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  • @lifejournies3070
    @lifejournies3070 7 років тому +39

    i have a test of probability, and this 8 minutes video helped me sooo much, thank you so much mr. i really appreciate your effort :)

    • @MathematicsTutor
      @MathematicsTutor 7 років тому +6

      Thanks for appreciation and All the Best!

    • @LE-PUNK26
      @LE-PUNK26 Рік тому

      Tomorrow i have 😊

    • @tholiwebanda8063
      @tholiwebanda8063 Рік тому

      @@MathematicsTutor i really appreciate, well explained Mr

    • @aimansaleem636
      @aimansaleem636 Рік тому

      Yes...and i have my homework 🙂👍😂

  • @mayanjatimothy5165
    @mayanjatimothy5165 2 роки тому +6

    Probability has been disturbing me but this video has opened up my eyes
    Thank you so much

  • @abellarjeahbearl2632
    @abellarjeahbearl2632 7 років тому +4

    its a huge help for my acads sir! 😄 thanks a lot , God bless you

  • @xuns5268
    @xuns5268 4 роки тому +3

    This was really helpful! Thanks man!

  • @weaponizedhyperfocus
    @weaponizedhyperfocus 4 роки тому +3

    Thank you! That's an amazing method!

  • @regina9453
    @regina9453 5 років тому +2

    This really helped me a lot! Thank you for sharing :)

  • @hadasahfaithlacson345
    @hadasahfaithlacson345 4 роки тому +1

    Thank you 😊 you're video is of a great help for a student like me.

  • @nanditaarora4295
    @nanditaarora4295 Рік тому

    This has helped me a lot. Thank you so much

  • @maikaprincessceledonio5574
    @maikaprincessceledonio5574 3 роки тому +1

    thank you so much, this helps a lot!

  • @blastoff_show
    @blastoff_show 7 років тому +1

    finally a table that makes perfect sense!

  • @sandragamarano4419
    @sandragamarano4419 Рік тому

    Great explanation!! Well done!

  • @vktengizik9916
    @vktengizik9916 3 роки тому +1

    Great video, simple as it could be.

  • @davidphilips7193
    @davidphilips7193 Рік тому

    This 8minls video really helped me I've been battling with probability since I was in secondary school

  • @user-to3fx2do4d
    @user-to3fx2do4d 10 місяців тому

    Thank you sir.
    Many people get the following question wrong, so please explain.
    [Question]
    Find the probabilities that the following events will occur when two dice are rolled.
    ①Both show odd numbers
    ②One shows odd number and another shows evenn number
    ③Both show even number
    P(E):the probability that event E occurs.
    【Distinguishable dice A and B】
    (the number that dice A shows,the number dice B shows):event
    If we only judge whether the numbers indicated by the dice are odd or even, the following four events will occur.
      (odd,odd) (odd,even)
      (even,odd) (even,even)
    If each event occurs with equal probability, the probability is 1/4.
    Therefore, P(①)=1/4, P(②)=1/2, P(③)=1/4 (1)
    If we judge the number(1,2,···,6) indicated by the dice ,the following 36 events will occur.
    (1,1), (1,3),(1,5) (1,2),(1,4),(1,6)
    (3,1), (3,3),(3,5) (3,2),(3,4),(3,6)
    (5,1), (5,3),(5,5) (5,2),(5,4),(5,6)
    (2,1), (2,3),(2,5) (2,2),(2,4),(2,6)
    (4,1), (4,3),(4,5) (4,2),(4,4),(4,6)
    (6,1), (6,3),(6,5) (6,2),(6,4),(6,6)
    If each event occurs with equal probability, the probability is 1/36.
    Therfore
    P(①)=9×(1/36)=1/4, P(②)=18×(1/36)=1/2, P(③)=9×(1/36)=1/4 (2)
    (2) matches (1).
    【Indistinguishable two dice】
    (odd,even)is the same event as(even,odd).
    Thererore, if we only judge whether the numbers indicated by the dice are odd or even, the following three events will occur.
      (odd,odd)
      (even,odd) (even,even)
    If each event occurs with equal probability, the probability is 1/3.
    Therefore
    P(①)=1/3, P(②)=1/3, P(③)=1/3 (3)
    (1,3) is the same event as (3,1).
    If we judge the number(1,2,···,6) indicated by the dice ,the following 21 events will occur.
    (1,1)
    (3,1), (3,3)
    (5,1), (5,3),(5,5)
    (2,1), (2,3),(2,5) (2,2)
    (4,1), (4,3),(4,5) (4,2),(4,4)
    (6,1), (6,3),(6,5) (6,2),(6,4),(6,6)
    If each event occurs with equal probability, the probability is 1/21.
    Therefore
    P(①)=6×(1/21)=2/7, P(②)=9×(1/21)=3/7, P(③)=6×(1/21)=2/7 (4)
    (4) contradicts (3).

