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Thank you professor. It was really helpful 🙂
You are welcome!
thank you this question ass it came in my school exam😀
Thank you
Thanks
thank you, sir
Why not use tabular method?
yeah tabular is way faster, I would totally use tabular alsoI only did parts for the video, to show the process, but yeah, tabular is WAY better!!
_1/2 cos2x+1/4 sin2x
helpful❤️❤️❤️❤️
isn't dv sin(2x)? so should you multiply sin(2x)*dx for th the second part or am i missing something
my bad realized my mistake
it's du bruhh
a huevo gracias
integral X^sin(2x) dx=[[[ sin(2x) X ]]=[[[ sin2x^x+cos2x ^x=X ]=[[si2x=X- xcos2x]]=[[ poversijos[X=xcos2x ]=[[ cos2x= 1 ] =[sin2x=O ]=[ nulinis Laipsnije Taip tad | 2x= 2Pik]=[ X=Pik]=[ k=1 X=4 ,
If we had x^-1 * sin(2x) , how would it be?
nice ty
Such a mess !!!
Thank you professor. It was really helpful 🙂
You are welcome!
thank you this question ass it came in my school exam😀
Thank you
Thanks
thank you, sir
Why not use tabular method?
yeah tabular is way faster, I would totally use tabular also
I only did parts for the video, to show the process, but yeah, tabular is WAY better!!
_1/2 cos2x+1/4 sin2x
helpful❤️❤️❤️❤️
isn't dv sin(2x)? so should you multiply sin(2x)*dx for th the second part or am i missing something
my bad realized my mistake
it's du bruhh
a huevo gracias
integral X^sin(2x) dx=[[[ sin(2x) X ]]=[[[ sin2x^x+cos2x ^x=X ]=[[si2x=X- xcos2x]]=[[ poversijos
[X=xcos2x ]=[[ cos2x= 1 ] =[sin2x=O ]=[ nulinis Laipsnije Taip tad | 2x= 2Pik]=[ X=Pik]=[ k=1
X=4 ,
If we had x^-1 * sin(2x) , how would it be?
nice ty
You are welcome!
Such a mess !!!