Equations of Motion | Easy to Difficult Questions | Grade 9 | SHIKHAR 2024 |
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- Опубліковано 6 чер 2023
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I was not avlble to attend it live..but watched it later..Thank You Sir For this session 😊😊
Homework..
1. B.1km/h
2. 7.5 secs
1km kaise solution please
It is so helpful guys for those who all are preparing for examination then must watch
We can do the 4th question with only one equation
S=Vt-1/2atsquare
By substuting values
S=(0)t - (-3) x 16/2
S= 24 m
Those who did by using this 😅
👇
Homework Answers:-
1) option b 1km/s
2) final v=15ms-¹ , intial velocity=0 and time =2ms-²
Since acceleration= change in velocity or time (a=(u-v)/t
By putting all the values 2= (15-0)/t
t= 15/2=7.5 seconds Hence , Police officer will match the speed of motorist in 7.5seconds
I couldn't come in yesterday's class 😔
@@afraa76 don't be sad you can watch recorded session too 😊
Thanks for the session sir!! 😄 Please bring some more sessions on numericals because this chapter needs more practice😅😃
🔴 HOMEWORK:-
QUESTION-1:03:19
ANSWER: For police officer=
U= 0, V=15, A=2,T=?
T= v-u/a
Or, 15-0/2
Or, 15/2= 7.5 seconds(answer)
Question 8 ( 48:02 )
Solution-
For first 4sec,
T=4 , s=24 , acceleration= a, initial velocity= u
We can use 2nd eq. In this condition.....
2nd eq. = UT+1/2at²=s
Or, Ux4+1/2xax4²
Or, 4u+1/2xax16
Or, 4u+8a=24
Or, u= (24-8a)/4....... (First part)
For next 4 seconds,
T= 4+4= 8sec.
S=24+64=88
Acceleration=a
Initial velocity= u
We can use 2nd eq.
S=ut+1/2at²
Or, RHS= 8u+1/2xax8²
Or, 8u+1/2xax64
Or, 8u+8a= 88
Or, u= (88-32a)/8...... (Part 2)
NOW, IF WE NOTICE... WE HAVE PART 1 AND 2 WITH SAME L. H. S...
By comparing,
Part 1=part 2
Or, (24-8a)/4=(88-32a)/8
After solving it, we will get a=2.5km/s²
WE HAVE A=2.5
NOW, WE CAN PUT IT IN ANY EQUATION, BECAUSE WE DON'T HAVE TO FIND ACCELERATION, QUESTION IS ASKING FOR INITIAL VELOCITY....
after putting it in any of two equations ( 4u+8(2.5)=24 or in 8u+32(2.5)=88)
We will get the same answer .... That is 1...
Thus, answer is option b...1
How can we solve 1st H.W question pls tell me it's little confusing 😐 48:08
And BTW you have written T = v-u/t instead of v-u/a 😀
@@M.LifeE.2007 hey, thanks for correcting my mistake 😃
Answer-
For first 4sec,
T=4 , s=24 , acceleration= a, initial velocity= u
We can use 2nd eq. In this condition.....
2nd eq. = UT+1/2at²=s
Or, Ux4+1/2xax4²
Or, 4u+1/2xax16
Or, 4u+8a=24
Or, u= (24-8a)/4....... (First part)
For next 4 seconds,
T= 4+4= 8sec.
S=24+64=88
Acceleration=a
Initial velocity= u
We can use 2nd eq.
S=ut+1/2at²
Or, RHS= 8u+1/2xax8²
Or, 8u+1/2xax64
Or, 8u+8a= 88
Or, u= (88-32a)/8...... (Part 2)
NOW, IF YOU NOTICE... WE HAVE PART 1 AND 2 WITH SAME L. H. S...
By comparing,
Part 1=part 2
Or, (24-8a)/4=(88-32a)/8
Now you just have to solve equation....
After solving it, you will get a=2.5km/s²
WE HAVE A=2.5
NOW, YOU CAN PUT IT IN ANY EQUATION, BECAUSE WE DON'T HAVE TO FIND ACCELERATION, QUESTION IS ASKING FOR INITIAL VELOCITY....
after putting it in any of two equations ( 4u+8(2.5)=24 or in 8u+32(2.5)=88)
You will get the same answer .... That is 1...