  • @lishadavids4093
    @lishadavids4093 Рік тому

    Thank you, very clear.

  • @rebeccajohn8672
    @rebeccajohn8672 5 років тому +7

    wow, this turned out to be so easy!

  • @colandrea5947
    @colandrea5947 7 років тому

    thamks soooo much, you made this soooo easy!

  • @arafatbaunto4068
    @arafatbaunto4068 5 років тому +1

    Very clear explanation. !!

  • @sharonportocarrero6806
    @sharonportocarrero6806 5 років тому

    thank you so much, hope you keep doing videos

  • @indaymayangchannel2164
    @indaymayangchannel2164 3 роки тому +1

    Now I indrestrand... Thankyou 🙋💕
    I thought it so hard to understand

  • @Hamzakhan-tb8nr
    @Hamzakhan-tb8nr 3 роки тому +1

    Great Job !
    Thanks Appreciated 😘

  • @MulindwaJoy-zo4tz
    @MulindwaJoy-zo4tz Рік тому

    Thank you sir I have really understood that concept

  • @hydersunfearless2519
    @hydersunfearless2519 3 роки тому +1

    Thanks man, would you mind solving a level stats past papers?

  • @ula58
    @ula58 9 років тому +1

    thank you for your video lesson:)

  • @mediknowz
    @mediknowz 5 років тому +1

    this is so informative thanks

  • @renxzkie
    @renxzkie 3 роки тому +1

    It helps me a lot to my activity thank you

  • @jasmin29495
    @jasmin29495 7 років тому +2

    thank you so much, keep making helpful videos like this :)

  • @meshm4087
    @meshm4087 7 років тому +2

    why 6 raws and com for the table and if its 3 or more what should we do ?

  • @HouGijock
    @HouGijock 9 місяців тому

    Thanks a lot sir 🙏

  • @ceciliaacevedo2005
    @ceciliaacevedo2005 9 років тому +3

    i never understood probabilities until now. this really helped

    • @MathematicsTutor
      @MathematicsTutor 9 років тому +1

      Cecilia Acevedo Thanks

    • @MathematicsTutor
      @MathematicsTutor 9 років тому +1

      Cecilia Acevedo It encourages me to share more videos and make mathematics simple and interesting.

  • @khanxxakeerkhan8300
    @khanxxakeerkhan8300 5 років тому +1

    Thank you so much sir nice lecture

  • @BigDaddy-vc7nc
    @BigDaddy-vc7nc 4 роки тому +1

    Hey man I need help
    How to make a tree diagram of 2 dies rolled? Please help

  • @kvngabelworld9834
    @kvngabelworld9834 9 місяців тому

    Thanks so much ❤

  • @m.almotawaqtr4843
    @m.almotawaqtr4843 8 років тому +4

    thanks a lot for the lesson, it is easy and so rationale for slow minded like me :)))

    • @MathematicsTutor
      @MathematicsTutor 8 років тому +2

      Feel free to post questions and ask for help any time. Thanks

  • @arjunghimire1257
    @arjunghimire1257 6 років тому +1

    great explanation

  • @Chicken_9119
    @Chicken_9119 Рік тому

    thank u sir :) very helpful video

  • @floppy008
    @floppy008 6 років тому +2

    OMG!!! Thank you!!!! NOW I ALREADY ABOUT THE SUM OF 7

  • @marrioaloysius9900
    @marrioaloysius9900 7 років тому +1

    Thank you very much! The video was really helpful

  • @welfredavictor5716
    @welfredavictor5716 3 роки тому

    Thanks Ser. Anil Kumar it's help me a lot 👍👍👍👍💖💖💖👏👏👨‍🏫👨‍🏫👨‍🏫👨‍🏫👏 😍😍

  • @aaliyahjohn7694
    @aaliyahjohn7694 4 роки тому +1

    This was very helpful. God bless you❤️✊

  • @ednasoriano5153
    @ednasoriano5153 3 роки тому

    thank you so much!!

