2 Block Problems | Friction | JEE Physics | Mohit Sir (IIT KGP) | IIT JEE
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- Опубліковано 6 вер 2024
- Two Block problems in Friction is discussed in detail in this video by Mohir Sir. These problems are asked in JEE Main and JEE Advanced exams.
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#Friction #2BlockSystem #PhDSeries #Eduniti #JEEMain #IITJEE #JEEAdvanced
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👀 Links - MUST WATCH!! 👀
🚀 Master PDF File for Physics PYQs and Concept Videos - bit.ly/2ZKb5Of
🔥 GOLD Mine Link - bit.ly/2VhOGFF
Gold mine or master pdf me difference kya h?
@@parthsarathidixit5648 Master PDF is just for PYQs (JEE Main) and Concept videos but GoldMine is overall channel educational content
@@mohitgoenka99 ok
Sir Three Block systems Or more than that With Graphs
@@parthsarathidixit5648 33eeee33333y
In your previous videos I just commented you to make a video on two block problems and you made it so quickly sir. Thank you so much. your efforts are highly appreciated.
You are most welcome
Sir rotation ka revision lec bana do
@@naveengupta2862 Tera kaam bhi done Hogaya bro 👌🔥
dude can u say the full form of this PHD series
@@aryanabhilesh11 PHoDu series
legends never comment in any educational platform. they just study, like, subscribe and giving millions and billions of love and thanks from their heart....❤
I have a q. in bth cases,5N also applies a downward normal force on 10kg right? we just ignore it bc its in vertical equi?
@@samairamalik3404No, gravitational force acts downwards. To understand normal force imagine you are pushing a wall, the force you give while pushing a wall is defined, we can call it F(human) signifying a human is giving a pushing force. But, the wall will not move, why? because of a multitude of factors and forces, there are too many to take into account but we know that the normal force always manages to equate the force we give on the wall. That is what normal force is, when a rigid body is immovable a normal force is said to act opposite to it. Hope i helped
@@zero0bb you did help!! thanks
You are not a legend then.
@@zero0bbLol,that's wrong.
I missed the lecture of two block friction in my coaching centre and was struggling until through his past students I came to know about him, extremely grateful for the work he is doing for JEE aspirants. Explanantion was good and now I have some confidence to go through module questions and DPP's.
I am dropper student ... I hate physics since I started preparing for jee ... And I advanced physics ke kaaran hi mera selection nhi ho paya and abhi bhi muje physics itni pasand nhi thi bas jabarjasti karta tha par abhi 1 mahine pehele aapka channel Mila and u made it very easy and I started loving physics and I am now top scorer in physics in my mocks .. thank you so much sir ❤❤❤..love u sir
ONLY ONE THING.....
This is one of the best PHYSICS CHANNEL IN INDIA❤️❤️❤️❤️
This channel is going to have millions of subscribers...
Thanx for lovely comment dear.
Note for my future reference -
First step, second step for friction ques uk
We have 2 categories
Jaha F neeche Wale par lage
Jaha F upar Wale par lage
For no. 1
F max corresponds to f limiting for upar wala
Final step me F = m sys (a max) [that chotu upar wala box can tolerate)
When F exceeds F max neeche wala aur upar wale ka FBD alg-alg banake solve Karo! Ese me koi confusion hoga hi ni! Ki neeche Wale box ki final Force ea me m sys hoga ki m box etc etc
For no. 2
F max corresponds to f limiting of lower box
Here don't u dare forget ki f static is self adjusting so acc to values in ques they can ask F min and F max both!..
F max corresponds to f limiting
F min corresponds to f kinetic (for lower box)
Baki all well!..😁👍
thanks buddy these takeaways are helpful
Ur written statement helped ❤️
good
This 2 block system is my favorite because my teacher didnt teach us this concept but some how after fighting 1hr i learned this concept by my own
Great Dear
change your teacher bro
Same here bro
Awesome sir great explanation, i found second approch of these questions and now i feel more confident on this topic. Great Content and great efforts sir.
Glad to hear that
You made this concept crystal clear to me.
One of the best Physics teacher i have ever found....👍
Glad to hear that
Again , aaj topic ko revise kiya , aaj phir bolunga iss topic pe isssse achha video kisi ne banaya nahi hai ..