Thus, answer is option b...1km/s
You will not get this question untill you try😃 so , try this once yourself:)
@@astha-- thank you 😊 so much that you solve and convence me, ʘ‿ʘ
Thank you 😊 again 🤗
@@M.LifeE.2007 that's my pleasure ☺️
Thanks for the solution astha🤜🏻🤛🏻
What is the short method to solve question number 7?
2:20
Final velocity v = 15 m s − 1 Initial velocity u = 0 m s − 1 Acceleration a = 2 m s − 2 Since, acceleration = change in velocity/time a = ( v − u ) / t Substituting values 2 = ( 15 − 0 ) / t t = 15 / 2 = 7.5 s e c o n d s
TYSM SOO MUCH SIR, NOW I'VE GAINED CONFIDENCE IN DOING NUMERICALS MUCH AND EVERRR... 💯
Sir please gave solution the solution of questions 8 48:07
⭐Homework
1. 1m/s
2.7.5second
By Jagdeep Singh Sidhu
😊😊
Thankyou sir for taking a session on numericals 😃
It's so helpful for our practice ✨
Can anyone give me the explanation of the question 8
Amazing session
Hw
v=u+at
0=15+2×t
t=15/2
t=7.5seconds
1. 1km/sec
2. 7.5sec
H. W
Sir mujhe kuchh smjh nhi aya mai kya karu??
sir , I can't understand the 4th question in medium level
Homework 7.5 sec ans
Thank you for the session sir,I need a bit practice to clear my understanding
Hw)
1)1m/s
2)7.5sec🎉🎉
For 5th question we can use. S=(u+v÷2)×t one try sir
5.question in minti I found it difficult
Thank you Saurabh sir for this amazing practice session!😃😃😃
Homework Question Answer:
(1) 1km/s
(2) The police will match the motorcyclist's speed in 7.5s
1km kaise ?? Solution please
@@kiran_198 First use the Second equation of motion where s=24km, t=4s
You will get an equation: 24=4u+8a...(i)
Again use the Second equation of motion
for the total distance and total time (s=88km and t=8s)
You will get an equation: 8u+32a...(ii)
On solving (i) and (ii) we get
u=1m/s
Thus, initial velocity is 1km/s
@@Avni-447 thanks sis ❤️
please change the class time
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Home work ans
Sorry i didn't understand the first one i will try after some time meanwhile the second one is u=0 a=2m/s sq v= 15m/s so using equation one we can solve it
V=u+at
15=0+2×t
15=2t
t=15/2
t=7.5 seconds
-Meenu raj ❤😊
I hadn’t understood 😢
48:19
Sir Can u please tell that in medium level Q5 in Second equation why u not write 10 as the equation is s=ut+1/2at² so the value will place is o ×10+1/2×10²but u wrote o×1/2×2×10²...sir please tell where i m doing Mistake...its helpful session thank you byjus for such an amazing teacher 👍
0×10=0 na
😮
Bohot accha tha sir
Can we take g=9.8m/s also?
Yes
Hey had mentioned it in question 10m/s (it’s a condition) so not 9.8
@@user-zk5rm1ep4nwe can’t (for this question) -_-
😊 11:17
Sir 48:08 question number 8
24:31 Bro how are you getting 24 wthhh
If you use the second equation you see there is plus after UT but in retadation it’s minus because it’s a negative force (now try it) 😊
Sir mujhe difficult part nhi aa rha h..
Thanks for this amazing session.🙂
I am not able to attend the classes live as I have my tuitions during the same time. 🙁
📖HW-
1) I am not able to solve this till now.🤔
2) v for motorcyclist= 15m/s
u for police= 0
a for police= 2m/s²
required v by police= 15m/s
Applying 1st equation
t= (v-u)/a =>t= (15-0)/2
t=7.5sec😇
Please bring more sessions on equations of motion, please🙏
2:40 2:41 2:42
sir 4 question to bina u find ke hi agaya
Omg main aaisa hi kuch dondh rahi thi
I think u all searched the question from Google and just typed here to make urself homework superstar i don't think so that this question was easy
C
A) 1 km/ hr or 1km / sec 😢(CONFUSED) 😢
B) 7.5sec
😀 🎉
Sir why are you explaining the answers in speed not clearly . Its hard to understand😭😭😭😭
Motta punda sunny miru
hw question
given
u=0m/s
t=?
a=2m/s square
v=15m/s [ as the police officer want reach the speed of motorist ]
using- v=u+at
15=0+2*t
15=2*t
t=15/2
=7.5 sec
thanks a lot for the session sir .
You are wrong
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