentions that intercepts are equal, but we have to think of 0 intercept as well that is "line passing through origin" so there are 2 answers to this question unless and until it is specified that intercept is not zero
33:24 sir your answer is incorrect sir😅 Given points A(7,6) and B(−3,4) Let the point be P(x,0) [we know that point on x-axis is (x,0)] So, AP=PB and AP2=PB2 ⇒(x−7)2+(0−6)2=(x+3)2+(0−4)2 [Distance between two points is given by distance formula, d=√(x2−x1)2+(y2−y1)2] ⇒x2+49−14x+36=x2+9+6x+16 ⇒49−9+36−16=6x+14x ⇒40+20=20x ⇒x=60/20=3 Hence, point on x-axis which is equidistant from the points A(7,6) and B(−3,4) is (3,0)
Bhai inh chizo par diyan nhi dete but aapne diya bahut acchi baat he iska matlab he aap diyan se pade honge ish chapter ko best off luck Bhai aaise hi diyan se pada karo 😊😊😊
1:51:10 since no one has written the equations for this question i will write what i got 1) x( root3 - 2 ) + y( 1 + 2root3 ) = 5 + 2root3 and 2) x( 2 + root3 ) + y( 2root3 - 1 ) = 7 + 2root3 please confirm if it is right or not
values of a and b were 3h and 3k respectively... and after substituting these values: we get x/3h + y/3k =1 .... it becomes 3kx + 3hy = 9hk ...so i don't understand how u get the "6" while taking common
39:44 i believe the angle is 60° and answer is √3 is valid too along with yours answer This question didn't specify any quadrants and i took first quadrant
@@jatintattoart hello bro , here the explanation:- 4x-3y=6 Divided by 6 in both side 4x/6-3y/6=6/6 Then, 2x/3-y/2=1 You know how to solve it is the form of x/a+y/b+c=0 Hence , x/3/2-y/2=1 or x/3/2-y/2-1=0 So,x intercept is 3/2 Y intercept is -2 Jo bhi x ke niche hota hai vo x intercept hota hai aur jo y ke niche vo y intercept hota hai bas x/a+y/b+c =0 condition honi chahiye. Okk bro .😅
39:32 but sir in the question it is not written that line is passing through origin.. So it can pass through any point on y axis... Hence.. How can you say that it will pass through the origin
3x-4y+c=0 ye ham pe line ki equation hai aur jab ham usme point put karenge toh mera to c=42 aa raha hai yahi ki meri line ki equation 3x-4y=42 aa raha hai?????
1:07:45 sirji point c na Bhi pata ho tabbhi horizontal line ka slope nikallenge with the help of two coordinate given on it and uske baad L1 perpendicular to L2 Ki condition se slope = -1 put karke slope nikallenge and then slope point form lagakar equation nikallenge 😊❤
Timestamps
00:02 - Understanding the concept of straight lines in NCERT Class 11 Maths
02:29 - Understanding the signs and coordinates in a Cartesian plane
07:28 - Derivation of the area of a triangle and introduction to slope of a line
10:18 - Finding slope of a line using two points
15:16 - Understanding slope of lines and their relationship
17:47 - Explaining the formula for finding the angle between two lines.
22:06 - Calculation of area of quadrilateral and equilateral triangle
24:40 - Finding the vertices and using Pythagoras Theorem in triangles.
29:18 - Finding a point on x axis using slope and equidistant concept
31:28 - Finding the slope of a line and understanding equidistant points
36:26 - Finding slopes of lines without using Pythagoras Theorem.
38:42 - Finding the slope of a line at a 30° angle with the y-axis
43:09 - Calculation of slopes and angles between two lines
45:41 - Finding the slope of two lines using the formula tan3
50:18 - Understanding the slope point form of a line equation
52:40 - Explanation of slope-intercept form in straight lines
57:14 - Discussion on collinear points and finding equations of lines.
59:20 - Explaining the formula for finding the equation of a line.
1:03:58 - Find the equation of median through vertex RRM.
1:06:37 - Solving for the equation of a line passing through two points
1:11:09 - Find the equation of a line and its slope
1:13:21 - Finding the equation of a line with the intercept form
1:17:50 - Solving linear equations with two variables
1:20:22 - Finding the equation of a line perpendicular to another line.