Thank you so much sir ❤
most welcome dear
keep learning
My teacher made this concept so tough like it was something out of this planet 😞😭 😭😑😑😑 then i xame here and sir you made it soo simple to understand and made us feel the concept ❤❤❤❤❤❤❤ thank you sir ... # learn like never before is so true 😉
Got 95 marks in jan attempt...
Now targeting for 100 marks in April ❤❤
Thank you so much sir 🙏
excellent dear
wish you best
Just 1.25 question more (5 marks)😅
@@anjangamming6943which shift ?
@@abhinavtripathi6764 27 ||
@@anjangamming6943probably he attempted all and did one ques worng
At 17:00 when applying the eqn
We r applying for lower block
Then i guess there total mass shd be 10+5 =15 not only 10
Plz correct me if im going wrong anywhere
25-15 =10a equation is just written for lower block dear. I made FBD of both block separately.
So here mass be 10 kg only.
@@mohitgoenka99 thank u so much sir🙏👍
Am I the only one who, first likes the video then watch it🤗
(Edit-bring more videos of concept which are being repeated)
Never understood two block system in 11th now in 12th finally understanding it Thanks sirr...🙏🙏
my concept is crystal clear sir.
now can easliy find direction of friction from the miniature visualization u did. in the start
Please make a video on direction of friction and some time Norma force is MG cos theta and friction question on incline plane and force vertical on friction question
9:17 Sir, I think that the acceleration on the orange/ yellow block in the free body diagram will be on the left direction as it is pseudo acceleration.
5:50 Fmax = 75N,
fmax = fl = 25N & acc of the system = 5 m/s^2
Even if the applied force is greater than 75N, Fl = 25N.
Thank you for uploading this video sir.. was looking forward to your mechanics concepts 😁
Most welcome 😊
Sir please make a video on that ques in which 2 blocks are connected with string and we have to find that there will arise tension or not??
Yes sir please
YES SIR PLEASE
I have a q. in bth cases,5N also applies a downward normal force on 10kg right? we just ignore it bc its in vertical equi?
I just want to send a hundred thousand thank you's to this man ❤ Love you sir and Tq so much boht help hua isse ☺ Please Phd series mai aur bhi imp topics karwa dena
Sure dear. Check the playlist to find many topics
Sir es session ke note nhi hai kya by the way great explaination sir your are the gem of physics and also god love you sir❤❤
sorry dear, iske pdf notes nahi hai
keep solving & learning
& welcome to the era of true learning
#learnlikeneverbefore
I dont know whether it will come to neet But I will definitely say this is the BESTEST video about 2 block problems... on YT
just wow!!
lovely dear
Thanku sir just bcz of u i got 97 percentile in physics 🙏
Great explanation sir...-"friction a necessary evil."
Sir thank you so much for this amazing session it cleared my whole concept about friction between two blocks 💖😊
always has doubt in when it will move together and when not and the way you explained is absolutely incredible I got it all thankyou so much
sir maine abhi mock m two block system k ques m glti ki thi to m yha aagya mistake sudharne thank uh sir ab aage +4 always ...
I have a q. in bth cases,5N also applies a downward normal force on 10kg right? we just ignore it bc its in vertical equi?
After watching your videos I gain confidence and pyqs bhi easily solve ho jaate h, thanks a ton 🙏🏻
greatEST EXPLANATION of two block system ever !!
well done dear
keep solving & learning
#learnlikeneverbefore
Please make a video on how to solve HC verma concepts of physics 🙏
sir kya mast padhate ho aap !!! charan sparsh!!
Best physics teacher ❤ great sir.
keep learning dear
#learnlikeneverbefore
I have a q. in bth cases,5N also applies a downward normal force on 10kg right? we just ignore it bc its in vertical equi?
pure gold....india owes you
When force is applied on both blocks then it becomes tough, pls make a vdo on this topic
Sir please make video for 3 and 4 block problems for jee advanced 2023
Sir from the bottom of my heart I literally say thank you for clearing this concept as it scratched my head to understand.
