WOW!!! I am very happy I found this page. I literally sat in in class for 2 months, and could not get what the teacher was trying to explain. I watched this video and actually learned something!! I will be watching more videos every night to get better in the field. Thank you so much VIVIDMATHS- Steve K. Much appreciated.
My math teacher told me to just add 180 if we know that A is a straight line. So 130+180=310 It’s the same answer, my teacher’s way is easier but to be honest I did not understand what she was doing until I saw this video. Thanks a lot sir
I personally find bearings very easy but from talking to my classmates it seems like in general people struggle with them. I have a few easy tricks. The angle of O from A is always equal to the angle of A from O + 180. In this example, A from O is 130, so O from A is 130 + 180 = 310. You can always turn any of these questions into a set of parallel lines by making the north south lines longer, from here on rules of parallel lines apply. Eg the angle of depression of A from O is the same as the angle of elevation of O from A.
I am a civil engineering student and I found this contrast to what i have learned in surveying. What you call bearing is what we call Azimuth,while the bearing can be measured from either N or S (but have to be less than 90 deg)
Another way to think about it- You are trying to go backwards, backwards is 180°. 130° forwards, the go back to that point- turn 180, and go back in that bearing- 130°+180°= 310°
This is so helpful...I couldn't do nothing or knew nothing in bearings and now I learnt couple things just now...you are way better than my math teacher..wish u were my math teacher overall😪👍thanks thou
Hi! Thank you so much for this video - it was very helpful. I did have one question: in my textbook, it has this question, and it looks like the answer might conflict with the concepts in this video at 1:05. The question is “Stacey walks on a bearing of 90 degrees (due East) for 100 m and then on a bearing of 180 degrees (due south) for 180 m. What is her bearing from the starting point? To find this, the textbook solution is to do tangent inverse of (100/180), meaning it will find the bearing starting at her ending point rather than her starting point (which is what I think the answer should be trying to find) - am I understanding this incorrectly? Thank you!
Bearing to (which you measure) is always the reciprocal (+/- 180) of the bearing from (which you plot to determine a line of position). Two lines of position intersection locate where you precisely are.
My teacher teaches us in a fashion like N40degrees and S30degreesW but she never explained what to do when the question only says 40degrees and 250degrees without any of the N, W, E, S. For the second degree do we start from North like the first bearing or do we start from South like all the problems my teacher has given us?
Thank you for the video. Please make sure that you are using the proper terms. azitmuth is an angle from the reference direction can be anything from 0 to 360 degrees. Bearing indicates a direction of north or south or the west or east line between 90 degrees. For this problem the ACTUAL BEARNG is 50 west of north or written as N50W.
guys can you make a video about this problem: A boat leaves a port and travels 40.23 km on a bearing of N 42°E. Then the captain turns the boat 90° clockwise & travels 28.96 km on a bearing of S 48° E. a.) how far is the boat from the port. b.)what is the bearing of the boat from the port ?
+Phantom God I have a headache after thinking about that...
8 років тому+1
+[SURVIVOR115] All the 4 and 5 mark GCSE math questions are a headache. They give you so much information, you don't no jack to do! LOL. The only way to answer it is do what you know and work out the answer in puzzles. Worded questions are te only questions that mind fucks people!
Sheesh, lighten up, you navigation nerds. This is more of a class in mathematics and geometry then it is about proper navigation terms. His explanation is terrific and the final answer is correct, regardless of whether or not he uses terminology that you prefer. Most civilians use bearing and azimuth interchangeably, and most everyone always knows what they're talking about.
This video saved my life 5 years ago. Thought I’d come back here and finally thank you for helping my brain evolve in math class 💀
I wish I could say the same thing 5 years In the future. It’s currently 07:10 in the morning and I have a math test today
@@vulxh how did it go bro i have my test tmrw
This has taught me in 8 minutes what my maths teacher has failed to teach me in 8 weeks. I cannot thank you enough.
Did you listen to the teacher though?