1:24:58 - Understanding mid point formula and section formula
1:26:52 - Understanding various forms of line equations
1:31:29 - Understanding distance and perpendicularity between a point and a line
1:33:50 - Understanding the distance formula for finding the points on the X-axis
1:39:16 - Lines will be equal or proportional based on the given equations
1:41:25 - Finding the equation of a line parallel to a given line
1:46:09 - Calculating the slope and value of theta
1:48:30 - Finding equation of the second line with given angle
1:53:21 - Intersection point by solving two equations
1:55:35 - L1 is perpendicular to L2, find the value of m1 * m2
2:00:34 - Solving equations using straight lines in one shot
2:02:36 - Finding intersection points and solving equations for line intercepts
2:06:49 - Solving equations and finding common points
2:09:05 - Finding equations with given slopes and angles.
2:13:44 - Solving equations and finding values of A and B.
2:16:27 - Solving for the value of B in a given equation
2:21:23 - Finding the slope of a line using two points.
2:23:53 - Understanding the equations of straight lines and their intersections.
00:02 Understanding the concept of straight lines in NCERT Class 11 Maths
02:29 Understanding the signs and coordinates in a Cartesian plane
07:28 Derivation of the area of a triangle and introduction to slope of a line
10:18 Finding slope of a line using two points
15:16 Understanding slope of lines and their relationship
17:47 Explaining the formula for finding the angle between two lines.
22:06 Calculation of area of quadrilateral and equilateral triangle
24:40 Finding the vertices and using Pythagoras Theorem in triangles.
29:18 Finding a point on x axis using slope and equidistant concept
31:28 Finding the slope of a line and understanding equidistant points
36:26 Finding slopes of lines without using Pythagoras Theorem.
38:42 Finding the slope of a line at a 30° angle with the y-axis
43:09 Calculation of slopes and angles between two lines
45:41 Finding the slope of two lines using the formula tan3
50:18 Understanding the slope point form of a line equation
52:40 Explanation of slope-intercept form in straight lines
57:14 Discussion on collinear points and finding equations of lines.
59:20 Explaining the formula for finding the equation of a line.
1:03:58 Find the equation of median through vertex RRM.
1:06:37 Solving for the equation of a line passing through two points
1:11:09 Find the equation of a line and its slope
1:13:21 Finding the equation of a line with the intercept form
1:17:50 Solving linear equations with two variables
1:20:22 Finding the equation of a line perpendicular to another line.
1:24:58 Understanding mid point formula and section formula
1:26:52 Understanding various forms of line equations
1:31:29 Understanding distance and perpendicularity between a point and a line
1:33:50 Understanding the distance formula for finding the points on the X-axis
1:39:16 Lines will be equal or proportional based on the given equations
1:41:25 Finding the equation of a line parallel to a given line
1:46:09 Calculating the slope and value of theta
1:48:30 Finding equation of the second line with given angle
1:53:21 Intersection point by solving two equations
1:55:35 L1 is perpendicular to L2, find the value of m1 * m2
2:00:34 Solving equations using straight lines in one shot
2:02:36 Finding intersection points and solving equations for line intercepts
2:06:49 Solving equations and finding common points
2:09:05 Finding equations with given slopes and angles.
2:13:44 Solving equations and finding values of A and B.
2:16:27 Solving for the value of B in a given equation
2:21:23 Finding the slope of a line using two points.
2:23:53 Understanding the equations of straight lines and their intersections.
Maha velaa😂😂
Dhanya hai wo me jisne tumhe janam diya
50:36 50:37 50:37 50:38 50:39 50:39 50:39 50:39 50:40 50:40 50:40 50:41 50:41 50:41 50:42 50:50 50:51 50:51 50:51 50:51 50:51 50:52 50:52 50:52 50:52 50:52 50:43 50:43 50:43 50:44 50:44 50:44 50:45 50:46 50:47 50:48 50:48 50:49 50:50 50:54 50:55 to 50:57 50:58 😊 50:58 50:59 😅 51:00 51:00 😮 51:01 51:01 😢 51:03 51:03 🎉 51:04 51:04 🎉 51:06 51:06 😂 51:07 51:07 ❤
@Abhi-kj5vt Mane diya ha
bhai ye padh rha tha ke likh hea rha tha 😂😂
It's 1 December 2024. Let's see how many of you are watching this video 👀
Dps ho kya
S we exist
Bro i have exam tmrw, 6 nov🥲
Same bro best of luck
kvs jammu region
Sir, at 33:15 the answer is 15/2 but you write -15/2. Because a=-60/-8 , but you write a=-60/8
Pls like it
yes
Sahi hai
Bhai calculation galat karta hai ye 😂
Bro u r right
It's right
Salute for sir because there are only 25+ students watching this video but sir teach like 5 lakh+ students are seen this video 🎉
bruh recorded hai
😂😂
@@DARKNinja273 pehle live bhi to thi bruh
@@Mata_rani.g live nhi premiere thi bruh
@@DARKNinja273 chal sorry😇
Vote for Conic Sections 😢
Bhai isko to dhang se padh le that means revision and question practise !!!