But now I understood the approach to solve such problems only because of you 🙏🙏🙏
thank you so much sir, ❤🙏🙏🙏
Thanks a lot sir bht prblms arhi thi friction m aj clr hogya very nice explanation ❤️🙌🔥
after ALAK SIR YOU MADE THE REVOLUTION IN PHYSICS ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤
Thank you so much sir for making this concept crystal clear!!! Love from Kerala❤
You're most welcome
Sir please make this type of video for Atwood machine also
Thanku sir
Sir next nlm ki v concept video
Finally understood now I m feeling calm . thankyou sir
13:39
he 👦 he boy
all set sir love u im a dropper i scored 97 tile in physics in my mains first attempt but still had doubts now i might even score 100tile thank you very much!!!
THANK YOU SIR FOR THIS AMAZING PHD SERIES SACH ME PHD KRA DI AAPNE CONCEPT KI........
Most welcome dear
thanku so much sir ❤❤
Sir please start a series that covers important concepts through question for important chapters please sir
Sir jiiii.....kamaal karte ho sir ji aap. Thank u soooo much sir
Most welcome dear
thank you so much sir. hats of to all your efforts.
You made it crystal clear. Thank you sir 😊✨.
You are most welcome
sir only becuse of you i am feeling confident in physics even after studying for 1 year from pw i am not feeling that confident but after founding your chanel 1 month before my physics had become so much strong
Bhai apne kaise use kia sir ka channel thoda briefly describe krna? 🙏❤
Same condition bro thank God I found this channel
@@dharmakurmi1257 bro sir ka 20 days challenge follow Kiya hai Maine pyqs lagaye hai 2022 or 2023 or kuch chapters m 2021 ke bhi
So nice we need teacher like him
Static friction should be always equal to applied force then how come it’s coming F/3 in the above case , and why would we always start with assumption that it will have same acceleration .
Can u answer this
Most Valuable channel for JEE ASPIRANTS
I have a q. in bth cases,5N also applies a downward normal force on 10kg right? we just ignore it bc its in vertical equi?
In the last case The max friction on 5kg BLOCK is 25N HOW IT WILL JUST MOVE AT 15N
Btw IT WAS AN AWESOME SESSION
LOVED IT❤❤❤❤❤
Thank You So Much Sir🙏🙏🙏🙏🙏
Keep it up
same question
bro try to understand, only one block is not moving, the whole system is moving.... (the moment F becomes larger than fmax i.e 25, both blocks will then start moving at seperate acceleration)
Sir ji hame quality education dene aur visualise krke padhane ke liye thanx..🙏
You are most welcome dear
this channel is soooo underrated ,I really like the phd series they were very useful thank u so much sirr...
#learnlikeneverbefore
Sir agar question me kinetic or static dono friction alag alag hai toh phir video ke sabse akhiri wala case me kinetic lenge ha static?
16:21 acc of the system = 1 m/s^2, Fmax = 30N.
Range of applied force: 15 - 30N.
Best content of physics in whole youtube ❤️❤️❤️❤️
Sir last problem mein range 15 to 30 ki jagah par 25 to 30 hoga
Kyuki 5Kg par agar ham 16N external lagaye toh f1 use balance kar dega kyuki uska max limit 25N hai par neeche wale 10Kg pe toh friction 16 N he lagega aur uspe friction 15N he laga toh uske pass acceleration a gaya but upar wala rest pe hai.
Please let me know If I am correct or wrong
My physics teacher tought us 3 block system i understand it but they donot tought us 2 block system
Thankyou sir for your videos
Jee 2024 aspirant
Target 220
dil se thankyou sir ye concept ekdum chamakgaya hai bahut problem hoti...in dealing these type of questions... thankyou
welcome dear
keep learning
Thanks sir for this video bcz this concept become more strong only of u ....
Sir please make such videos which will explain important topics in short.... Just like projectile motion....It will be really helpful... Thank u for this one🤩😇😇
Noted
Is type mai to bhut problem definite aati thi pahle but sir ab ye mera strength ban gya
Thanku sir 🙏 ☺
Thank you sir for such a good explanation ❤️😊
Sir plz keep on bringing these type of important concept videos sir🙏🏻🙏🏻
Welcome dear
if i wll get iit i will surely tell in my interview that mr rajwant singh and mr mohit goenka are gems of physics
lovely dear
keep solving, learning and revising
#learnlikeneverbefore
atleast he has some dreams unlike u@@comradesofficialff8800
mili IIT?
@@AyushAwasthi_JEE2025 iit ism dhanbad
@@sameersamal1708 ohh congrats bro...btw rank?