WOW!!! I am very happy I found this page. I literally sat in in class for 2 months, and could not get what the teacher was trying to explain. I watched this video and actually learned something!! I will be watching more videos every night to get better in the field. Thank you so much VIVIDMATHS- Steve K. Much appreciated.
My math teacher told me to just add 180 if we know that A is a straight line. So 130+180=310
It’s the same answer, my teacher’s way is easier but to be honest I did not understand what she was doing until I saw this video. Thanks a lot sir
Thank you sooo much for this. I'm in the tenth grade and I learnt this topic today and I seriously did not understand. You just got a new subscriber!!
My test was Tomorrow and I had no clue of how to solve bearings and this saved my cheeks. I appreciate it man 🥰
I personally find bearings very easy but from talking to my classmates it seems like in general people struggle with them. I have a few easy tricks.
The angle of O from A is always equal to the angle of A from O + 180. In this example, A from O is 130, so O from A is 130 + 180 = 310.
You can always turn any of these questions into a set of parallel lines by making the north south lines longer, from here on rules of parallel lines apply.
Eg the angle of depression of A from O is the same as the angle of elevation of O from A.
Thanks, My exam starts in the next 4 hours
Lmao
Damn your staying up late
@@ahmednisar2359 wtf fam
How'd it go bro
I've been watching your videos all day about angle and you touch me more than my teacher ever did
You are so good at math
I am a civil engineering student and I found this contrast to what i have learned in surveying. What you call bearing is what we call Azimuth,while the bearing can be measured from either N or S (but have to be less than 90 deg)
Seems interesting
Same
I was having a very hard time understanding bearings God bless you cuz u saved a life
your voice is magic to listen to
Lol
Thats right
This was so helpful thank you! I was struggling to understand the whole a from b stuff
Wow I wish this was my online math teacher! He explains super well...
I'm in grade 8 and I now understand what my teacher was saying thanks a lot sir
I thank you sir. Just understanding dms
Another way to think about it-
You are trying to go backwards, backwards is 180°. 130° forwards, the go back to that point- turn 180, and go back in that bearing- 130°+180°= 310°
This is so helpful...I couldn't do nothing or knew nothing in bearings and now I learnt couple things just now...you are way better than my math teacher..wish u were my math teacher overall😪👍thanks thou
Thank you! I just experienced enlightenment!:-).
Hats off to you sir.
Thank you so much sir! ✨
Thanks for this teaching
you are very good math teacher it helped me on my test
You got a new subscriber!!!
This was taken when I was born 😭😭 saved me in my geography test 12 years later
Nice and like your voice man
Hi! Thank you so much for this video - it was very helpful. I did have one question: in my textbook, it has this question, and it looks like the answer might conflict with the concepts in this video at 1:05. The question is “Stacey walks on a bearing of 90 degrees (due East) for 100 m and then on a bearing of 180 degrees (due south) for 180 m. What is her bearing from the starting point? To find this, the textbook solution is to do tangent inverse of (100/180), meaning it will find the bearing starting at her ending point rather than her starting point (which is what I think the answer should be trying to find) - am I understanding this incorrectly? Thank you!
Yes it's correct, the tangent inverse of 100/180
woooooow thanks this video is the best one ive see out there which didnt make me more confused it rly helped thanks!!!!
Thank you for letting me know it was helpful
amazing lesson. Thank you
really helped no better video I could find
perfect explanation 👍🏼
I have solved this problem before him in about 3 minutes but its good for those who need to understand this in detail
Thank you sir this was totally helpful😊😊!!
Glad it was helpful!
Ik more simple method then this one😂😂 but good job sir 👍
Pauly Shore is a great teacher...!!!
Thanks U really helped me!!!!
Bearing to (which you measure) is always the reciprocal (+/- 180) of the bearing from (which you plot to determine a line of position). Two lines of position intersection locate where you precisely are.
This is very helpful , and can someone get a vectors video.
My teacher teaches us in a fashion like N40degrees and S30degreesW but she never explained what to do when the question only says 40degrees and 250degrees without any of the N, W, E, S. For the second degree do we start from North like the first bearing or do we start from South like all the problems my teacher has given us?