@@satyamupadhyay0002 padh liya hu bhai
Abey conic section bhot easy chapter hai ngl
Haa
Yup
1:34:17
x intercept -->3/2
y intercept --> (-2)
vroo ur ans was wrong
@@vijenderchhimpa_ padh or hai ke too
I was correct 😂❤❤💯❤
@@vijenderchhimpa_ shi h uska answer
1:25:47 ans is 2kx+hy=3hk
31:00 Sir -14a+6a=8a not 7a😊
Exactly
@@U_knowme-8a
1:11:52 Heart touching line sir ... 😊❤️🩹
what is the color of your brain ?
Understanding the concept of straight lines in NCERT Class 11 Maths
02:29 Understanding the signs and coordinates in a Cartesian plane
07:28 Derivation of the area of a triangle and introduction to slope of a line
10:18 Finding slope of a line using two points
15:16 Understanding slope of lines and their relationship
17:47 Explaining the formula for finding the angle between two lines.
22:06 Calculation of area of quadrilateral and equilateral triangle
24:40 Finding the vertices and using Pythagoras Theorem in triangles.
29:18 Finding a point on x axis using slope and equidistant concept
31:28 Finding the slope of a line and understanding equidistant points
36:26 Finding slopes of lines without using Pythagoras Theorem.
38:42 Finding the slope of a line at a 30° angle with the y-axis
43:09 Calculation of slopes and angles between two lines
45:41 Finding the slope of two lines using the formula tan3
50:18 Understanding the slope point form of a line equation
52:40 Explanation of slope-intercept form in straight lines
57:14 Discussion on collinear points and finding equations of lines.
59:20 Explaining the formula for finding the equation of a line.
1:03:58 Find the equation of median through vertex RRM.
1:06:37 Solving for the equation of a line passing through two points
1:11:09 Find the equation of a line and its slope
1:13:21 Finding the equation of a line with the intercept form
1:17:50 Solving linear equations with two variables
1:20:22 Finding the equation of a line perpendicular to another line.
1:24:58 Understanding mid point formula and section formula
1:26:52 Understanding various forms of line equations
1:31:29 Understanding distance and perpendicularity between a point and a line
1:33:50 Understanding the distance formula for finding the points on the X-axis
1:39:16 Lines will be equal or proportional based on the given equations
1:41:25 Finding the equation of a line parallel to a given line
1:46:09 Calculating the slope and value of theta
1:48:30 Finding equation of the second line with given angle
1:53:21 Intersection point by solving two equations
1:55:35 L1 is perpendicular to L2, find the value of m1 * m2
2:00:34 Solving equations using straight lines in one shot
2:02:36 Finding intersection points and solving equations for line intercepts
2:06:49 Solving equations and finding common points
2:09:05 Finding equations with given slopes and angles.
2:13:44 Solving equations and finding values of A and B.
2:16:27 Solving for the value of B in a given equation
2:21:23 Finding the slope of a line using two points.
2:23:53 Understanding the equations of straight lines and their intersections.
Hi sis can I ask you which and all are imp topic
Hii can we become friends ❤
@@BdbdHdbdbd-w9w Sure whts ur name?
@@SathwikRP-t6e 1)Slope of a Line 2)Different Forms of the Equation of a Line 3)General Equation of a Line 4)Angle Between Two Lines 5) Distance of a Point from a Line 6)Distance Between Two Parallel Lines [ HOPE THIS HELPS] :) All the best for your test!