Super explanation sir❤
No notes for this lecture :(
I am in love with this channel great content. Also is it possible to increase the size of that red pointer it will be helpful plz
I'm from pw batch and friction was not clear i had doubts thanks sir 🔥 now I understood everything
No offense...but RJ sir is really overrated
Sir this lecture was awesome and gajbestic ❤️❤️💗❤️💗❤️💗❤️💗
And one request 🔥🔥🔥
Please make a PhD series on power questions including on water motor's power please sir 🙏🏻🙏🏻🙏🏻🙏🏻
why should at 19.51 it move with constant accaleration when f is greater than 15 for eg if i take F as 16 N the f1 is 16 N which balances it out and the accaleration of lower block block becomes 0.1m/s which clearly shows a will not be constant
The most of all videos on two block systems I have ever watched is not so good as you taught in too depth from basic to advance. Thank you sir ❤❤❤❤
@@user-dn7yf7cs4l most welcome dear
Kemon achis
Tui abhiman na ?
@@Joyboy098
Yes , you can assume
Crystal clear concept 🚀🚀
I WILL COME BACK TO WATCH THIS VIDEO IN 2HRS !!🔥🤟
Bkk
You deserve many many many more subs sir and one day with this dedication ik you will become the greatest physics teacher on this planet
Best channel for physics on youtube👍🏻👍🏻👍🏻
At 20:14 what if I applies a force of 27N f1m(maximum static friction is 25N) therefore making fbd for the case we get 2N as the net forward driving force with acc=0.4 m/s²
But that same 25N (frictional force) would be acting on 10kg block also and the resisting force there equals 15N and hence as a result 10N is the net force.. therefore acceleration should be 1m/s²
Then sir how can the range be 15 to 30N.. correct me if I am wrong anywhere
Done ✅
Day 2/7 phy hard challenge
Sir this was very relevant and helpful.
Enjoyed a lot and thank you for everything you did to us .
Because yof you I liked this concept 😀
Crystal clear 2 block system problems 😊thnks a lot of sir❤❤
well done dear
keep learning
@@mohitgoenka99 sir Aaj Mera test tha advance ka mere se NLM ke spring k concept k ques nhi bnn rhe the mere se kchh tips bta dejia kaise krun..??
Your concepts are just lit 🔥, finally found this channel 🔥❤
Thanx dear & welcome to Eduniti
@@mohitgoenka99 Thanks a lot sir, ye topic abhi tak clear nahi hua tha, ab sab clear hai 🔥, btw sir I am neet aspirant to neet ke liye koi separate playlist hai kya? 🤔
@@surajmundhe2489 No dear but our PhD and revision series are equally relevant for you all
@@mohitgoenka99 okk sir ❤I definitely follow them, then 🔥✌
@@surajmundhe2489 bhai kaisa rha neet aapka
Sir aapka explanation to itna achcha hai ki iit phodne ka confidence agya hai thank you so much sir for such a wonderfull content
Bhaiya in the last case while drawing the FBD of 10kg block you took 10kg as an independent block and not as a system.because u write the EQ as.
25-15=10a
Here you have only taken the mass of 10kg block and multipled it with 'a' But in same EQ you have taken f2 = 15N
Were the value 15N has come from the contribution of both the blocks weight.
Why can't we take the value of f2 as 10N only.
Bhaiya Plz explain 😥🙏🙏🙏
Sir friction naso me bas gaya hai lecture dekh ke, maza aa gaya❤❤
Oh nice you cleared my doubt thank u so much ❤️
Really sir loved it a lottttt😍😍
Sir plzz iss lecture ka pdf available kar dijiye .!!🙏🙏
Sir I know where students face problems thanks sir
This is the most underrated channel and you are a star sir ..thank you very much for this beautiful class sir 🙏🙏
Currently Preparing for BITSAT-2024 sir, these videos are still extremely helpful!
Sir in this in the 1st case when force was applied on the lower block you didn't subtracted the friction due to 5kg block on the 10 kg but in the 2nd case you did can you please explain this thing , thank you
same question
Why didn't we write consider the two blocks as a system and find Fmax =(15)(Acommon)
Going on way completion of syllabus and this marvelous series I sway helping a lot ♥️♥️♥️♥️♥️♥️❤️❤️❤️❤️❤️❤️❤️💕💕💕
Excellent