Thank you
Thank you!! This was helpful.
Does minutes relate to the bearing of the line? Or the distance???
Thanks a million! My textbook was a bit confusing.
😂😂
thanks my guy. Really helpful
Thanks!
But are those for the same? like from a to b is the same from b to a
??
You have to put crosshairs, not necessarily
Thank you for the video. Please make sure that you are using the proper terms. azitmuth is an angle from the reference direction can be anything from 0 to 360 degrees.
Bearing indicates a direction of north or south or the west or east line between 90 degrees.
For this problem the ACTUAL BEARNG is 50 west of north or written as N50W.
So would it be the same procedure if u wanted to go from A to O?
You saved my life
NICE EXPLANATION...
i think there is something medically wrong with my brain- i have no idea what hes saying, im an english student btw
Ur so helpful guys keep doing what u do
great help thanks
Awesome!Tnx for helping
thanks soo much
Thank you, my exam is tomorrow and I was having trouble with this
really interesting topic
Dawg thank you so much
Best explanation , so helpful
clarified my misconceptions in less time.
hahahahahhah
I love your videos! Great stuff.
what do you do when forward bearing is 180degrees and you want find backward bearing
Finally a good vedio
My teacher literally has like three slides of notes talking about random stuff when she was supposed to be teaching bearings I’m like……teach!
guys can you make a video about this problem: A boat leaves a port and travels 40.23 km on a bearing of N 42°E. Then the captain turns the boat 90° clockwise & travels 28.96 km on a bearing of S 48° E.
a.) how far is the boat from the port.
b.)what is the bearing of the boat from the port ?
+Phantom God I have a headache after thinking about that...
+[SURVIVOR115] All the 4 and 5 mark GCSE math questions are a headache. They give you so much information, you don't no jack to do! LOL. The only way to answer it is do what you know and work out the answer in puzzles. Worded questions are te only questions that mind fucks people!
yup
+Genos Demon Cyborg do you have to swear. its not everyday. no offence
49.57m
This helped a lot😄😄😄😄😄😄😄😄😄😄
hello sir ,,can you please discuss about prominent bearing?
thank you for this information .
You are welcome
Thank you for the help
We need to see the question
Very good video helped alot
Allot more easier than your formal class on bearing tnks
Thank you (: super helpful
I now know how to do bearings thanks man :)
i can now do my homework
N 310° W
Is this the correct way to write the angle
we should just add 180 to thee bearing to get the back bearing. RIGHT?
tysm 🙌💕
Wow this really hepled a lot !! Thank u so much !!
What is this 1st, 2nd and 3rd stuff?
"Welcome to Dr Sheldon Cooper's fun with Flags"😂😂😂😂
superb way on explaining ... you are great mate
This is very helpful.
You can solve it easier! Extend the line backwards in the first figure. 130+180=310
love your videos!! You explain so well... :)
THANK YOUUUU!!!!!!!!!!!! Now I can solve dem questions so I get dem full markz U kno
thankyou! very very helpful
Thank you so much this helped me so much especially one day before the final exam
Thank a lot
Any reason why it should not be 270 + 40 degrees?
why bearing is always range from 0- 90?
Well done tell more 🙏🙏🙏👍
Nobody: ....
I like how his magnetic ruler sticks to the white board X) lol
This lad is a legend 🙏🏻this helped so much
the final answer is the azimuth, not the bearing.when is the producer of the video going to correct it?
I was thinking the same thing
Sheesh, lighten up, you navigation nerds. This is more of a class in mathematics and geometry then it is about proper navigation terms. His explanation is terrific and the final answer is correct, regardless of whether or not he uses terminology that you prefer. Most civilians use bearing and azimuth interchangeably, and most everyone always knows what they're talking about.
Can you also , say N 50 degrees W?
Thankyou love
this helped me thanks! My textbook explanation was so god damn confusing
can someone tell me the question he is answering
how did you get 130
Thanx I was struggling with bearings