@@richurushhhave you got Snapchat or Insta
1:34:12 ANSWER
X INTERCEPT: 3/2
Y INTERCEPT: -2
1:23:35 ɴᴏᴛɪᴄᴇ ʙᴀᴄᴋʀᴏᴜɴᴅ sᴏᴜɴᴅ☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️☠️
It's 12 November,2024 .lets see how many of you are watching this
😂 here 13
@@Authentic008 same
15 here 😅
nnn done
18
Only because of him..i am able to complete my ncert just one day before my exam🌻
us bro us
Was it worth it? 😢 this is the first time I'm watching his video..I'm having exam day after tomorrow and I'm scared bruh
It's 26 nov... Let's see who are watching this
I am watching now
🎉🎉🎉@@SaptarshiMandal-n4w
Kal exam hai
🖐🏻
@@kavitagiri4412🤝🏻🤝🏻
1:41:54 I just paused the video and gave it a try and BINGO!!
3x-4y+18=0
Why nobody is talking ABT his singing skill 💗
because he is a teacher
Not a singer 🙃
kyu ham padhne aye h or sir padhane 😁
dayyummmmm😂@@Anassiddiqui-u4o
what is the color of your brain ?
What colour is urs ?@@AnonymousGuy-gy5yb
ONE DAY BEFORE EXAM
IM COOKED
me rn
literally me😍
Soo me !!!😭
Ye bata ke bahut cool banana chahte ho benstokes
@@Utsav-jaiswal-4554 yh bolke tuh fool lag rha hai
Who is having paper tomorrow ☠️☠️
I have my exam today
Morning me padh raha hun
Me 😂
2x feeling like 1x 😂😂
Me😅
it must be +15/2 in 33:31 sec
I also agree
Remove that must because it is.
yes bro
2x speed pe mast samajh aa raha
Sahi batt hai
Exam ke 1 din pahle bahut badhiya se samjh me aata 2x pe 😂
Pta ni q prr mujhe to 2x ke alava abb kisi bhi speed prr smjh hi ni aata...😂
10th ki aadat 😂😂
@@gentleadi23 bhai mai to 2.5x pe aa gya hu ab
@@swoorp itni speed ka toh option hi nhi hota
sir tomorrow Is my mathematics examination and I've studied through a tons of ur videos during my preparation leave 😊😊❤❤ , I have no words to describe my gratitude towards u , and pls give me ur blessings for my tomorrow's Mathematica examination 😌🙇🏻🙏
aur kya haal hai ?
aur kitne marks aaye?
12th kaise hai?
Its 2025. Let's see how many of you are watching this video 😶😳
1:54:47 sirji ❤DOUBT❤
pls mera ek doubt Clear kardo sir Ji is question mai humlog equation nikalne ke baad Kya Y-axis Ki equation se solve karke y intercept nikalsakte hai because y axis and yeh, like y intercept Par he toh yeah Line aur y axis meet karrahe hai so that point must be its intercept/intersection and my answer is coming out to be (y=+3) and slope is 1/2. Pls reply
Did no one except me notice that in the stratification, class 9th is written instead of class 11😂😢
0:25
Ur right bro 😂
i did and was looking for comments who noticed them
32:19 the correct eqn. was 8a = 60 ... so a = 15/2
Hi
Funniest part of the video😂😂 at 7:00
1:6:39 per eq -4+20
very very thanks sir tom
orrow is my maths exam and your video is actually ver helpful ... hatts off to your hardwork
1:34:17
(2x/3-y/2) from this we get,
X(intercept)=3/2,
Y(intercept)=-2,
X is 3
@@anirbanroy3088 Noo
@@anirbanroy3088 3/2 is correct
1:6 -20 ki jgh =20 aayega left side
thank you sir for saath dene ke liye
30:15 in this question if the point can be took away from the other two points then why can't we simply let it be the mid point between those two points that is ,(7,6) and (3,4) and then use the class 10th formula to find it's coordinates.
