As you may be aware, I recently found your channel and subscribed. I come to wonder apart from all this very crucial lessons, it would be very essential for us if prepare us a video on how you manage your time. We like to know what your day looks like. I personally struggle to manage my time and seeing you doing a lot of things gives me the idea that you have a strong time management. So please give us one video of your time tricks. Thanks.
In actuality I am not as good in my time management as you think. And I have a lot of trouble with working on multiple things at the same time and dividing my time appropriately. I do work many hours per week and during the time that we were producing multiple videos per day and working multiple jobs I was working 90 hours per week, which should not be kept up for any length of time.
The friction factor is related to the resistance of air flow in a duct. The coefficient of friction is related to the friction force required to slide one object over the surface of another object.
sry quick qn. If thats the case we wont need the Reynolds number to find the friction factor right? we can just draw straight from the Relative roughness and then we can find the friction factor from there?
Not sure. It could be a factor added that is related to the viscosity of the liquid, the temperature of the liquid, or in case the units are different (it should be meters of head loss).
We’re unable to calculate velocity for Reynolds number because our velocity equation, derived from Bernoulli’s equation, includes major and minor losses and requires the friction factor, lambda. Without velocity, we can’t calculate Reynolds number, which we need to find lambda. Given that I know k/D , is there another way to determine Reynolds number so we can solve for lambda?
But what happens if the reynold's number and relative roughness intersect at a point below the lines? Like when reynold's number is 10^5 and relative roughness is 0.0001 in the diagram. How to find f then?
It wasn't meant to point to a "particular" value. It looks like it would be somewhere between 0.05 and 0.06. It was not the value that mattered but the principle that was explained.
Hello sir, I have a qs on optics The image size of a distant object as formed by a convex lens of focal length 20 cm is 1.5 cm......When a concave lens is placed between the convex lens and the image at a distance of 15 cm from the convex lens, size of the image is 1.8 cm......What is the focal length of the concave lens??? Sir plz help me with this pblm🙏
What does it indicate if experimental data gives a friction factor around 0.02 and Re number of 2x10^4? That there is error in my experimental data, (or calculations)? Or if not, how would I read the Moodys Diagram to give a value for the relative roughness?
This dude just explained what my teacher couldn't in my native language and two hours of class!!! Simply amazing, Thank you sir!!
Happy to help!
@@MichelvanBiezen Sir thanks
Once again I find myself watching this guy's video. Been watching his videos since my calc 1 days and here I am watching him again for fluids now.
We appreciate our viewers. Glad we can help.
I have never seen the lecturer as best as you.. God protect u
Been watching you Sir since my freshman year in Engineering and now i’m doing my Masters still coming back here, Thanks a ton Sir ♥️✨
That is great. Keep up the great effort on your studies! Glad we are a small part of it. 🙂
for detailing in friction factor
ua-cam.com/video/2SlpsCRjUJY/v-deo.html
The one thing I haven’t revised for my exams!! 🙏🏼🙏🏼 perfect timing
Please continue doing this series!
when i open my you tube to see lecture firstly your web appear in my window ,,,,,,,,,actually you are versatile in any science
Very nice! Concise.
Glad it was helpful! 🙂
These lessons are awesome. You take me right to the point thank you.
Thanks! Glad you found our videos! 🙂
Best teacher...he makes us clear in soo simple way 🥰🥰
Thank you! 😃 Glad you think so and that you found our videos. 🙂
This just so great, thanks a lot sir
Thank you. Glad you found it helpful. 🙂
My favorite professor ❤❤
Wow, thanks
Just love your stuff, thank you.
Thank you. Glad you do.
I have a test about this in 1.5 hours
Hope you did well on the test.
Try exam in the same time as yours
Me too😂😂😂😂😂
Wonderful 👏 👏 👏 thank you so much sir. Thanks for the time you drawn everything on the white board. I really appreciate your efforts ❤🌹
Most welcome 😊
this is the best presentation I've seen on this. makes it crystal clear even for someone studying fluid dynamics
FR
As you may be aware, I recently found your channel and subscribed. I come to wonder apart from all this very crucial lessons, it would be very essential for us if prepare us a video on how you manage your time. We like to know what your day looks like. I personally struggle to manage my time and seeing you doing a lot of things gives me the idea that you have a strong time management. So please give us one video of your time tricks. Thanks.
In actuality I am not as good in my time management as you think. And I have a lot of trouble with working on multiple things at the same time and dividing my time appropriately. I do work many hours per week and during the time that we were producing multiple videos per day and working multiple jobs I was working 90 hours per week, which should not be kept up for any length of time.
