its simple. The reason behind the decreasing delta angle is the increase in the magnitude of the Ea to maintain the Ea*Sin(delta) constant at every instant. And also when the field becomes stronger then then the locked-up becomes more stronger and then load angle=delta angle reduces.
Sir , as you told that as"If" increases , "Ea" also increases, so to maintain "Ef *sin (delta)" constant.....delta value has to be decreased to reduce overall "sin(delta)".
When motor was in lag section, the inductive reactance was more due to which the Ia lag Ea by larger angle and angle between Ea and Estat is also large, as the field excitation increases stator inductive reactance decrease, so theta decrease which results in decrease of the angle between Ea and Estat.... Answer with reference to "4 Equivalent circuit of synchronous generator 7:00 "
Practically..if field curr increases the field get stronger and the attraction between rotor and stator poles increases...which tends to pull the rotor to make rotor field axis as close to stator rotating field axis and the angle between them viz delta reduces.....well I think so..i might be wrong...if it is wrong please correct me...I'll be thankful..😊
sir I think as the motor moves from lagging to leading it means reactive power consumption by the motor decreases so to satisfy this condition delta need to decrease??
If in a synchronous motor driving mechanical load and drawing current at lagging power factor from constant voltage supply if field excitation is increased then its power factor become ???
You can find the DC machine course, and all the other courses in the playlist section : 1. DC machines: ua-cam.com/play/PLPpCFgQP7QKHUOFYvZhQ6ra5XrU3dN2dD.html 2. Induction motor: ua-cam.com/play/PLPpCFgQP7QKGLh0E_GU9fHs7YL-R6941u.html
its simple. The reason behind the decreasing delta angle is the increase in the magnitude of the Ea to maintain the Ea*Sin(delta) constant at every instant. And also when the field becomes stronger then then the locked-up becomes more stronger and then load angle=delta angle reduces.
sir, I loved the way you have explained every topic.
Simplified and easy to understand phasor diagram
Wonderfully explained sir
thank you..
Easy to understand V and inverted V curves.
Thank you very much sir
Sir , as you told that as"If" increases , "Ea" also increases, so to maintain "Ef *sin (delta)" constant.....delta value has to be decreased to reduce overall "sin(delta)".
When motor was in lag section, the inductive reactance was more due to which the Ia lag Ea by larger angle and angle between Ea and Estat is also large, as the field excitation increases stator inductive reactance decrease, so theta decrease which results in decrease of the angle between Ea and Estat.... Answer with reference to "4 Equivalent circuit of synchronous generator 7:00 "
Answering the open Question -: Ea sin(del) is constant. So if Ea is increasing then (del) has to be decreasing to keep constant value of Power
he mentioned that at 17:45
Can't power also increase with flux?
Awesome video Sir! Thank you!
This was a great video sir.... cleared all my doubts !!!
Angle delta is decreasing to maintain input power to be constant
You are too good sir ji
NICE EXPLANATION BY U SIR G THANKS..........
Glad to be of help....please do consider sharing the videos also...,
Thanks you sir nice explanation 👌
Nice explanation sir
Thnq so much sir....... its very helpful
Most welcome
very good lecture sir
great
Practically..if field curr increases the field get stronger and the attraction between rotor and stator poles increases...which tends to pull the rotor to make rotor field axis as close to stator rotating field axis and the angle between them viz delta reduces.....well I think so..i might be wrong...if it is wrong please correct me...I'll be thankful..😊
No yr right..the stronger the field the stronger the locking
Sir.The topic for effect of load change or excitation change does not consider the presence of governor and voltage regulator,right?
sir I think as the motor moves from lagging to leading it means reactive power consumption by the motor decreases so to satisfy this condition delta need to decrease??
If in a synchronous motor driving mechanical load and drawing current at lagging power factor from constant voltage supply if field excitation is increased then its power factor become ???
How we can define power factor in synchronous motor ? I mean p.f is taken at the input terminal or the output terminal of the motor...
Is power only dependent on load? Why not dependent on If?
How the sign of reactive power was determined
what is its meaning , please explain
Sir exactly causes of reducing armature current is not clear what I do for clear concept???
Thanks Sir
The answer is delta is decreasing because of Ea sin(delta)=constant all time to maintain it ,since Ea is increasing .
Why Ea is always been drawn below V ?? What will happen if Ea is drawn above V ??
I will get back to this in the weekly doubt clearing session...
thank you sir
Why Ia is increasing when we are increasing excitation??
can you provide us the notes???
Want video on DC motor DC generator and induction motor
You can find the DC machine course, and all the other courses in the playlist section :
1. DC machines: ua-cam.com/play/PLPpCFgQP7QKHUOFYvZhQ6ra5XrU3dN2dD.html
2. Induction motor: ua-cam.com/play/PLPpCFgQP7QKGLh0E_GU9fHs7YL-R6941u.html
Ea is increasing . For that delta is decreasing.By this ,the speed of motor remain constant
Maintain power constant so ea increase s delta decrease s
Yes as per equations...why don't u try to think about what hapoends physically in the machines
Why is power constant? Why can't flux have an effect on it?
Could you give your videos a subtitle broo?
Why aren't you Telling first what is Ea and Vphi
They have already been explained in previous videos..I would recommend you follow the playlist