Cuz for applying the midpoint formula or section formula it should be mentioned in the question that the points are on the same line
@lof1x343 ok
Answer is 3x-4y+8 1:06:42
Thanks Bhai
Me confused ho gaya tha
1:40:03 6x+8y+32=0
Nooo... sir is right , for parallel lines a1/a2 = b1/b2 ≠ c1/c2
jab sabhi ke ratio equal ho jate hai to vo coincidence lines ho jati h
1:00:44 sir tan 75= tan(30+45 )
2kx + hy = 3kh for q 1:25:43
1:34:13 x intercept = 3/2
Y intercept= -2
U r best teacher sir♥️🤗...all concept are crystal clear...i am coming here after seeing your seq and series one shot
Really
😂 itna mat bol
@@yash_x_editz5493 kisko bol rha haii meko ya ankita ko😐
🆔 do mai aur Crystal clr kr dunga
@@PWians122 apni janeman ko 😗
1:25:42 Answer:-2KX+HY=3HK 😊 correct na sirji 😇✔☑✅
Hy ke Sather bhi 2 ayega
HY nhi HK ke saath 3 nhi 2 aayega
2:23:23 Slope is wrong it should be -3/a-5
Fr
1:16:59 this question has 2 answers actually, one is x+y = 5 and other is y=3x/2 which is a case of 0 intercept, the question mentions that intercepts are equal, but we have to think of 0 intercept as well that is "line passing through origin" so there are 2 answers to this question unless and until it is specified that intercept is not zero
1:11:56 itna reality check bhi nhii dena thaa sir😭🤌🏻
0:47 sequence and silies 😁
1:34:17 x intercept =3/2 and y intercept= -2
49:00 nostalgia hitting so hard... 🥺
💯💯
20:05 sir area of quadrilateral is equal to (sum of area of triangles)
1:25:34 2kx+hy-3hk
Where did you get the 2
1:01:29 tan 75° is 2+√3 hoga.....by tarun sir
Straight Lines Class :- 9th ka nhi hai class :- 11th ka hai ,Thumbnail and Title need to be changed.
Abbe chutiye kya pad rha h yhi likha class 11
54:41 Line Touch Cutting On Y-axis (0,c)
Best lect of straight line on whole UA-cam fr❤👍 thanks a lottt Sir✨️
1:46:37 180+30 = 210 is the answer tan 150 is -ve
1:06:03 sir ish mai X1 aar Y1 (4,5) ko he kyu liye hum log (0,2) ko bhi tho le sakte thee question mai tho aasa kuch bola nahi thaa ke kisko Lena hai
Limits and derivations
33:24 sir your answer is incorrect sir😅
Given points A(7,6) and B(−3,4)
Let the point be P(x,0) [we know that point on x-axis is (x,0)]
So, AP=PB and
AP2=PB2
⇒(x−7)2+(0−6)2=(x+3)2+(0−4)2
[Distance between two points is given by distance formula, d=√(x2−x1)2+(y2−y1)2]
⇒x2+49−14x+36=x2+9+6x+16
⇒49−9+36−16=6x+14x
⇒40+20=20x
⇒x=60/20=3
Hence, point on x-axis which is equidistant from the points A(7,6) and B(−3,4) is (3,0)
yes yes
Kisi ne board nhi dekha starting Mai 11th ki jagah 9th likha hai😂😂
chomu vo chapter 9 hai
11th repet kar reha haikya
@@AnkitSingh-e3jabe chomu tu ha class ix likha ha😂
Chonge vo 11th hi likha ha😂
Vo 11th hi lika hai😅
1:25:41
Equation of the line =
2kx+hy=3kh
thankyou sir for clearing our concepts... plz upload circle chapter... as soon as possible..
1:34:13 x intercept. 3/2 y intercept 2
Conic sections ❤
imp questions
2:05:00
2:13:00(snf question)
2:14:30
2:19:49
2:23:00
2:24:00
Padle bethke
24:00 sir 28 nahi aayega? 12 ki jgh
1:43:43 pls batado do sirji😊 😅❤❤
31:55 sir one mistake .instead of 7a its -8a
Starting m sir k board per IX(9th) likha h
how many of you notice?🧐🧐
Bhai inh chizo par diyan nhi dete but aapne diya bahut acchi baat he iska matlab he aap diyan se pade honge ish chapter ko best off luck Bhai aaise hi diyan se pada karo 😊😊😊
1:51:10 since no one has written the equations for this question i will write what i got 1) x( root3 - 2 ) + y( 1 + 2root3 ) = 5 + 2root3 and 2) x( 2 + root3 ) + y( 2root3 - 1 ) = 7 + 2root3 please confirm if it is right or not
Sir please conic sections daal diye 20th se pehle, mere unit test hain
1:04:03 I remembered the trending reel of crying girl 😂😂😂😂😂😂
Cooked 🤙🏻✌🏻
U cooked or u are cooked?