  • @lisar5676
    @lisar5676 2 роки тому

    Thank you!!!

  • @johnnewman3221
    @johnnewman3221 6 років тому +1

    super, i need a solution for this problem, a pair of dice rolled once. let x be the random variable whose value for any out come is the sum of the two numbers on the dice, find P(3

  • @vishnuakshaya4401
    @vishnuakshaya4401 4 роки тому +1

    Wow it's helpful

  • @raufge
    @raufge 7 місяців тому +1

    hy sir anil kumar kindly guide me about(probability of ace drawing when die thrown twice)

  • @ndymthembu
    @ndymthembu 2 роки тому

    Thank you so much sir

  • @tholiwebanda8063
    @tholiwebanda8063 Рік тому

    Thank you so much

  • @maddykhan9024
    @maddykhan9024 Рік тому +1

    Shukriyaaaaa sir gg bhot bhot You're just an amazing teacher God bless you .Thankuee so muchhh .....

    • @MathematicsTutor
      @MathematicsTutor Рік тому

      Thanks. Playlist for you: ua-cam.com/video/YxkOuAm3VE4/v-deo.html

  • @Black-xy4pj
    @Black-xy4pj 2 роки тому

    Thanks sir 🙏🏾

  • @danielagaudio2508
    @danielagaudio2508 4 роки тому +1

    this helped me a lot thanks so much

  • @DivineObasuke
    @DivineObasuke 4 місяці тому

    What is the probability of getting two odd numbers

  • @giulcg
    @giulcg Рік тому

    awesome! Thanks

  • @sushiyama1
    @sushiyama1 5 років тому +1

    Thank you sir

  • @viswanathanpr9443
    @viswanathanpr9443 Рік тому

    Thankyou very much.
    Chennai.

  • @sirangle2388
    @sirangle2388 Рік тому

    Wow bravo ,thanks sir

  • @mubinajamili5453
    @mubinajamili5453 5 років тому +1

    It is useful for as thank you so much

  • @basantabudhathoki3084
    @basantabudhathoki3084 3 роки тому

    Thank you

  • @bmgaming510
    @bmgaming510 2 роки тому

    Sir loveeee uuuu so much😍

  • @veynalmandelawe1193
    @veynalmandelawe1193 7 років тому +2

    wow, wonderful explanations. Thank you so much

  • @arkabhattacharjee3386
    @arkabhattacharjee3386 6 років тому +2

    Thanks

  • @h3mdan677
    @h3mdan677 8 років тому +2

    thank you ❤

  • @privilegemahuma6182
    @privilegemahuma6182 8 років тому +2

    thank you very much guru

  • @aayanmoledina1587
    @aayanmoledina1587 6 років тому +2

    Thanks a lot you really helped me study for my test

  • @festusfunmi2912
    @festusfunmi2912 2 роки тому

    But 3, can also go into 15and36
    Or there no need to divide .
    In number two question

  • @fakharabbasabbas9619
    @fakharabbasabbas9619 4 роки тому +1

    Very nice

  • @khristinec.lumbis1916
    @khristinec.lumbis1916 2 роки тому

    What about if P(0)?

  • @ayeshaanjum5592
    @ayeshaanjum5592 4 роки тому +1

    good lect

  • @samch2589
    @samch2589 4 роки тому +1

    Sir jo hmy parhya gya tha us mai at least 7 k keay prob=21/36 the

  • @mikebenchmarks9767
    @mikebenchmarks9767 2 роки тому

    THANKS

  • @saritaevane4558
    @saritaevane4558 6 років тому +1

    Thank u sir..

    • @MathematicsTutor
      @MathematicsTutor 6 років тому

      Thanks for appreciation. Feel free to post questions.

