It's much faster to calculate bc/ab=c/a=200/100=2, so c=2a. As ca=300, we find that 2a²=300, so a²=150, so a=±sqrt(150)=±5*sqrt(6) As c=2a, we find that c=±10*sqrt(6) As ab=100, we find that b=100/a=100/±5*sqrt(6)=±20/sqrt(6)=±20*sqrt(6)/6=±10*sqrt(6)/3 So a+b+c=±sqrt(6)*(5+10/3+10)=±55/3*sqrt(6) So, there are 2 answers. You forgot the negative one -55/3*sqrt(6)
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ab*bc*ca=(abc)^2=6*10^6 abc=1000sqrt(6) = 1000s6 abc/ab=c=10s6 abc/bc=a=5s6 abc/ca=b=10/3*s6 a+b+c=55/3*sqrt(6) Basic algebra: year 7. In reach of year 9!
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It's much faster to calculate bc/ab=c/a=200/100=2, so c=2a.
As ca=300, we find that 2a²=300, so a²=150, so a=±sqrt(150)=±5*sqrt(6)
As c=2a, we find that c=±10*sqrt(6)
As ab=100, we find that b=100/a=100/±5*sqrt(6)=±20/sqrt(6)=±20*sqrt(6)/6=±10*sqrt(6)/3
So a+b+c=±sqrt(6)*(5+10/3+10)=±55/3*sqrt(6)
So, there are 2 answers. You forgot the negative one -55/3*sqrt(6)
thank you so much
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ab*bc*ca=(abc)^2=6*10^6
abc=1000sqrt(6) = 1000s6
abc/ab=c=10s6
abc/bc=a=5s6
abc/ca=b=10/3*s6
a+b+c=55/3*sqrt(6)
Basic algebra: year 7.
In reach of year 9!
You forgot all negative solutions because abc=±1000*sqrt(6)
ok
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That actually seems easy. The answer is 1/3(55*sqrt(6))
ok