So very helpful. I'm all the way in South Africa. Thank you.
Welcome to the channel!
Great video, congrats!
Glad you enjoyed it
Thank you, sir. It was very useful
Glad to hear that
What a great teaching sir I really understand this important theory in exam and daily life
Thank you. Glad you found our videos. 🙂
Thanks a lot I'm taking my class in french but this was really helpful.
Glad it was helpful! 🙂
Great video. Thank you for taking the time.
Our pleasure!
Thank you sir...love from 🇮🇳
what is the difference between coefficient of friction and friction factor?
The friction factor is related to the resistance of air flow in a duct. The coefficient of friction is related to the friction force required to slide one object over the surface of another object.
sry quick qn. If thats the case we wont need the Reynolds number to find the friction factor right? we can just draw straight from the Relative roughness and then we can find the friction factor from there?
You see there is small curve in chart :)
Thanks for your patience and time for helping 😚 me
My pleasure 😊
In some books, i found the friction loss formula with a 4. 4fLv2/ 2g D. Why there is a 4?
Not sure. It could be a factor added that is related to the viscosity of the liquid, the temperature of the liquid, or in case the units are different (it should be meters of head loss).
when we use coefficient of friction f instead of friction factor f then we multiply 4 in the equation.
We’re unable to calculate velocity for Reynolds number because our velocity equation, derived from Bernoulli’s equation, includes major and minor losses and requires the friction factor, lambda. Without velocity, we can’t calculate Reynolds number, which we need to find lambda. Given that I know k/D , is there another way to determine Reynolds number so we can solve for lambda?
But what happens if the reynold's number and relative roughness intersect at a point below the lines? Like when reynold's number is 10^5 and relative roughness is 0.0001 in the diagram. How to find f then?
You would have difficulty of finding anything with relative roughness of 0.0001. This chart is useful for typical cases and materials.
excellent video!
thank you Professor
You are very welcome
just a clarification based on the example, should I get 0.06 as the friction factor or 0.05? Thanks in advance, Sir
It wasn't meant to point to a "particular" value. It looks like it would be somewhere between 0.05 and 0.06. It was not the value that mattered but the principle that was explained.
Nice explanation
We we don't have Reynolds no. can we find 'f' by roughness directly by drawing straight line from roughness value
If the absolute roughness is zero how I can find friction factor ???
Absolute roughness equal to zero is an unrealistic situation not expected in a real world situation. That is why the scale used here is as shown.
@@MichelvanBiezen we have smooth pipe what about rounghness to it ? Dr I see u from Arab sorry about language
thanks it was awesome. how i can find next video
You can find these videos in this playlist: PHYSICS 34.1 BERNOULLI'S EQUATION & FLOW IN PIPES which can be found from the home page of this channel
I love physics :D
how to know use turbulent or laminar flow? bcs it doesnt state in my lab report
That was helpful thanks sir🙏🇮🇳
Happy to help
thank you verey much! a very helpful video!
Glad it was helpful!
Thank you for explaining sir, I'm from India
Welcome to the channel!
@@MichelvanBiezen thank you sir
Hello sir, I have a qs on optics
The image size of a distant object as formed by a convex lens of focal length 20 cm is 1.5 cm......When a concave lens is placed between the convex lens and the image at a distance of 15 cm from the convex lens, size of the image is 1.8 cm......What is the focal length of the concave lens???
Sir plz help me with this pblm🙏
I'm so impressed you drew out that massive moody chart, man!! Thank you for your dedication and nobility!!
You are welcome. Glad you appreciate the hard work that goes into these videos. 🙂
What does it indicate if experimental data gives a friction factor around 0.02 and Re number of 2x10^4? That there is error in my experimental data, (or calculations)? Or if not, how would I read the Moodys Diagram to give a value for the relative roughness?
Superb sir👌 moody diagram 😍 love fluid behaviour 😃💝
Thanks a ton
Thx teacher
thank you prof
You are welcome
But how to do iteration???
Use interpolation as you would on any graph.
Awesome
Thankyou
Welcome
what I supposed to do when Re is so large like 80000
Its just turbulent they can go up to 10^8
@@harshbhasin760 I'm Nuclear Engineering student, so I need to know, What i must do
@@7iba384 aah understandable, don't want any nuclear plants messing up
annoys me you draw f like that. What are you a tagger?
Seems like a bit of an overreaction.
THANKS
You're welcome.