  • @pkgamerzyt4822
    @pkgamerzyt4822 2 роки тому +1

    Watching now

  • @Eyebroooo
    @Eyebroooo 3 роки тому +1

    thanks baby bro

  • @dipakshelke5517
    @dipakshelke5517 Рік тому

    Nice sir

  • @Nature.scenes0
    @Nature.scenes0 2 роки тому +1

    Legends in 2022

  • @selmamohamed4149
    @selmamohamed4149 8 років тому

    Nice

  • @simphiwetshabalala9528
    @simphiwetshabalala9528 5 років тому +2

    u just broke a mountain into soil particles in a blink of an eye

  • @sazsquad7147
    @sazsquad7147 7 років тому

    but Which totals have the highest and lowest probability of occurring

    • @MathematicsTutor
      @MathematicsTutor 7 років тому

      Lowest probability will be Zero and the Highest will be 1 (100%).
      Sum less than 1 will give the lowest probability and Sum greater than 1 will be highest.

    • @sazsquad7147
      @sazsquad7147 7 років тому

      thanks

  • @ngbeyond6406
    @ngbeyond6406 5 років тому +1

    Sir it's awesome...
    But what with three dice! is there any trick for it?

    • @MathematicsTutor
      @MathematicsTutor 5 років тому

      Thanks for the request. Here is an example with 3 dice: ua-cam.com/video/gWJDSzsJhq4/v-deo.html
      You can search my videos by Anil Kumar Topic example , anil kumar three dics
      Thanks

  • @deepakpuri3109
    @deepakpuri3109 6 років тому +1

    Sir why dint you simplify 15/36 = 5/12

  • @LianXinHua
    @LianXinHua 4 роки тому +1

    I slapped my dumb self for not realizing how easy it is
    Thanks a lot mr. now I can give my exam in peace
    😇

  • @ArunKumar-ng7bn
    @ArunKumar-ng7bn 6 років тому +1

    to sir ek bar Bina table ke bata digiye

  • @thegreatveteran6575
    @thegreatveteran6575 6 років тому +1

    Thanks. .....please sum of 7 I didn't get it. ....
    I thought it might be 42/36
    But still please help me understand thanks again and again

    • @MathematicsTutor
      @MathematicsTutor 6 років тому +1

      As you can see in the table created for the sum there are 6 ways the sum of two dice can be 7
      There are in all 36 ways of adding numbers of two dice
      Probability is ratio of Favourable and Total.
      Probability can never be more than 1.
      Hope that helps.
      Thanks

  • @ArunKumar-ng7bn
    @ArunKumar-ng7bn 6 років тому +1

    ager sir table nhi banay to keya nhi hal hoga

    • @MathematicsTutor
      @MathematicsTutor 6 років тому

      alag alag tarika se savall ka hal ho sakta hai. Table jaroori nahi. Dhanyavaad!

  • @4504595
    @4504595 8 років тому +1

    I don't know why it bothered me so badly that you didn't reduce 15/36, while the other ratios got that reduction love.
    I guess I am just easily bothered by unimportant things.
    Thanks for the video!

    • @MathematicsTutor
      @MathematicsTutor 8 років тому +1

      Thanks for pointing that out. I should have reduced it to 5/12 as has been done for the others. I highly appreciate and will incorporate the correction in the video also. Thanks

  • @AnKit-bs3oy
    @AnKit-bs3oy 2 роки тому

    Its so easy

  • @mihirshah8955
    @mihirshah8955 Рік тому +1

    Wtf is this .... U r just counting the elements in the set..... It is not gonna help if the set is not a perfect square or its very large

  • @orlaklassen6355
    @orlaklassen6355 2 роки тому

    You made a mistake? You totally left out the probability of rolling a 6???? WHY????????????? Didn't you mean Probability of rolling a dice with a value of LESS THAN 7????????????

  • @amarjeetsaini7110
    @amarjeetsaini7110 4 роки тому +1

    Thanks sir

  • @nursebrooks3237
    @nursebrooks3237 6 років тому +1

    Thank you

  • @praveenmalik5228
    @praveenmalik5228 7 років тому +2

    Thanks sir