@@MohanLal-z1d lol
32:45 answer galat nikal raha hai
Sir apka answer galat ha time 33:13 uss ma ➖ nahi ha
33:29 sir a ki value +15/2 aayegi kyuki minus minus cancel hojayega..
Baaki your one shots are really very helpful ❤
It's 15 December 2024. Let's see how many of you are watching this video 😂
intersect meaning
(used about roads, lines, etc.) to meet or cross each other
(सड़कों, रेखाओं, आदि का) एक दूसरे से मिलना या एक दूसरे को काटना
33:25 sir -15/2 nhi aayaga 15/2 aayaga
YSSSSSS
1:25:45 2x/3h +y/3k = 1
1:25:07 sir I just paused the video and calculated the answer as 2xk + yh - 3kh = 0 , and Now iam going to see its further solution in this video
How did you get the 2
@@infosite9787 by taking 3 common from 6kx and 3hy
nah its Kx + Hy - 3kh = 0
values of a and b were 3h and 3k respectively... and after substituting these values:
we get x/3h + y/3k =1 ....
it becomes 3kx + 3hy = 9hk
...so i don't understand how u get the "6" while taking common
@euphoriafrfr value of b is 3k/2...
39:44 i believe the angle is 60° and answer is √3 is valid too along with yours answer
This question didn't specify any quadrants and i took first quadrant
Sir please Limit ka bhi one shot dal do please ❤❤😊
1:6:39 per eq -4+20😊
Who are watching 17 nov and __________😅
1:34:13 x intercept is 3/2
Y intercept is -2
How pl tell
@@jatintattoart hello bro , here the explanation:-
4x-3y=6
Divided by 6 in both side
4x/6-3y/6=6/6
Then, 2x/3-y/2=1
You know how to solve it is the form of
x/a+y/b+c=0
Hence ,
x/3/2-y/2=1 or x/3/2-y/2-1=0
So,x intercept is 3/2
Y intercept is -2
Jo bhi x ke niche hota hai vo x intercept hota hai aur jo y ke niche vo y intercept hota hai bas x/a+y/b+c =0 condition honi chahiye.
Okk bro .😅
@@Xyzgaming411 okk broo thanks alot✨..I was confused and the day after tmr i have my math unit test..🙂
@@jatintattoart thankyou bro 🤗
39:32 but sir in the question it is not written that line is passing through origin.. So it can pass through any point on y axis... Hence.. How can you say that it will pass through the origin
Mentioned
1:11:57 💯💯
54:38 sir ji intercept refers to the dist from origin at which the line cuts the axis
kal half yearly hai .. 9ch aarhe hai .... shaam ke 6 baj rhe hai ab start kar rha hu no tesion ushank sir is here
33:22 plese correct it is (15/2,0)
Its 1st December let see who's are watching in December
Me...🖐️
1:34:15
X intercept = 3/2
Y intercept = 2
54:38
Intersection point where line cuts at y axis
Sir ji 40:26 do answer honge kyuki ek aur line aygi jo x axis se 60 degree pe hogi
It will be plus minus root3
Kis kis ko ushank sir Ashu sir k judwaa Bhai lagte h 😂😂😂😂
mujhe 😂
Abe ashu sir ke kukhke bhai hai ushank sir pagal 😊
3x-4y+c=0 ye ham pe line ki equation hai aur jab ham usme point put karenge toh mera to c=42 aa raha hai yahi ki meri line ki equation 3x-4y=42 aa raha hai?????
sir pls aap iske important questions and pyq ki video bna do
1:11:53 lekin sir mai toh padhne aaya tha 😭😭
Its 30 Nov.. Let's see that how much you are watching
Sir please ISC ke liye 11&12 ke liye koi paid ya free course launch kariye ....
Please Ashu sir aap paid hi le aaiye ISC ke liye please sir 🥺
Its 6 january 2025
Those who are watching... Give attendance
1:07:45 sirji point c na Bhi pata ho tabbhi horizontal line ka slope nikallenge with the help of two coordinate given on it and uske baad L1 perpendicular to L2 Ki condition se slope = -1 put karke slope nikallenge and then slope point form lagakar equation nikallenge 😊❤
kya is question ko aise kar sakte ki m1×m2=-1 mai m1 ki value put karke jaise DC ki slope × Ab ki slope